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TCS Placement Questions & Answers :: TCS

270.6K

Tot. Mock Test: 40


Total Qs: 649+

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In a particular year the month of January had exactly 4 Thursdays and 4 Sundays, on which day of the week, Jan 1 occurs?


AMonday

BTuesday

CThursday

DWednesday

Answer: Option A

Explanation:

As there are 4 full weeks i.e 28 days.
So, every day occurs min 4 times.

Then remaining 3 days (as jan has 31 days) will be Monday Tuesday Wednesday. so on 31st Jan comes Wednesday.
So, 1st Jan will be MONDAY

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SHSTTON
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Choose the correct option.

Average salary of 17 teachers is 45000.3 teachers left and the average salary dropped by 2500.What is the sum of salaries of 3 teachers who left?


A173000

B176000

C170000

D85000

Answer: Option C

Explanation:

Total Initial Salary : 17*45000 = 765000
Average Salary After removal of 3 Teachers = 45000-2500 = 42500
Total Final Salary : 14*42500 = 595000
Sum of Salaries of 3 teachers who left : 765000 - 595000 = 170000

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Tags: TCS TCS NQT

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Find a two digit number which is doubled and after that add +2 in it. and then reverse the number we would get the actual number.
(Example : xy * 2 = pq => pq+2 = xy )


A25

B34

C52

D26

ENone of these

Answer: Option A

Explanation:

Lets assume the two digit number be 10x+y
Adding 2 after doubling the number is reverse of the number.
So 2(10x+y)+2 = 10y+x
19x -8y +2=0 ----- (i)
The above equation (i) satisfies for the value, x=2, y=5
So, the number = 10*2+5= 25

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Let a, b, c, d and e be distinct integers in ascending order such that(76-a)(76-b)(76-c)(76-d)(76-e) = 1127. What is a + b + c + d


A247

B274

C300

D287

Answer: Option B

Explanation:

Product of 5 terms equal to 1127. As all the five terms are integers, given product should be a product of 5 numbers. Now factorize 1127.
1127 = 72 * 23 = 7 * 7 * 23
But given that all the a, b, c, d, e are distinct. And we are getting only 3 terms with 7 repeats.
Now the logic is, integers means positive and negative, 7 and - 7 possible and 1, - 1 also possible . As a,b, c, d, e are in ascending order, the factors should be in decreasing order. So (23, 7, 1, -1, -7)
Now a = 53; b = 69; c = 75; d = 77
a + b + c + d = 274.

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Choose the correct option.

What is the average of the first 200 terms of the series
1, -2, 3, -4, 5, -6, 7......


A-1

B-1/3

C-1/2

D1/2

Answer: Option C

Explanation:

1+3+5+7+9+11+13.........+199 i.e 100 terms and
sum of n odd natural numbers is n^2 i.e 100^2 =10,000

-(2+4+6+8+10+12...........+200) i.e 100 terms and
sum of n even natural numbers is n(n+1) i.e -(100(100+1))= -10,100
average of first 200 terms = (10,000+(-10,100))/200
=-100/200
=-1/2 Ans.

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If 43 times of two digit numbers is 34 times of two digit reverse no . and sum of number is 14 then what is the number?


A86

B68

C95

D59

ENone of these

Answer: Option B

Explanation:

43 time the no. And 34 time the reverse no.
43(10x+ y)=34(10y+ x)
430x+ 43y= 340y+34x
430x+43y-340y-34x=0
To solve this equation become
4x-3y=0 -------------- (1)

Sum of no. And reverse no. Is 14
X+ Y= 14 ------------- (2)
To solve both equation value of x and y
X= 6 and y= 8
So, number will be 68

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Choose the correct option.

Structure can be used


ATo hold different datatypes

BHave pointers to structure

CTo assign to one another

DAll the above

Answer: Option D

Explanation:

Here is no explanation for this answer

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Choose the correct option.

A can do a piece of work in 14 days which B can do in 21 days. They begin together but 3 days before the completion of the work, A leaves off. The total number of days to complete the work is:


A6 3/5

B8 1/2

C10 1/5

D13 1/2

Answer: Option C

Explanation:

A's 1 day work = \(\frac{1}{14}\)
B' 1 day work = \(\frac{1}{21}\)

A left 3 day before the completion of work.
B's 3 days' work = \(\frac{1}{21} \times 3 = \frac{1}{7}\)
Remaining work = \(1 \times \frac{1}{7} = \frac{6}{7}\)

(A + B)'s 1 day's work = \(\left(\frac{1}{14} + \frac{1}{21}\right) = \frac{5}{42}\)

Now, \(\frac{5}{42}\) work is done by A and B = 1 day.
or
whole work done by A&B = \(\frac{42}{5}\)
\(\frac{6}{7}\) part of work done by A and B = \(\frac{42}{5} \times \frac{6}{7} = \frac{36}{5}\) days.

Hence, total time taken = (3+36/5)days = \(10\frac{1}{5}\) days.

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Choose the correct option.

A can do a work in 10 days and B can do the same work in 15 days. So how many days they will take to finish the same work ?


A5 days

B7 days

C9 days

D6 days

Answer: Option D

Explanation:

First find the 1 day work of both (A & B)
A 1 day's work = 1/10
and
B 1 day's work = 1/15

So (A + B) 1 day's work = (1/10+1/15)
= (3/30+2/30) = 5/30 = 1/6

So Both (A & B) together can finish work in 6 days

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Here is the list of questions asked in TCS Aptitude Test Question with Answers TCS Mock Test page 65. Practice TCS Written Test Papers with Solutions and take Q4Interview TCS Online Test Questions to crack TCS written round test. Overall the level of the TCS Online Assessment Test is moderate. Only those candidates who clear the written exam will qualify for the next round, so practic all the questions here and take all the free tests before going for final selection process of TCS