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# TCS Placement Questions & Answers :: TCS

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## Total Qs: 650+

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In a particular year the month of January had exactly 4 Thursdays and 4 Sundays, on which day of the week, Jan 1 occurs?

AMonday

BTuesday

CThursday

DWednesday

| | Important Formulas | Topic: | Asked In TCS |

Explanation:

As there are 4 full weeks i.e 28 days.
So, every day occurs min 4 times.

Then remaining 3 days (as jan has 31 days) will be Monday Tuesday Wednesday. so on 31st Jan comes Wednesday.
So, 1st Jan will be MONDAY

Tags: TCS

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28
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36
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Average salary of 17 teachers is 45000.3 teachers left and the average salary dropped by 2500.What is the sum of salaries of 3 teachers who left?

A173000

B176000

C170000

D85000

| | Important Formulas | Topic: | Asked In |

Explanation:

Total Initial Salary : 17*45000 = 765000
Average Salary After removal of 3 Teachers = 45000-2500 = 42500
Total Final Salary : 14*42500 = 595000
Sum of Salaries of 3 teachers who left : 765000 - 595000 = 170000

Tags: TCS TCS NQT

NA
SHSTTON
21
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11
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32
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Find a two digit number which is doubled and after that add +2 in it. and then reverse the number we would get the actual number.
(Example : xy * 2 = pq => pq+2 = xy )

A25

B34

C52

D26

ENone of these

| | Important Formulas | Topic: | Asked In |

Explanation:

Lets assume the two digit number be 10x+y
Adding 2 after doubling the number is reverse of the number.
So 2(10x+y)+2 = 10y+x
19x -8y +2=0 ----- (i)
The above equation (i) satisfies for the value, x=2, y=5
So, the number = 10*2+5= 25

Tags: TCS TCS NQT

NA
SHSTTON
1
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13
Solv. In. Corr.
14
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Let a, b, c, d and e be distinct integers in ascending order such that(76-a)(76-b)(76-c)(76-d)(76-e) = 1127. What is a + b + c + d

A247

B274

C300

D287

| | Important Formulas | Topic: | Asked In TCS |

Explanation:

Product of 5 terms equal to 1127. As all the five terms are integers, given product should be a product of 5 numbers. Now factorize 1127.
1127 = 72 * 23 = 7 * 7 * 23
But given that all the a, b, c, d, e are distinct. And we are getting only 3 terms with 7 repeats.
Now the logic is, integers means positive and negative, 7 and - 7 possible and 1, - 1 also possible . As a,b, c, d, e are in ascending order, the factors should be in decreasing order. So (23, 7, 1, -1, -7)
Now a = 53; b = 69; c = 75; d = 77
a + b + c + d = 274.

Tags: TCS

NA
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12
Solv. Corr.
13
Solv. In. Corr.
25
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What is the average of the first 200 terms of the series
1, -2, 3, -4, 5, -6, 7......

A-1

B-1/3

C-1/2

D1/2

| | Important Formulas | Topic: | Asked In TCS |

Explanation:

1+3+5+7+9+11+13.........+199 i.e 100 terms and
sum of n odd natural numbers is n^2 i.e 100^2 =10,000

-(2+4+6+8+10+12...........+200) i.e 100 terms and
sum of n even natural numbers is n(n+1) i.e -(100(100+1))= -10,100
average of first 200 terms = (10,000+(-10,100))/200
=-100/200
=-1/2 Ans.

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NA
SHSTTON
18
Solv. Corr.
13
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31
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If 43 times of two digit numbers is 34 times of two digit reverse no . and sum of number is 14 then what is the number?

A86

B68

C95

D59

ENone of these

| | Important Formulas | Topic: | Asked In |

Explanation:

43 time the no. And 34 time the reverse no.
43(10x+ y)=34(10y+ x)
430x+ 43y= 340y+34x
430x+43y-340y-34x=0
To solve this equation become
4x-3y=0 -------------- (1)

Sum of no. And reverse no. Is 14
X+ Y= 14 ------------- (2)
To solve both equation value of x and y
X= 6 and y= 8
So, number will be 68

Tags: TCS TCS NQT

NA
SHSTTON
161
Solv. Corr.
202
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363
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Structure can be used

ATo hold different datatypes

BHave pointers to structure

CTo assign to one another

DAll the above

| | Topic: | Asked In |

Explanation:

Here is no explanation for this answer

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A can do a piece of work in 14 days which B can do in 21 days. They begin together but 3 days before the completion of the work, A leaves off. The total number of days to complete the work is:

A6 3/5

B8 1/2

C10 1/5

D13 1/2

| | Important Formulas | Topic: | Asked In 1 |

Explanation:

A's 1 day work = $$\frac{1}{14}$$
B' 1 day work = $$\frac{1}{21}$$

A left 3 day before the completion of work.
B's 3 days' work = $$\frac{1}{21} \times 3 = \frac{1}{7}$$
Remaining work = $$1 \times \frac{1}{7} = \frac{6}{7}$$

(A + B)'s 1 day's work = $$\left(\frac{1}{14} + \frac{1}{21}\right) = \frac{5}{42}$$

Now, $$\frac{5}{42}$$ work is done by A and B = 1 day.
or
whole work done by A&B = $$\frac{42}{5}$$
$$\frac{6}{7}$$ part of work done by A and B = $$\frac{42}{5} \times \frac{6}{7} = \frac{36}{5}$$ days.

Hence, total time taken = (3+36/5)days = $$10\frac{1}{5}$$ days.

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A can do a work in 10 days and B can do the same work in 15 days. So how many days they will take to finish the same work ?

A5 days

B7 days

C9 days

D6 days

| | Important Formulas | Topic: | Asked In 5 |

Explanation:

First find the 1 day work of both (A & B)
A 1 day's work = 1/10
and
B 1 day's work = 1/15

So (A + B) 1 day's work = (1/10+1/15)
= (3/30+2/30) = 5/30 = 1/6

So Both (A & B) together can finish work in 6 days

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Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg will be:

ARs. 175.50

BRs. 180

CRs. 170

DRs. 169.50

| | Important Formulas | Topic: | Asked In 2 |