21. In a family, the father took 1/5 of the cake and he had 4 times as much as others had, then the family members are:
Answer:
Explanation:let total cake is 1 and there are x no of member.
father took 1/5.
then others took=1 - (1/5)=4/5.
If we not consider the father then there are (x-1) member and each member took (4/5)/(x-1)=4/5(x-1)
now as father had 4 times then other,we can write the equation like this,
1/5 = 4*4/5(x-1)
or,1/5=16/5(x-1)
or,x-1=16
or,x=17
.'. Total no of member=17.
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Hexaware Technologies
22. A man travels by bus for 20 hours and they by train for 05 hours . if the average speed of the bus was 20 kmph and that of the entire journey was 24 kmph. What was the average speed of the train?
Answer:
Explanation:distance travelled in bus = d1
distance travelled in train = d2
speed of train = s2
Speed of bus = 20Kmph
average speed of journey = 24kmph
Avg speed = (d1 + d2) / (T1 + T2)
=> 24 = (20*20 + 5*s2) / (20 + 5)
=> 600 = 400 + 5*s2
=> s2 = speed of train = 40 kmph
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Hexaware Technologies
23. A man walks at speed of 8 km/h, 300 mtrs length train crosses man in 30 sec from back, find speed of train?
Answer:
Explanation:If speed of train is x kmph, then
Relative speed =(x-8 ) km/hr = (x-8)*5/18 m/sec
(x-8)*(5/18)*30=300
x-8=36
x= 44 km/hr
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Hexaware Technologies
24. In a scheme, a pack of three soaps with mrp rs45 is available for Rs. 42. if it still gives a profit of 5% to the shopkeeper,then the cost price of the pack is:
Answer:
Explanation:C.P=x ,M.P=45,S.P=42
(42-x)/x=0.05
x=40
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Hexaware Technologies
25. Three years ago , the average age of A, B and C was 27 years and that of B and C, 5 years ago was 20 years. A’s present age is :
Answer:
Explanation:Sum of the present ages of A, B and C = (27 x 3 + 3 x 3) years = 90 years.
Sum of the present ages of B and C = (20 x 2 + 5 x 2) years = 50 years.
A's present age = (90 - 50) years = 40 years.
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Hexaware Technologies
26. A car moves at the speed of 80 km/hr. what is the speed of the car in metres per second?
Answer:
Explanation:Car speed=(80*5/18)m/sec=(40*5/9)m/sec =200/9 m/sec
By using numerator and Denominator formula =22*2/9 =(198+2)9 =200/9
=22*2/9 m/sec
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Hexaware Technologies
27. In an examination, 35% candidates failed in one subject and 42% failed in another subject while 15% failed in both subjects. If 2500 candidates appeared at the examination, how many passed in either subject but not in both ?
Answer:
Explanation:Both fail=15%, Only fail in sub1=20% and
Only fail in subject 2=(42-15)%=27%
So only pass in subject 1=27% and
Only pass in subject 2= 20%
So (20+27)%=47% passed in either subject but not both
Now 100% =2500
So 47%=(2500/100) * 47=1175
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Hexaware Technologies
28. The average of a non-zero number and its square is 5 times the number. The number is:
Answer:
Explanation:(x+x^2)/2=5x
x^2=9x
x=9
Workspace
Hexaware Technologies
29. In how many different ways could couples be picked from 8 men and 5 women?
Answer:
Explanation:1 men from 8 men can be chosen by 8 ways
1 women from 5 women can be chosen by 5 ways
men and women = couple
so, 8*5 =40
Workspace
Hexaware Technologies
30. Three years ago the average of A and B was 18 Years. With C joining them now, the average becomes 22 years. How old is C now?
Answer:
Explanation:let, present age of A and B and C is x and y and z.
before 3 yrs ago sum of their age was (x-3)+(y-3)=2*18
x+y=42..........(1) and
now sum of their age is x+y+z=22*3
x+y+z=66..........(2)
solving eqn (1) and (2), we get z=24
Workspace
Hexaware Technologies
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