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The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is:
A17 kg
B20 kg
C26 kg
D31 kg
Answer: Option D
Explanation:Let A, B, C represent their respective weights. Then, we have:
A + B + C = (45 x 3) = 135
A + B = (40 x 2) = 80
B + C = (43 x 2) = 86
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2 / 94
What is the average (arithmetic mean) of all the multiples of ten from 10 to 190 inclusive?
A90
B95
C100
D105
E110
Answer: Option C
Explanation:Answer:100
Solution: All the multiples are (10 20 30 40 50 60 70 80 90 100 110 120 130 140 150 160 170 180 190)/19=100
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3 / 94
The average salary of 3 workers is 95 Rs. per week. If one earns Rs.115 and second earns Rs.65 how much is the salary of the 3rd worker.
A285
B150
C105
D104
Answer: Option C
Explanation:Lets assume three workers a a,b and c
Their average salary is (a+b+c)/3 = 95
=> a+b+c=285
a=115,
b=65
So c=285-115-65=105
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4 / 94
The average length of three tapes is 6800 feet. None of the tapes is less than 6400 feet. What is the greatest possible length of one of the other tapes?
A7600
B7500
C7000
D8000
Answer: Option A
Explanation:Minimum length = 6400
2 tap can be of length 6400,
So the next one will be max = (6800*3)-(2*6400)=7600
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5 / 94
When a student weighing 45 kgs left a class, the average weight of the remaining 59 students increased by 200g. What is the average weight of the remaining 59 students
A55
B56
C57
D58
Answer: Option C
Explanation:Lets assume average weight of the 59 students = x kgs.
=> Total weight of the 59 = 59*x
Given when the weight of this student who left is added, the total weight of the class = (59x + 45)
The average weight decreases by 0.2 kgs, when these students included.
=> (59x+45)/60=(x-0.2)
=> (59x+45)= 60(x-0.2)
=> 59x + 45 = (60A - 12)
=> 45 + 12 = 60x - 59x
=> x = 57
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6 / 94
In Arun's opinion, his weight is greater than 65 kg but less than 72 kg. His brother doest not agree with Arun and he thinks that Arun's weight is greater than 60 kg but less than 70 kg. His mother's view is that his weight cannot be greater than 68 kg. If all are them are correct in their estimation, what is the average of different probable weights of Arun?
A67 kg.
B68 kg.
C69 kg.
DData Inadequate
Answer: Option A
Explanation:Let Arun's weight by X kg.
According to Arun, 65 < X < 72 -------(1)
According to Arun's brother, 60 < X < 70 ------ (2)
According to Arun's mother X <= 68 --------- (3)
The values satisfying all above 3 conditions are 66, 67 and 68.
so average = (66 + 67 + 68)/3 = 201/3 = 67 kg.
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7 / 94
A library has an average of 510 visitors on Sundays and 240 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is:
A250
B276
C280
D285
Answer: Option D
Explanation:Required average
=> (510 * 5 + 240 * 25)/30.
=> 8550/30
=> 285.
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8 / 94
The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person?
A76 kg
B85 kg
C76.5 kg
DData inadequate
Answer: Option B
Explanation:Given total weight increased by 2.5 kg.
So total weight increased = (8 x 2.5) kg = 20 kg.
Weight of the new person = (65 + 20) kg = 85 kg.
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9 / 94
The average of 7 consecutive numbers is 20. The largest of these numbers is
A20
B22
C23
D24
Answer: Option C
Explanation:Let the first number be x,
So last number will be (x+6)
Average = [x+(x+1)+(x+2)+(x+3)+(x+3)+(x+4)+(x+5)+(x+6)]/7 = 20
=> (7x+21) = 20*7
=> 7x = 119
=> x = 17
So largest number= (x+6) = (17+6) = 23
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10 / 94
The average of four consecutive odd numbers is 24. Find the largest number.
A25
B27
C29
D31
Answer: Option B
Explanation:The numbers will be x, x+2, x+4, x+6
so [x+(x+2)+(x+4)+(x+6)]/4=24
=>(4x+12)/4=24
=> (x+3)=24
=>x=21
So largest number = (21 + 6) = 27
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