31. Suppose cricket team plays 8 games. The chance of winning any particular game is 50%. Determine the probability of completing the season without ever having more losses than wins during the season:
Answer:
Explanation:no of games-8
total probability- 2^8 = 256
now ,
more wins than losses can be arranged as
4w 4L - 8c4=70
5w 3L - 8c5=56
6w 2L - 8c6=28
7w 1L - 8c7=8
8w 0L - 8c8=1
total=163
probability= 163/256
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32. Sixteen men can complete a work in twelve days. Twenty four children can complete the same work in 18 days. 12 men and 8 children started working and after eight days three more children joined them. How many days will they now take to complete the remaining work?
Answer:
Explanation:one day work of 16 men is 1/12
one day work of 24 children is 1/18
1 man's one day work is 1/(12*16 )
1 child 's one day work is 1/(24*18)
one day work of 12 men and 8 children = 12*one day work of one man + 8* one day work of one child
hence one day work of 12 men and 8 children = ((12/12*16)+(8/24*18))
on solving
one day work =(35/54*8)
work done in 8 days is 8* one day work = 8*(35/54*8) = 35/54
remaining work = 1-35/54 = 19/54
the remaining work is done by 12 men and 11 children
their one day work is 12*one men's oneday work + 11 * one child's one day work
hence 12*(1/12*16) + 11*(24*18)
one day work * number of days to complete remaining work = remaining work
((1/16)+(11/24*18)) * X = 19/54
on solving
X = 4
hence the work is done in 4 days
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33. Salaries of A, B and C are in the ratio 1 : 2 : 3. Salary of B and C together is Rs. 6000. By and what percent is salary of C more than of A ?
Answer:
Explanation:let the salaries of A,B,C be x ,2x, 3x, then 2x+3x=6000
=>x=1200
=>As salary=1200, Bs salaries=2400 , Cs salaries= 3600.
Excess of Cs salaries over As=(3600/1200)x 100 = 300%
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34. A's income is 25% more than B's income. B's income in terms of A's income is :
Answer:
Explanation:let us take b income=100
then A's income=125
25 rs exceeding the B's
25/125*100=20
B's income is 80
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35. Two circles are there one with arc area 60digree equal to 45 digree of another circle find the area of circle1:circle2 ratio
Answer:
Explanation:rea for first circle=(3.14*r^2)/6
area of second circke=(3.14*R^2)/8
therefore, ratio=3:4
since, area of arc= 360/arc degree.
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36. In an examination, A got 10% marks less than B, B got 25% marks more than C and C got 20% less than D. If A got 360 marks out of 500. The percentage of marks obtained by D was :
Answer:
Explanation:A got 369/500 * 100 = 72%
This was 90% of B. So B = 72 * 100 / 90 = 80%.
This was 125% of C. So C = 80 * 100 / 125 = 64%.
This was 80% of D. So D = 64 * 100 / 80 = 80%.
So D got 80% marks.
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37. A bag contains Rs.102 Rs. In the form of rupee, 50paise and 10paise coins in the ratio 3:4:10. What is the number of 10 paise coins?
Answer:
Explanation:Let no of 1 rupee is 3x;
no of 50 paise is 4x;
no of 50 paise is 10x;
Therefore 3x*1+4x*.50+10x*.10=106
=>6x=106
=>x=17
Therefore no of ten(10) paise in 10*17=170
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38. A person walks a distance of 18 kms at a particular speed. For the next 30 kms he increases his speed by 2 kmph. Had he walked the entire distance at 3 kmph more than his initial speed, he would have reached 4 hours earlier. Find his initial speed.
Answer:
Explanation:Let x be the initial speed , then
18/x+30/x+2=12 , we get 12 from 3*4=12
by solving we get x=1,-3
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39. if I sell two articles, one at 20% profit for rs.100 and the other at 20% loss for rs.100, what is my net profit/loss?
Answer:
Explanation:20/100=(100-CP1)/CP1
20/100=(CP2-100)/CP2
CP1 = 500/6 = 83.33
CP2 = 500/4 = 125
Total CP = 208.33
Total SP = 200
Loss = 8.33
Loss % = Loss x 100 / CP
833.33/208.33
4.0004 % loss
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40. The sides of a triangle are in the ratio 3:5:7. If the pereimeter is 60 cms,the longest side is?
Answer:
Explanation:Assume common multiple to k.
Hence sides are 3k,5k,7k.
Perimeter is 15k. Hence 15k=60
Therefore k=4
Hence longest side is 7*4=28
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