Let the petrol 1 unit initial price be rs 100.
25% increase on rs 100= rs 125
since expenditure to remain constant 125*x= 100*1
x=.80 unit
So, consumer reduces =.20 unit i.e 20%
Workspace
NA
SHSTTON
50
Solv. Corr.
135
Solv. In. Corr.
185
Attempted
0 M:10 S
Avg. Time
12 / 99
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On the first test of the semester, kiran scored a 60. On the last test of the semester, kiran scored 75%. By what percent did kiran's score improve?
In first test kiran got 60
In last test he got 75.
% increase in test = (60(x+100))/100=75
=> 0.6X+60 = 75
=> 0.6X = 15
=> X=15/0.6 = 25%
Workspace
NA
SHSTTON
66
Solv. Corr.
63
Solv. In. Corr.
129
Attempted
0 M:32 S
Avg. Time
13 / 99
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A candidate who gets 20% marks fails by 10 marks but another candidate who gets 42% marks gets 12% more than the passing marks. Find the maximum marks.
Let the maximum marks be x.
From the given statement pass percentage is 42% - 12% = 30%
By hypothesis, 30% of x - 20% of x = 10 (marks)
i.e., 10% of x = 10
Therefore, x = 100 marks.
Workspace
NA
SHSTTON
95
Solv. Corr.
54
Solv. In. Corr.
149
Attempted
0 M:33 S
Avg. Time
14 / 99
Choose the correct option.
Randy's chain of used car dealership sold 16,400 cars in 1998. If the chain sold 15,744 cars in 1999, by what percent did the number of cars sold decrease?
Let the population =x Males=(5/9)x
Married males = 30% of (5/9)x = x/6
Married females = x/6
Total females = (x-(5/9)x)=4x/9
Unmarried females = (4x/9 - x/6) = 5x/18
Required percentage = (5x/18 * 1/x * 100) = (250/9)%
Workspace
NA
SHSTTON
26
Solv. Corr.
100
Solv. In. Corr.
126
Attempted
0 M:0 S
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16 / 99
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In an election contested by two parties, Party D secured 12% of the total votes more than Party R. If party R got 132,000 votes, by how many votes did it lose the election?
Let the percentage of the total votes secured by Party D be x%
Then the percentage of total votes secured by Party R = (x – 12)%
As there are only two parties contesting in the election, the sum total of the votes secured by the
two parties should total up to 100%
i.e., x + x – 12 = 100
2x – 12 = 100
or 2x = 112 or x = 56%.
If Party D got 56% of the votes, then Party got (56 – 12) = 44% of the total votes.
44% of the total votes = 132,000 i.e. 44/100 * T = 132,000
T = (132000 * 100)/44 = 300000 votes.
The margin by which Party R lost the election = 12% of the total votes
= 12% of 300000 = 36000.
Workspace
NA
SHSTTON
41
Solv. Corr.
63
Solv. In. Corr.
104
Attempted
0 M:0 S
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17 / 99
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Increase area of a square by 69% by what percent should the side be incresed
Then area of increase=100+69=169
square root of 169 i.e 13 .
Workspace
NA
SHSTTON
49
Solv. Corr.
52
Solv. In. Corr.
101
Attempted
0 M:9 S
Avg. Time
18 / 99
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The boys and girls in a college are in the ratio 3:2. If 20% of the boys and 25% of the girls are adults, the percentage of students who are not adults is:
decrease in salary in single shot =38.8%
first decease =20% let the salary be 100 then it will become 80
2nd decrease is= 15%. 15% of 80 =12 then salary become 68
3rd decrease is of 10% . 10% of 68 =6.8.then salary become 61.2
so overall decrease=38.8%
Workspace
NA
SHSTTON
33
Solv. Corr.
66
Solv. In. Corr.
99
Attempted
2 M:55 S
Avg. Time
20 / 99
Choose the correct option.
In a society of 80 resident families who subscribe newspapers, 60% of them subscribe The Hindu newspaper, 80% of them subscribe regional language newspaper and 70% of them subscribe TOI. How many families could, at the least, be subscribing to all the three newspapers
Total no. of families who take newspaper=80
Hindu newspaper = 60% = (80*60/100) = 48
Regional newspaper = 80% = (80*80/100) = 64
TOI newspaper = 70% = (70*80/100) = 56
Find common families take H.C.F (48,64,56) = 8
Therefore,(8/80)*100=10%
So, common families who take all newspaper = 10%.
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