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In how many ways can a group of 5 men and 2 women be made out of a total of 7 men and 3 women?
A63
B90
C126
D45
E135
Answer: Option A
Explanation:Total 7 men and 3 women
5 men can be selected from 7 men in 7C5 ways
2 women can be selected from 3 women in 3C2 ways
So 7C5*3C2= 63 ways.
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In how many different ways can the letters of the word 'CORPORATION' be arranged so that the vowels always come together?
A810
B1440
C2880
D50400
Answer: Option D
Explanation:In the word "CORPORATION",treat those vowels OOAIO as one letter.
so it will be "CRPRTN (OOAIO)".
which is having 7 (6 + 1) letters. out of which R occurs 2 times and the rest are different.
Number of ways arranging these letters = (7!/2!) = 2520.
Now 5 vowels in which O occurs 3 times and the rest are different, can be arranged as 5!/3! = 20 ways.
So required number of ways = (2520 x 20) = 50400.
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3 / 95
How many 4-letter words with or without meaning, can be formed out of the letters of the word, 'LOGARITHMS', if repetition of letters is not allowed?
A40
B400
C5040
D2520
Answer: Option C
Explanation:LOGARITHMS' contains 10 different letters.
Required number of words = Number of arrangements of 10 letters, taking 4 at a time.
= 10P4
= (10 x 9 x 8 x 7)
= 5040.
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4 / 95
23 people are there, they are shaking hands together, how many hand shakes possible, if they are in pair of cyclic sequence.
A23
B20
C22
D1
ENone of these
Answer: Option C
Explanation:
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5 / 95
Six friends go to pizza corner there are 2 types of pizzas. And six different flavors are there they have to select 2 flavors from 6 flavors. In how many ways we can select?
A6C2
B6P2
C(6C2)/2!
DNone of these
Answer: Option A
Explanation:Number of ways 2 flavors can be selected out of 6 flavors = 6c2 = 15
Number of ways pizza can be selected = 2 [there are 2 types of pizzas]
âˆ´ Number of ways to select a pizza = 2 Ã— 15 = 30 ways
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36 people {a1, a2, ..., a36} meet and shake hands in a circular fashion. In other words, there are totally 36 handshakes involving the pairs, {a1, a2}, {a2, a3}, ..., {a35, a36}, {a36, a1}. Then size of the smallest set of people such that the rest have shaken hands with at least one person in the set is
A12
B11
C13
D18
Answer: Option D
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7 / 95
From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least 3 men are there on the committee. In how many ways can it be done?
A564
B645
C735
D756
Answer: Option D
Explanation:We may have (3 men and 2 women) or (4 men and 1 woman) or (5 men only).
Required number of ways = (7C3 * 6C2)+(7C4 * 6C1)+(7C5)
=>[(7*6*5)/(3*2*1) * (6*5)/(2*1)]+(7C3 * 6C1) + (7C2)
=> 525 + [(7*6*5)/(3*2*1)* 6]+[(7*6)/(2*1)]
= (525 + 210 + 21)
= 756
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In how many different ways can the letters of the word 'MATHEMATICS' be arranged so that the vowels always come together?
A10080
B4989600
C120960
DNone of these
Answer: Option C
Explanation:In the word 'MATHEMATICS', we treat the vowels AEAI as one letter.
Thus, we have MTHMTCS (AEAI).
Now, we have to arrange 8 letters, out of which M occurs twice, T occurs twice and the rest are different.
So,Number of ways of arranging these letters = (8!/2!*2!)=10080.
Now, AEAI has 4 letters in which A occurs 2 times and the rest are different.
Number of ways of arranging these letters = (4!/2)=12.
=> Required number of words = (10080 * 12) = 120960.
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Consider the word ROTOR. Whichever way you read it, from left to right or from right to left, you get the same word. Such a word is known as palindrome. Find the maximum possible number of 5-letter palindromes?
A16576
B17576
C56689
D35142
Answer: Option B
Explanation:The first letter from the right can be chosen in 26 ways because there are 26 alphabets.
Having chosen this, the second letter can be chosen in 26 ways.
=> The first two letters can be chosen in 26*26=676 ways
Having chosen the first two letters, the third letter can be chosen in 26 ways.
=> All the three letters can be chosen in 676*26=17576 ways.
=> maximum possible number of five letter palindromes is 17576 because the fourth letter is the same as the second letter and the fifth letter is the same as the first letter.
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In how many ways can an animal trainer arrange 5 lions and 4 tigers in a row so that no two lions are together
A2880
B1440
C5760
DNone of these
Answer: Option A
Explanation:The lions and the tigers can be arranged in 5!*4!= 2880 ways
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