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11. A certain sum amounts to Rs. 7350 in 2 years and to Rs. 8575 in 3 years. Find the sum and rate percent.
Answer: Option C
Explanation:S.I. on Rs. 7350 for 1 year = Rs. (8575-7350) = Rs. 1225.
Therefore, Rate = (100*1225 / 7350*1) % = 16 2/3 %.
Let the sum be Rs. X. then, x[1 + (50/3*100)]^2 = 7350.
=> x * 7/6 * 7/6 = 7350.
=> x = [7350 * 36/49] = 5400.
So, Sum = Rs. 5400.
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12. In how much time would the simple interest on a certain sum be 0.125 times the principal at 10% per annum?
Answer: Option B
Explanation:Lets assume sum = x.
Then, S.I. = 0.125x = 1/8 *x, GivenR = 10%
Formula: Time = (100 * S.I)/(P * R)
Time = (100 *1/8* x) / (x * 10) = (100 *x)/(x*8*10)
= 5/4 = 1 1/4 years.
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Tags: Infosys
13. There is 60% increase in an amount in 6 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate?
Answer: Option C
Explanation:Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.
R = (100 x 60)/(100x6) = 10% p.a.
Now, P = Rs. 12000
T = 3 years and R = 10% p.a.
So, C.I. = Rs.[12000 * [(1 + 10/100)^3- 1]]
= Rs. 12000 * 331/1000 = Rs. 3972
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Tags: Infosys
14. A certain sum of money amounts to Rs. 1008 in 2 years and to Rs.1164 in 3 1/2 years. Find the sum and rate of interests.
Answer: Option C
Explanation:S.I. for 1 and 1/2 years = Rs.(1164-1008) = Rs.156.
SI for 2 years = Rs.(156*(2/3)*2)=Rs.208.
Principal = Rs. (1008 - 208) = Rs. 800.
Now, P = 800, T = 2 and S.l. = 208.
Rate =(100 * 208)/(800 * 2)% = 13%
Workspace
Tags: Tech Mahindra
15. What sum of money will accumulate to Rs.5300 at 8% rate of interest in 9 months?
Answer: Option A
Explanation:Let assume money = p.
so,106p/100=5300
p=5000
Workspace
Tags: IBM
16. A car that has an original value of $52,500 depricates $10000 in the first year and there original cost per year. What is its value after 8 years?
Answer: Option D
Explanation:Given 1st year depreciation amount = $10000
next 7 year's depreciation amount = 7 * 8% original cost price
= 7*8/100 * 52500 = $29400
Total depreciation amount = ($10000 + $29400) = $39400
Value after 8 years = $(52500-39400) = $13100
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Tags: IBM
17. simple interest on an amount at 4% per annum for 13 months is more than the simple interest on the same sum for 8 months at 6% per annum by Rs. 40. what is the principle amount
Answer: Option B
Explanation:Lets assume principle ammount = Rs. x
[(P*4*13/100*12) - (p*6*8/100*12)] = 40
=> p=12000
Workspace
Tags: Cognizant
18. Given that the interest is only earned on principal, if an investment of Rs.1000.00 amount to Rs.1440.00 in two years, then what is the rate of interest earned?
Answer: Option A
Explanation:Solution: I= (P*R*T)/100 INTEREST( I)= 1440-1000= 440
440=(1000*R*2)/100
R=22%
Workspace
Tags: Cognizant
19.
Answer: Option D
Explanation:Workspace
Tags: Capgemini
20. As per scheme a car loan of Rs. 4 lakh at 12.5 p.c.p. rate of simple interest can be borrowed on a repayment term of lump sum amount at the end of 3 years.
As per scheme (b), the amount can be repaid at the end of 2 years, but compound interest (compounded annually) would be charged at the same rate. What would be the difference in amount of interest between the two schemes?
Answer: Option B
Explanation:Scheme ,
p=400000
r=12.5%
n=3
SI = 400000*3*12.5/100
SI = 150000
Total Sum = 550000
Scheme (b)
Amount = 400000[1 + 12.5/100]^2
=> 400000*[9/8 * 9/8]
Amount = 506250
Difference is 550000 - 506250 = Rs. 43750
Workspace
Tags: Syntel Inc.