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Process Management Questions

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In round robin scheduling, if time quantum is too large then it degenerates to


ARound Robin

BFCFS

CSJF

DSRT

Answer: Option B

Explanation:

Here is no explanation for this answer

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In a processor these are 120 instructions . Bits needed to implement this instructions


A6

B10

C7

Dnone of these

Answer: Option C

Explanation:

Here is no explanation for this answer

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Banker's algorithm for resource allocation deals with


ADeadlock avoidance

BDeadlock prevention

CDeadlock recovery

DNone of these

Answer: Option A

Explanation:

Here is no explanation for this answer

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If the time quantum is too large, Round Robin scheduling degenerates to


AShortest Job First Scheduling

BMultilevel Queue Scheduling

CFCFS

DNone of these

Answer: Option C

Explanation:

Here is no explanation for this answer

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Choose the correct option.

Semaphore is used for


Asynchronization

Bdead-lock avoidance

Cbox

DNone of these

Answer: Option A

Explanation:

Semaphores are synchronization tools.

Any integer(non negative) can act as semaphore. Semaphores are used for counting tasks such as creating a critical region that allows a specified number of threads to enter. For example, if we want at most four threads to be able to enter a section, we could protect it with a semaphore and initialize that semaphore to four.The first four threads will be able to decrement the semaphore and enter the region, but at that point, the semaphore will be zero and any other thread will be blocked from outside the critical region until one of the current threads leaves and signals the semaphore.

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Choose the correct option.

CPU Scheduling is a function of OS under


AProcess Management

BMemory Management

CI/O Management

DNone of these

Answer: Option A

Explanation:

Here is no explanation for this answer

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Choose the correct option.

Which of following is not a condition of Dead Lock ?


AMutual Exclusion

BNo Preemption

CHold and Wait

DData Transfer

Answer: Option D

Explanation:

There are four conditions for a deadlock to occur-

1. Mutual exclusion

2. Hold & wait

3. Circular wait

4. No preemption

Option D is the odd one out.

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Choose the correct option.

Which is non pre-emptive


ARound robin

BFIFO

CMQS

DMQSF

Answer: Option B

Explanation:

Round Robin: It is a preemptive mode of CPU scheduling. In this, the available processes which join the ready queue are selected in FCFS order for execution. Also, each process is allowed to execute for a fixed time quantum, i.e, the maximum allowable time given to each process to execute. When the time quantum is reached, the process joins the ready queue, and again waits for the CPU to get alloted to it. Only those processes waits in the ready queue which still has their CPU burst time left. When a process completes its execution, it terminates.

FIFO: FIFO or FCFS is a non-preemptive mode of CPU scheduling where the processes are allocated CPU based o arrival time, i.e, lower the arrival time, earlier will be the CPU allotment. Each process will be alloted CPU until and unless the process terminates.

MQS(Multilevel Queue Scheduling): In this, processes are classified into different groups. For example, interractive processes(foreground) and batch processes(background) are two types because of their different response time, scheduling needs and priorities. This algorithm partitions the ready queue into separate queues. Processes are permanently assigned to each queue. This is done based upon the properties such as memory size or process type.

MQSF(Multilevel feedback queue scheduling): It is an enhancement of MQS. The principle here is that processes can move between the queues now. In this scheduling, the ready queue is partitioned into multiple queue of different priorities. The processes are assigned to the queues by the system based ontheir CPU-burst time characteristics. This means that if a process consumes too much of CPU time, it is placed into a lower priority queue. So I/O bound and interractive processes stay in the higher priority queues and the CPU bound processes move to the lower priority queues. However, these processes in the lower priority queues should be promoted to the next higher priority queue after a suitable time interval. This technique is known as Aging.


 

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Choose the correct option.

Shortest Job First executes first the job


Awith the least processor needs

Bthat first entered the queue

Cthat has been in the queue for the longest

Dthat last entered the queue

Answer: Option A

Explanation:

Shortest Job First(SJF) scheduling: The basic principle of SJF algorithm is to allocate the CPU to the process with least CPU burst time. The processes are available in the ready queue. CPU is always assigned to the process with least CPU burst time requirements.

Example-

ProcessCPU burst time
P15
P210
P38
P43

Since, the process with smallest CPU burst time is executed first, so these processes would be scheduled in P4 --> P1 --> P3 --> P2 order. SO, average waiting time = (0+3+8+16) / 4 = 6.75 ms.

SJF is an optimal algorithm since this algorithm gives minimum average waiting rime.


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Choose the correct option.

The register context and stacks of a thread are deallocated when the thread


Aterminates

Bblocks

Cunblocks

Dspawns

Answer: Option A

Explanation:

Here is no explanation for this answer

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