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1 / 16
If the simple interest on a sum of money for 2 years at 5% per annum is Rs. 50, what is the compound interest on the same at the same rate and for the same time?
Answer: Option A
Explanation:Sum = Rs. (50 * 100)/(5*2) = Rs. 500.
Amount = Rs. [500 * (1 + 5/100)2]
= Rs. (500 * 21/20 * 21/20 )
= Rs. 551.25
C.I. = Rs. (551.25 - 500) = Rs. 51.25
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2 / 16
What is the difference between the compound interests on Rs. 5000 for 1 1/2 years at 4% per annum compounded yearly and half-yearly?
Answer: Option A
Explanation:C.I. when interest
compounded yearly=rs.[5000*(1 4/100)(1 1/2*4/100)]
= Rs. 5304.
C.I. when interest is
compounded half-yearly=rs.5000(1 2/100)^3
= Rs. 5306.04
Difference = Rs. (5306.04 - 5304) = Rs. 2.04
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3 / 16
A sum of money amounts to Rs.6690 after 3 years and to Rs.10035 after 6 years on compound interest. Find the sum.
Answer: Option D
Explanation:Let's assume the Sum = Rs. P.
P [1 + (R/100)]^3 = 6690 -------- (i)
P [1 + (R/100)]^6 = 10035 ----------(ii)
On dividing, we get [1 + (R/100)]^3 = 10035/6690 = 3/2.
P * (3/2) = 6690 or P = 4460.
Hence, the sum is Rs. 4460.
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4 / 16
The difference between the compound interest and the simple interest on a certain sum at 12% p.a. for two years is Rs.90. What will be the value of the amount at the end of 3 years?
Answer: Option B
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5 / 16
A sum of money doubles itself at C.I. in 15 years. In how many years will it become eight times?
Answer: Option D
Explanation:P [1 + (R/100)]^15 = 2P => [1 + (R/100)]^15 = 2 ----------- (i)
Let P [1 + (R/100)]^n = 8P => P [1 + (R/100)]^n = 8 = 2^3
= [{1 + (R/100)}^15]^3.
=> [1 + (R/100)]^n = [1 + (R/100)]^45.
=> n = 45.
So, the required time = 45 years.
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6 / 16
The principal that amounts to Rs. 4913 in 3 years at 6 1/4 % per annum C.I. compounded annually, is?
Answer: Option B
Explanation:Formula: P = Amount / (1 + R/100)^n
Principal = [4913 / (1 + 25/(4 * 100))3]
=> 4913 * 16/17 * 16/17 * 16/17 = Rs. 4096
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7 / 16
Anil invests an amount for 2 years at the rate of 15% per annum at simple interest.Had he invested in a scheme in which interest was compounded yearly he would have got Rs.450 more. Find the principal:
Answer: Option C
Explanation:Lets assume D amount difference between compound and simple interest for 2 years, D=P*(R/100)^2
where P is the principal
R is rate of interest
so here,
450 = P*(15/100)^2 => P= Rs. 20000
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8 / 16
If the compound interest (compounded Yearly) on a certain sum for 2 years at 3% is Rs.101.50 then what will be the corresponding simple interest?
Answer: Option B
Explanation:Given, years = 2
3% of 50= (50*(3/100))=Rs.1.5
Simple Interest =50+50=100
Compound Interest=50+50+1.5=101.5
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9 / 16
If the compound interest on a sum of Rs.5000 at the rate of 10% per annum is Rs.1050, then time period is (Interest compounded yearly):
Answer: Option D
Explanation:C.I of 5000 at 10% interest for x years is 6050 = Rs. 1050
6050 = 5000 ( 1 + 10/100)^n => 6050/5000 = (11/10)^n
=> 605/500 = (11/10)^n => n = 2 years.
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10 / 16
At what rate of interest (compounded yearly)will Rs. 10,000 amount to Rs. 12,100 in 2 years?
Answer: Option D
Explanation:Amount = P(1 + R/100)^n
Where Principal = P, Rate = R% per annum, Time = n years.
12100 = 10000 (1+R/100)^2
=> 121/100 = (1+R/100)^2
=> 11/10 = (1+R/100)=> 11/10 = (100 + R)/100
=> 110 = 100 + R => R = 10%
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