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C Programming :: String

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5. #include
void main()
char a[]="12345\0";
int i=strlen(a);
printf("Value of i %d\n",++i);

Answer: Option A

Explanation :

The char array 'a' will hold the initialized string, whose length will be counted from 0 till the null character. Hence the 'I' will hold the value equal to 5, but after the pre- increment in the printf statement, value of I will be printed.

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