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TCS Placement Questions & Answers :: TCS

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Tot. Mock Test: 40


Total Qs: 649+

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If x2 < 1/100 and x< 0, What is the tightest range in which x can lie?


A-1/10 < x < 0

B-1 < x < 0

C-1/10 < x < 1/10

D-1/10

Answer: Option A

Explanation:

Given x2 < 1/100
so, x < 1/10 or x > - 1/10 first statement
also, as per question x < 0 second statement
so, intersection of both statement will be
- 1/10 < x < 0

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How many 6 digit telephone numbers can be formed if each number starts with 35 and no digit appears more than once?


A720

B360

C1420

D1680

Answer: Option D

Explanation:

6 digits telephone number can be formed by 10 digits (0,1,2...9)
As Given, each number start with 35.
So we have 8 digits remaining and 4 place.
So, 4 places can be formed in 8*7*6*5=1680.

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The least number which when divided by 48, 60, 72, 108 and 140 leaves 38, 50, 62, 98 and 130 as remainders respectively, is:


A4562

B15110

C2135

D7589

Answer: Option B

Explanation:

(48 - 38 ) = ( 60 - 50 ) = ( 72 - 62 ) = ( 108 - 98 ) = ( 140 - 130 ) = 10 in every case

Leat number will be LCM of ( 48, 60, 72, 108, 140 ) - 10

LCM = 15120

So, required number = 15120 - 10 = 15110

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If a person has to work 8 continuous day & he gets a rest on the 9th day. If a person starts on Monday. What is the day of 12th rest day?


AMonday

BWednesday

CSunday

DTuesday

Answer: Option B

Explanation:

1st rest day on 9th day ,
so 12th rest day on 108th day... 1wk=7days.
108/7 reminder=3. 3rd day is rest day.
work started on monday so 3rd day is wed.

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This question consists of a question and two statements (I and II). Read and Decide whether the data provided in the statements are sufficient to answer the question or not and choose the correct option.

Question: A turtle is crossing a field. What is the total distance (in meters) passed by turtle?
Statements:
(X) The average speed of the turtle is 2 meters per minute
(Y) Had the turtle walked 1 meter per minute faster than his average speed it would have finished 40 minutes earlier


AStatement X alone is enough to get the answer

BBoth statements X and Y are needed to get the answer

CStatement Y alone is enough to get the answer

DData inadequate

Answer: Option B

Explanation:

Here is no explanation for this answer

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Aniket and kumari are a married couple. They have two kids, one of them is a girl. Assume safely that the probability of each gender is 1/2.What is the probability that the other kid is also a girl?


A1/2

B1/3

C2/3

DNone of these

Answer: Option B

Explanation:

Here is no explanation for this answer

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26
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A girl rode her bicycle from home to school, a distance of 15 miles, at an average speed of 15 miles per hour. She returned home from school by walking at an average speed of 5 miles per hour. What was her average speed for the round trip if she took the same route in both directions?


A8.5 miles/hr.

B7 miles/hr.

C7.5 miles/hr.

DNone of these

Answer: Option C

Explanation:

Avg speed=(total disance)/(total time)
Total distance= 15+15 = 30 miles.
Total time= 1+3=4 hrs.
So average Spedd = 30/4 = 7.5 miles/hr.

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If log 0.318=0.3364 and log 0.317=0.33320 then log 0.319 =?


A0.33365

B0.3368

C0.3396

D0.3369

Answer: Option C

Explanation:

log 0.319=log0.318+(log0.318-log0.317) = 0.3396

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Five college students met at a party and exchanged gossips. Uma said, “Only one of us is lying”. David said, “Exactly two of us are lying”. Thara said, “Exactly 3 of us are lying”. Querishi said, “Exactly 4 of us are lying”. Chitra said “All of us are lying”. Which one was telling the truth?


ADavid

BQuerishi

CChitra

DThara

Answer: Option B

Explanation:

Here is no explanation for this answer

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A clock showed 5 min past 3'0 clock on Sunday evening when the correct time was 3'0 clock it looses uniformly and was observed to be 10 min slow on the subsequent Tuesday at 9pm . when did the clock show the correct time


A10 AM Monday

B10 PM Monday

C9 PM Monday

D9 AM Monday

Answer: Option D

Explanation:

Clock showed 5 min past 3'0 clock on Sunday evening when the correct time was 3'0 clock.
It looses uniformly and was observed to be 10 min slow on the subsequent Tuesday at 9pm .

In 54 hrs , it lost 15 mins.

so 5 mins are lost in 5*54/15 = 18 hrs

so watch showed correct time at 1500+1800-2400= 0900 hrs on Monday i.e 9AM Monday

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