31. A 12 address lines maps to the memory of
Answer: 0.5k bytes
Explanation:Here is no explanation for this answer
Workspace
Wipro Societe Generale
32. Consider a machine with 64 MB physical memory and a 32-bit virtual address space. If the page size s 4KB, what is the approximate size of the page table?
Answer: 2 MB
Explanation:Number of pages = 232 / 4KB = 220 as we need to map every possible virtual address.
So, we need 220 entries in the page table. Physical memory being 64 MB, a physical address must be 26 bits and a page (of size 4KB) address needs 26-12 = 14 address bits. So, each page table entry must be at least 14 bits.
So, total size of page table = 220 * 14 bits ~ 2 MB
Workspace
Cisco Societe Generale
33. Size of virtual memory depends on
Answer: size of address bus
Explanation:Here is no explanation for this answer
Workspace
Cisco Global Edge Societe Generale
34. Thrashing can be avoided if
Answer: The pages, belonging to the working set of the programs, are in main memory
Explanation:Here is no explanation for this answer
Workspace
Wipro Societe Generale
35. Disk scheduling includes deciding
Answer: order in which disk access requests must be serviced
Explanation:Here is no explanation for this answer
Workspace
Global Edge Societe Generale
36. Which is not a memory management scheme?
Answer: monitors
Explanation:Here is no explanation for this answer
Workspace
Cisco Global Edge Societe Generale
37. Main function of shared memory is:
Answer: to do inter process communication
Explanation:Here is no explanation for this answer
Workspace
Cisco Societe Generale
38. How many primary partitions can be created?
Answer: 3
Explanation:Here is no explanation for this answer
Workspace
Global Edge Societe Generale
39. Reference bit is used for
Answer: Implementing NRU algorithm
Explanation:Here is no explanation for this answer
Workspace
Societe Generale Wipro
40. Which of the following is not a system file?
Answer: .ini
Explanation:Here is no explanation for this answer
Workspace
Global Edge Societe Generale