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Problems on Ages Questions

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A father's age was 5 times his son's age 5 years ago and will be 3 times son's age after 2 years, the ratio of their present ages is equal to:


A3:7

B5:11

C10:3

D10:7

Answer: Option C

Explanation:

Lets assume father and son as x and y respectively.
So, five years ago.
=> x-5 = 5(9y-5) ------ (1)
After 2 years.
=> x+2 = 3(y+2) ------ (2)
By solving eq(1) & (2)
x/y=10/3.

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The average age of a woman and her daughter is 16 years. The ratio of their ages in 7 : 1 respectively. What is the woman's age?


A24 years

B28 years

C32 years

D26 years

ENone of these

Answer: Option B

Explanation:

The average age of a woman and her daughter is 16 years.
Sum of ages = 16*2=32 years.

The ratio of their ages in 7 : 1 say 7x and x.
Then 8x = 32
=> x=4
Hence, the age of woman = 7*4 = 28 years.

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Three years ago, the average age of A, B and C was 27 years and that of B and C, 5 years ago was 20 years. A's present age is :


A30 years.

B35 years.

C40 years.

D48 years.

Answer: Option C

Explanation:

Lets assume present ages of A, B and C as x,y, and z respectively.
Three years ago their ages were x-3,y-3,z-3.
Given:
=> (x-3+y-3+z-3)/3 = 27.
=> x+y+z=90.
and 5 years ago:
Then (x-5+y-5)/2=20.
=> y+z=50.
=> x=90-(y+z).
=> x=90-50 = 40 years.

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Total of the ages of A, B ahd C at present is 90 years. Ten years ago, the ratio of their ages was 1: 2: 3. What is the age of B at present


A23 years

B20 years

C30 years.

D33 years.

Answer: Option C

Explanation:

Let their ages 10 years ago is x, 2x and 3x years.
(x + 10) + (2x + 10) + (3x + 10) = 90 hence x= 10
B's present age = (2x + 10) =30 years.

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The sum of ages of suresh and his father is 78 years.6 years hence father's age will be twice of suresh's age. Find present age of father.


A54 years

B45 years

C55 years

DNone of these

Answer: Option A

Explanation:

Lets assume suresh age = x years.
So, father age = (78-x) years.
Condition : 6 years hence
2* (x + 6) = (78 - x + 6)
=> 2x + 12 = 84 - x
=> 3x = 72
x = 24 years.
Father age = 78 - 24 = 54 years.

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A father is three times as old as his son. After fifteen years the father will be twice as old as his son's age at that time. Hence
the father's present age is


A48 years.

B44 years.

C45 years.

DNone of these

Answer: Option C

Explanation:

Lets assume son's current age = x years
So, father's current age = 3x
After 15 years (condition)
2(x+15)=3x+15
Son's age = 15 years, and father's age = 45 years.

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The sum of the ages of A,B and C was 52 three years ago.Four years ago B,who is a year younger than C,was 1 1/2 times as old as A.The sum of the ages of B and C two years hence,will be


A50 years

B45 years

C49 years

DNone of these

Answer: Option C

Explanation:

Present sum of ages of A,B & C = A+B+C = 52+9=61 ---(i)
Given B is a year younger than C, so B+1 = C ---(ii)
Also B-4=(A-4)*3/2
=> 2B - 8 = 3A-12
=> 2B -3A= -4 ---(iii)
Substituting C=B+1 from (ii) in (i)
A+2B=60 ---(iv)
On solving (iii) & (iv)
A=16, B=22 so C=23
So sum of the ages of B & C two year hence= (B+2)+(C+2)=24+25 = 49 Years.

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A certain company retirement plan has a rule of 70 provision that allows an employee to retire when the employee's age plus years of employment with the company total at least 70. In what year could a female employee hired in 1986 on her 32nd birthday first be eligible to retire under this provision?


A19 years.

B18 years.

C21 years

DNone of these

Answer: Option A

Explanation:

Lets assume it has taken x years to the female employee to reach the rule of 70.
So her age should be (32 + x).Also she gains x years of experience.
=> (32 + x) + x = 70
=> x = 19 years.

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In 4 years, Raj's father age twice as raj, Two years ago, Raj's mother's age twice as raj. If Raj is 32yrs old in eight yrs from now, what is the age of Raj's mother and father?


A55

B65

C44

D46

Answer: Option D

Explanation:

Raj present age = 32 - 8 = 24.
After 4 years Raj's age is 28. and Raj's fathers age is 28 x 2 = 56, and his present age is 52.
Two years ago, Raj's age is 22. and his mother's age is 22 x 2 = 44. His mother's present age = 46

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When Usha was thrice as old as Nisha, her sister Asha was 25, When Nisha was half as old as Asha, then sister Usha was 34. their ages add to 100. How old is Usha?


A37

B44

C45

D40

Answer: Option D

Explanation:

Let the age of Usha is 3x then Nisha is x and Asha is 25
Also Usha 34, Nisha y, and Asha 2y.
We know that 3x - 34 = x - 2y = 25 - 2y
Solving above three equations we get x = 9, y = 16
Their ages are 34, 16, 32. whose sum = 82. So after 18 years their ages will be equal to 100. So Usha age is 34 + 6 = 40

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