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Consider the sequence of numbers 0, 2, 2, 4,... Where for n > 2 the nth term of the sequence is the unit digit of the sum of the previous two terms. Let sn denote the sum of the first n terms of this sequence. What is the smallest value of n for which sn >2771?
A692
B693
C694
D700
Answer: Option (Login/Signup)
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[0, 2, 2, 4, 6, 0, 6, 6, 2, 8, 0, 8, 8, 6, 4, 0, 4, 4, 8, 2], 0, 2, 2...this series repeats after every 20 terms.
Sum of these 20 terms = 80
So 2771 =34*80 + 51
Sum of 13 terms = 52
So we have to use 34 times 20 terms = 34*20 = 680
680+13 = 693
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