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Control Instructions Questions

NA
SHSTTON
9
Solv. Corr.
146
Solv. In. Corr.
155
Attempted
0 M:6 S
Avg. Time

11 / 33

Choose the correct option.

A "switch" statement is used to


Aswitch between functions in a program

Bswitch from one variable to another variable

Cto choose from multiple possibilities which may arise due to different values of a single variable

Dto use switching variable

Answer: Option B

Explanation:

Here is no explanation for this answer

Workspace

NA
SHSTTON
89
Solv. Corr.
71
Solv. In. Corr.
160
Attempted
0 M:18 S
Avg. Time

12 / 33

What would be the output of below program if choice = 'R'?
void main() {
switch (choice) {
case 'R': printf("RED");
 case 'W': printf("WHITE"); 
case 'B' : prinf ("BLUE"); 
default: printf("ERROR");
break;
}

ARED

BRED ERROR

CRED WHITE BLUE ERROR

DRED WHITE BLUE

Answer: Option C

Explanation:

The answer is C

As it prints RED then there is no break statement in the switch statment so the rest of the all cases will execute. 

so the output is REDWHITEBLUEERROR

Workspace

NA
SHSTTON
107
Solv. Corr.
43
Solv. In. Corr.
150
Attempted
0 M:12 S
Avg. Time

13 / 33

What is the output of the below fragment of C code, if i = 3?
if (i >1)c = 2;
else c = 3;
switch (c) {
case 2: printf("CAUTION");
break;
case 3: printf("GOOD BYE");
break;
default : printf("TERROR");
}

ACAUTION

BGOOD BYE

CERROR

DDefault

Answer: Option A

Explanation:

Here is no explanation for this answer

Workspace

NA
SHSTTON
4
Solv. Corr.
133
Solv. In. Corr.
137
Attempted
0 M:58 S
Avg. Time

14 / 33

Consider the following C program fragment.
if (marks > 80)
grad = 'A';
else if ((marks > 70) && (attendance > 75 ))
grade= 'B';
else if (attendanc < 75)
grade = 'R';
if ((marks > 60) && (attendance > 50))
grade= 'F';
else 
grade = 'E'

What is the value of grade if marks = 565 and attendance = 80?

AA

BB

CF

DE

Answer: Option D

Explanation:

As the marks =565 and the if case is starting from marks >80 

This satisfy the condition so I think ans should be option A i.e A grade

Workspace

NA
SHSTTON
55
Solv. Corr.
79
Solv. In. Corr.
134
Attempted
0 M:0 S
Avg. Time

15 / 33

Choose the correct option.

A continue statement causes execution to skip to


Athe return 0; statement

Bthe first statement after the loop

Cthe statement following the continue statement

Dthe next iteration of the loop

Answer: Option C

Explanation:

Here is no explanation for this answer

Workspace

NA
SHSTTON
38
Solv. Corr.
97
Solv. In. Corr.
135
Attempted
0 M:0 S
Avg. Time

16 / 33

Choose the correct option.

The call zap(6) gives the values of zap

int zap(int n){
if(n<=1)then zap=1;
else zap=zap(n-3)+zap(n-1);
}


A8

B9

C6

D12

Answer: Option B

Explanation:

This function is a recursive function now read the below statements carefully


when zap(6) is called it needs value of zap(3) and zap(5)

further zap(3) needs value of zap(0) and zap(2) ( zap(0) returns 1 ) now it only needs value of zap2


now zap(2) needs value of zap(-1) and zap(1) they both return a value of 1 (as n<=1 value of 1 is returned by zap(-1) anb zap(1) )


so zap(2) is now equal to 2
which return its value to zap(3) which is now equal to zap(0)+zap(2)=1+2 = 3;

similarly zap(5) will need value of zap(2) and zap(4) value of zap(2) is equal to 2;

zap(4) will need value of zap(1) and zap(3) zap(1)=1 and zap(3) = 3;

so zap(4) = zap(3)+zap(1) = 3+1=4;

zap(5)=zap(2)+zap(4)=2+4=6;

zap(6)=zap(3)+zap(5)=3+6=9;

Workspace

NA
SHSTTON
51
Solv. Corr.
82
Solv. In. Corr.
133
Attempted
0 M:0 S
Avg. Time

17 / 33

Point out the error in the program
#include<stdio.h>
int f(int a){
    a > 20? return(10): return(20);
}
int main(){
    int f(int);
    int b;
    b = f(20);
    printf("%d\n",B);
    return 0;
}

AError: Prototype declaration

BNo error

CError: return statement cannot be used with conditional operators

DNone of these

Answer: Option C

Explanation:

Here is no explanation for this answer

Workspace

NA
SHSTTON
14
Solv. Corr.
120
Solv. In. Corr.
134
Attempted
1 M:41 S
Avg. Time

18 / 33

What will be the result of the following program?
#include <stdio.h>
int main()
{
       int ones, twos, threes, others;
       int c;
       ones = twos = threes = others = 0;
       while ((c = getchar ()) != EOF)
       {
                  switch (c)
                  {
                     case '1': ++ones;
                     case '2': ++twos;
                     case '3': ++threes;
                                       break;
                     default: ++others;
                                       break;
                  }
       }
       printf ("%d  %d", ones, others);
       return 0;
    }

A1 1

B3 4

C3 2

D3 3

EError

Answer: Option D

Explanation:

Here is no explanation for this answer

Workspace

NA
SHSTTON
29
Solv. Corr.
92
Solv. In. Corr.
121
Attempted
0 M:46 S
Avg. Time

19 / 33

What will be output of following c program?
#include<stdio.h>
int main(){
int i=0;
for(i=0;i<20;i++){
switch(i){
case 0:i+=5;
case 1:i+=2;
case 5:i+=5;
default: i+=4; break;
}
printf("%d ",i);
}
return 0;
}

A0 5 9 13 17

B5 9 13 17

C12 17 22

D16 21

ESyntax error

Answer: Option D

Explanation:

Here is no explanation for this answer

Workspace

NA
SHSTTON
26
Solv. Corr.
77
Solv. In. Corr.
103
Attempted
0 M:7 S
Avg. Time

20 / 33

What will be output of following c program?
#include<stdio.h>
int main(){
char c=-64;
int i=-32;
unsigned int u =-16;
if(c>i){
printf("pass1");
if(c<i)
printf("pass2");
else
printf("Fail2");
}
else
printf("Fail1”);

if(c==i)
printf("pass2");
else
printf("Fail2");
return 0;
}

APass1Pass2

BPass1Fail2

CFail1Pass2

DFail1Fail2

ENone of these

Answer: Option D

Explanation:

Here is no explanation for this answer

Workspace

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