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In how many ways a team of 11 must be selected a team 5 men and 11 women such that the team must comprise of not more than 3 men.
A1565
B2256
C2456
D1243
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5 men and 11 women and not more than 3 men
1st way= 1men and 10 women= 5C1 * 11C10
2nd way= 2 men and 9 women=5C2 *11C9
3rd way= 3 men and 8 women= 5C3* 11C8
4th way= 0 men and 11 women=5C0* 11C11
Adding all we get= 2256.
1st way= 1men and 10 women= 5C1 * 11C10
2nd way= 2 men and 9 women=5C2 *11C9
3rd way= 3 men and 8 women= 5C3* 11C8
4th way= 0 men and 11 women=5C0* 11C11
Adding all we get= 2256.
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