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Wipro Written Test Qs.(General Aptitude) :: Square Root and Cube Root - Discussion

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What is the product of the irrational roots of the equation (2x-1)(2x-3)(2x-5)(2x-7)=9?

A3/2

B4

C3

D3/4

Answer: Option (Login/Signup)

Show Explanation

Let 2x - 4 = y 
=> (y + 3) (y + 1) (y - 1) (y - 3) = 9 
=> (y^2 - 1) (y^2 - 9) = 9 
=> y^4 - 10y^2 + 9 = 9 
=> y^2 (y^2 - 10) = 0 
=> y = 0 or± √(10) 
=> 2x - 4 =± √(10) 
=> x = (1/2) [4± √(10)] 
=> product of the irrational roots 
= (1/2)^2 * [4 + √(10)] [4 - √(10)] 
= (1/4) * 6 
= 3/2.

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