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31 / 154
Suppose cricket team plays 8 games. The chance of winning any particular game is 50%. Determine the probability of completing the season without ever having more losses than wins during the season:
A70/128
B163/256
C27/122
D35/128
Answer: Option B
Explanation:no of games-8
total probability- 2^8 = 256
now ,
more wins than losses can be arranged as
4w 4L - 8c4=70
5w 3L - 8c5=56
6w 2L - 8c6=28
7w 1L - 8c7=8
8w 0L - 8c8=1
total=163
probability= 163/256
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32 / 154
Sixteen men can complete a work in twelve days. Twenty four children can complete the same work in 18 days. 12 men and 8 children started working and after eight days three more children joined them. How many days will they now take to complete the remaining work?
A2 days
B4 days
C6 days
D8 days
Answer: Option B
Explanation:one day work of 16 men is 1/12
one day work of 24 children is 1/18
1 man's one day work is 1/(12*16 )
1 child 's one day work is 1/(24*18)
one day work of 12 men and 8 children = 12*one day work of one man + 8* one day work of one child
hence one day work of 12 men and 8 children = ((12/12*16)+(8/24*18))
on solving
one day work =(35/54*8)
work done in 8 days is 8* one day work = 8*(35/54*8) = 35/54
remaining work = 1-35/54 = 19/54
the remaining work is done by 12 men and 11 children
their one day work is 12*one men's oneday work + 11 * one child's one day work
hence 12*(1/12*16) + 11*(24*18)
one day work * number of days to complete remaining work = remaining work
((1/16)+(11/24*18)) * X = 19/54
on solving
X = 4
hence the work is done in 4 days
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33 / 154
Salaries of A, B and C are in the ratio 1 : 2 : 3. Salary of B and C together is Rs. 6000. By and what percent is salary of C more than of A ?
A300
B600
C1200
D200
Answer: Option A
Explanation:let the salaries of A,B,C be x ,2x, 3x, then 2x+3x=6000
=>x=1200
=>As salary=1200, Bs salaries=2400 , Cs salaries= 3600.
Excess of Cs salaries over As=(3600/1200)x 100 = 300%
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34 / 154
A's income is 25% more than B's income. B's income in terms of A's income is :
A75%
B80%
C90%
D96%
Answer: Option B
Explanation:let us take b income=100
then A's income=125
25 rs exceeding the B's
25/125*100=20
B's income is 80
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35 / 154
Two circles are there one with arc area 60digree equal to 45 digree of another circle find the area of circle1:circle2 ratio
A2:3
B3:4
C4:3
D3:2
ENone of above
Answer: Option B
Explanation:rea for first circle=(3.14*r^2)/6
area of second circke=(3.14*R^2)/8
therefore, ratio=3:4
since, area of arc= 360/arc degree.
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36 / 154
In an examination, A got 10% marks less than B, B got 25% marks more than C and C got 20% less than D. If A got 360 marks out of 500. The percentage of marks obtained by D was :
A70%
B75%
C80%
D85%
Answer: Option C
Explanation:A got 369/500 * 100 = 72%
This was 90% of B. So B = 72 * 100 / 90 = 80%.
This was 125% of C. So C = 80 * 100 / 125 = 64%.
This was 80% of D. So D = 64 * 100 / 80 = 80%.
So D got 80% marks.
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37 / 154
A bag contains Rs.102 Rs. In the form of rupee, 50paise and 10paise coins in the ratio 3:4:10. What is the number of 10 paise coins?
A120
B170
C150
D145
Answer: Option B
Explanation:Let no of 1 rupee is 3x;
no of 50 paise is 4x;
no of 50 paise is 10x;
Therefore 3x*1+4x*.50+10x*.10=106
=>6x=106
=>x=17
Therefore no of ten(10) paise in 10*17=170
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38 / 154
A person walks a distance of 18 kms at a particular speed. For the next 30 kms he increases his speed by 2 kmph. Had he walked the entire distance at 3 kmph more than his initial speed, he would have reached 4 hours earlier. Find his initial speed.
A3 kms/hr
B2 kms/hr
C4 kms/hr
DNone of these
Answer: Option D
Explanation:Let x be the initial speed , then
18/x+30/x+2=12 , we get 12 from 3*4=12
by solving we get x=1,-3
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39 / 154
if I sell two articles, one at 20% profit for rs.100 and the other at 20% loss for rs.100, what is my net profit/loss?
A4.16 profit
B4.16 loss
C8.33 profit
D8.33 loss
Answer: Option B
Explanation:20/100=(100-CP1)/CP1
20/100=(CP2-100)/CP2
CP1 = 500/6 = 83.33
CP2 = 500/4 = 125
Total CP = 208.33
Total SP = 200
Loss = 8.33
Loss % = Loss x 100 / CP
833.33/208.33
4.0004 % loss
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40 / 154
The sides of a triangle are in the ratio 3:5:7. If the pereimeter is 60 cms,the longest side is?
A7
B30
C28
D15
Answer: Option C
Explanation:Assume common multiple to k.
Hence sides are 3k,5k,7k.
Perimeter is 15k. Hence 15k=60
Therefore k=4
Hence longest side is 7*4=28
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