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# C Programming :: Basic Concepts

NA
SHSTTON
2
Solv. Corr.
11
Solv. In. Corr.
13
Attempted
0 M:0 S
Avg. Time

31 / 90

What is the output of the following program ?
#include<stdio.h>
void main()
{
char c=' ',x,convert(z);
getc(c);
if((c>='a') && (c<='z'))
x=convert(c);
printf("%c",x);
}
convert(z)
{
return z-32;
}

AConvert to Upper Case

BConver to Lower Case

CNo Ouptput No error

DCompiler error

Explanation:

Declaration of convert and format of getc() are wrong.

Workspace

NA
SHSTTON
9
Solv. Corr.
1
Solv. In. Corr.
10
Attempted
0 M:0 S
Avg. Time

32 / 90

What is the output of the following program ?
#include<stdio.h>
int swap(int *a,int *b)
{
*a=*a+*b;*b=*a-*b;*a=*a-*b;
}
void main()
{
int x=10,y=20;
swap(&x,&y);
printf("x= %d y = %d\n",x,y);
}

Ax= 20 y = 10

Bx= 10 y = 20

CCompilation Error

DNone of these

Explanation:

This is one way of swapping two values.

Workspace

NA
SHSTTON
7
Solv. Corr.
2
Solv. In. Corr.
9
Attempted
0 M:0 S
Avg. Time

33 / 90

What is the output of the following program ?
#include<stdio.h>
void main()
{
printf("sizeof (void *) = %d \n", sizeof( void *));
printf("sizeof (int *)   = %d \n", sizeof(int *));
printf("sizeof (double *) = %d \n", sizeof(double *));
printf("sizeof(struct unknown *) = %d \n", sizeof(struct unknown *));
}

Asizeof (void *) = 4 sizeof (int *) = 4 sizeof (double *) = 4 sizeof(struct unknown *) = 4

Bsizeof (void *) = 2 sizeof (int *) = 2 sizeof (double *) = 4 sizeof(struct unknown *) = 4

Csizeof (void *) = 4 sizeof (int *) = 4 sizeof (double *) = 2 sizeof(struct unknown *) = 4

DCompilation Error

Explanation:

The pointer to any type is of same size.

Workspace

NA
SHSTTON
2
Solv. Corr.
7
Solv. In. Corr.
9
Attempted
0 M:0 S
Avg. Time

34 / 90

Choose the correct option.

To print out a and b given below, which printf() statement will be used ?

float a = 3.14;
double b = 3.14;

Aprintf("%f%f', a, b);

Bprintf("%Lf%f', a, b);

Cprintf ("%Lf%Lf', a, b);

Dprintf("%f%Lf', a, b);

Explanation:

Here, in every option we see that there is a missing terminating " character, which will result to an error.

Hence, to print the values of a and b, the code should be-

printf("%f%f",a,b);

This will give the output as 3.1400003.140000.

Workspace

NA
SHSTTON
3
Solv. Corr.
6
Solv. In. Corr.
9
Attempted
0 M:0 S
Avg. Time

35 / 90

Choose the correct option.

To scan float a and double b, which scanf() statement will be used?

Ascanf("%f%f", &a, &b);

Bscanf("%f%Lf', &a, &b);

Cscanf ("%Lf%Lf', &a, &b);

Dscan{ ("%f%lf', &a, &b);

Explanation:

We want to scan float a and double b.

Option A is incorrect because it will scan both the variables as float.

Option B is incorrect as here variable b will be scanned as long-double type, but we want b to be double type.

Option C is incorrect because here both the variables will be scanned as long-double type.

Option D is incorrect because it should be 'scanf' and not 'scan{', which will create an error. If we correct this then variable a will be scanned as float type and variable b will be scanned as double type.

Workspace

NA
SHSTTON
6
Solv. Corr.
4
Solv. In. Corr.
10
Attempted
0 M:0 S
Avg. Time

36 / 90

Choose the correct option.

The Below statement in 'C' prints.

printf("%c", 200)

Aprints 200

Bprints the ascii equivalent of 200

Cprints garbage

Dnone of these

Explanation:

Here, 200 is an integer value, and we are printing a character. Hence, the output will be the character corresponding to the given integer value 200.

For ASCII code 200, the printable character will be "â•š ".

Hence, the correct option is B.

Workspace

NA
SHSTTON
95
Solv. Corr.
31
Solv. In. Corr.
126
Attempted
0 M:23 S
Avg. Time

37 / 90

Choose the correct option.

C language is available for which of the following Operating System?

BWindows

CUnix

DAll of these

Explanation:

Here is no explanation for this answer

Workspace

NA
SHSTTON
31
Solv. Corr.
50
Solv. In. Corr.
81
Attempted
0 M:0 S
Avg. Time

38 / 90

Choose the correct option.

How will you print \n on the screen ?

Aprintf(“\n”);

Becho \\n;

Cprintf(“\n”);

Dprintf(\\n);

Explanation:

The statement printf("\\n"); prints '\n' on the screen.

Workspace

NA
SHSTTON
7
Solv. Corr.
6
Solv. In. Corr.
13
Attempted
0 M:0 S
Avg. Time

39 / 90

Choose the correct option.

Assignment operator targets to _____

Ar-value

Bl-value

Cboth

DNone

Explanation:

Assignment operators are used to assign the the values present on the right-hand side to whatever is present on the left-hand side of the operator. The left-hand side can be a variable or a pointer, and the right-hand side can be a variable, a constant, an expression or a function call.

For example-

a=5;    //assigns '5' to 'a'.

On the other hand, 5=a;    //error.

Very often in C, we use the terminology of l-value in error messages. It basically refers to the operands present on the left-hand side of the assignment operator. It can be a variable or a pointer, but should not be a constant.

Hence, from the above theory, we can conclude for sure that assignment operator targets to L-value.

Workspace

NA
SHSTTON
0
Solv. Corr.
2
Solv. In. Corr.
2
Attempted
0 M:0 S
Avg. Time

40 / 90

int zap (int n)
{
if (n<=1)then zap=1;
else zap=zap(n-3)+zap(n-1);
}
then the call zap(6) gives the values of zap

A8

B6

C9

D12

E15

Explanation:

9

Workspace

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