Take a note while surfing.
Give your Note a Colorful Tag.
Stay on same information and in Sync wherever you are.
Organize your information,It may take Shape.
Differ your Content by Color.
Easy to pull up your content from anywhere anytime.
Don't Let information to miss,Because it take shape
Simple an Easy Way to take a note.
Get the same in next visit.
Please wait...
11. Bucket A has thrice the capacity as bucket B. It takes 80 turns for bucket A to fill the empty drum. How many turns it will take for both the buckets A and B, having each turn together to fill the empty drum?
Answer: Option B
Explanation:Lets Assume capacity of bucket A = x
so capacity of bucket B = x/3
Given that it takes 80 turns for bucket A to fill the empty drum.
So capacity of the drum = 80x
Number of turns required if both A and B having each turn together=80x/(x+x/3)=240x/(3x+x)=60
Workspace
Tags: No Tags on this question yet!
12. A large tanker can be filled by two pipes A and B in 60 minutes and 40 minutes respectively. How many minutes will it take to fill the tanker from empty state if B is used for half the time and A and B fill it together for the other half?
Answer: Option B
Explanation:Tank part filled by pipe A in 1 minute = 1/60
Tank part filled by pipe B in 1 minute =1/40
So Tank Part filled by both pipes A and B in 1 minute = (1/60+1/40)=5/120=1/24
Lets Assume tanker get filled in x minutes.
Then, to fill the tanker from empty state, B is used for x/2 minutes
and A and B together is used for the rest x/2 minutes.
(x/2*1/40)+(x/2*1/24)=1
=> x/2(1/40+1/24)=1
=> x/2*8/120=1
=> x/30=1
=> x = 30 minutes
Workspace
Tags: No Tags on this question yet!
13. Pipe A can fill an empty tank in 12 hours. Pipe B can empty it in 36 hours. If at 8 a.m. the pipe A is opened on an empty water tank and pipe B is opended at 9 a.m., 10 a.m. 11 a.m. and 12 p.m. for 15 minutes each, by what time in the evening will the tank be filled?
Answer: Option C
Explanation:Tank part filled by Pipe A in 1 hour = 1/12
similarly Tank part emptied by pipe B in 1 hour = 1/36
or Tank part emptied by pipe B in 15 min = 15 * 1/60*36 = 1/144
From 8 a.m. to 9 a.m. tank part filled = 1/12 => 11/12 of the tank is empty
From 9 a.m. to 10 a.m. tank part will be filled = (1/12 + 1/144) = 11/144 => 1 hour 11/144 of the tank gets filled
11/12 part of the tank would take = 11/12 x 144/11 = 12 hours
Total time required is 1 + 12 = 13 hours
=> Tank would be full @ 8 a.m. + 13 = 9 p.m.
Workspace
Tags: No Tags on this question yet!
14. Three taps A,B and C can fill a tank in 12,15 and 20 hours respectively. If A is open all the time and B ,C are open for one hour each alternatively, the tank will be full in:
Answer: Option C
Explanation:Tank filled by (A+B) in 1 hour = (1/12+1/15) = 9/60 = 3/20
Tank filled by (A+C) in 1 hour = (1/12+1/20) = 8/60 = 2/15
So tank filled in 2 hours = (3/20 + 2/15) = 17/60
Tank part filled in 6 hrs = 3*17/60 = 17/20
Remaining part = (1-17/20) = 3/20
Now, it is the turn of A and B (3/20) part is filled by A and B in 1 hour.
So Total time taken to fill the tank =(6+1)hrs= 7 hrs
Workspace
Tags: No Tags on this question yet!
15. There are 2 taps A and B to fill up a water tank. The tank can be filled in 40 minutes if both taps are on. The same tank can be filled in 60 minutes if tap A alone is on. How much time will tap B alone take to fill up the same tank ?
Answer: Option D
Explanation:Tank part filled by (A+B) in 1 min = 1/40
Tank part filled by A alone in 1 min = 1/60
=> Tank part filled by B alone in 1 min = (1/40 -1/60) = 1/120
Therefore Tap B can fill the tank in 120 minutes
Workspace
Tags: No Tags on this question yet!
16. 8 taps through which water flows at the same rate can fill a tank in 30 minutes. If two taps go out of order, how long will the remaining taps take to the fill the tank?
Answer: Option C
Explanation:Given Time need by 8 taps to fill tank = 30 minutes
So let's assume time need by 6 taps to fill tank = M minutes
M = (8 x 30)/6 = 40 minutes
Workspace
Tags: No Tags on this question yet!
17. A water tank is two-fifth full.Pipe A can fill a tank in 10 minutes and pipe B can empty it in 6 minutes.If both the pipes are open,how long will it take to empty or fill the tank completely?
Answer: Option A
Explanation:Pipe B is faster than pipe A
=> the tank will be emptied.
part to be emptied = 2/5
Tank part emptied by (A+B) in 1 minute= (1/6-1/10)=1/15
1/15:2/5::1:x =>2/5 = 1/15x=> x = 6min
so, the tank will be emptied in 6 min
Workspace
Tags: No Tags on this question yet!
18. Two pipes can fill a tank in 20 and 24 minutes respectively and a waste pipe can empty 3 gallons per minute. All the three pipes working together can fill the tank in 15 minutes. The capacity of the tank is:
Answer: Option C
Explanation:Tank part filled by pipe A in 1 min = 1/20
similarly by pipe B in 1 min = 1/24
So Work done by waste pipe in 1 min = 1/15 - (1/20+1/24) = -1/40(Here negative value means emptying)
Volume of 1/40 part = 3 gallons
Volume of whole = 3*40 = 120 gallons.
Workspace
Tags: No Tags on this question yet!
19. Two pipes P and Q can fill a cistern in 12 and 15 minutes respectively. Both are opened together, but at the end of 3 minutes the first is turned off. How much more time will it take to fill the tabk by pipe B?
Answer: Option D
Explanation:Tank part filled by pipe A in 1 minute = 1/12
similarly by pipe B = 1/15
Tank part filled by both pipe in 1 min = (1/12+1/15)
so tank part filled by both pipe in 3 min = 3*(1/12+1/15) = 9/20
So remaining part to be filled by B = (1-9/20) = 11/20
1/15 part of tank filed by B = 1 min
so 11/20 part of tank filled by B = 15 * 11/20 = 8 1/4 min.
Workspace
Tags: No Tags on this question yet!
20. A cistern has a leak which would empty the cistern in 20 minutes. A tap is turned on which admits 4 liters a minute into the cistern, and it is emptied in 24 minutes. How many liters does the cistern hold?
Answer: Option A
Explanation:Work done by the inlet in 1 min = (1/20-1/24) = 1/120
=> volume fo 1/120 part = 4 liters.
=> volume of whole = 120*4 = 480 liter.
Workspace
Tags: No Tags on this question yet!