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Problems on Time and Work

Home > Quantitative Aptitude > Time and Work > General Questions
NA
SHSTTON
52
Solv. Corr.
48
Solv. In. Corr.
100
Attempted
0 M:47 S
Avg. Time

11 / 90

Choose the correct option.

A, B and C can complete a piece of work in 24, 6 and 12 days respectively. Working together, they will complete the same work in


A7/24

B3 3 /7

C4 3/7

D3 4/7

Answer: Option B

Explanation:

1 day work done by A, B and C will be 1/24, 1/6 and 1/12 respectively.
So (A + B + C)'s 1 day's work = (1/24+1/6+1/12) = (1/24 + 4/24 + 2/24)
= 7/24
So, A, B and C together can complete the job in 24/7=3 3/7 days
.

Workspace

NA
SHSTTON
59
Solv. Corr.
54
Solv. In. Corr.
113
Attempted
1 M:6 S
Avg. Time

12 / 90

Choose the correct option.

A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With the help of C, they did the job in 4 days only. Then, C alone can do the job in :


A1/9

B9 3/5

C9 2/5

D9 4/5

ENone of these

Answer: Option B

Explanation:

1 day's work done by A = 1/16
1 day's work done by B = 1/12
1 day's work done by (A, B and C) = 1/4
=> so C 1 day's work = (1/4-1/12-1/16) = (12/48-4/48-3/48) = 5/48
so C alone can do the work = 48/5 days = 9 3/5 days

Workspace

NA
SHSTTON
37
Solv. Corr.
47
Solv. In. Corr.
84
Attempted
1 M:52 S
Avg. Time

13 / 90

Choose the correct option.

A takes twice as much time as B or thrice as much time to finish a piece of work. Working together, they can finish the work in 2 days. B can do the work alone in .


A4 days

B8 days

C6 days

D12 days

Answer: Option C

Explanation:

Let's suppose A, B and C take x, x/2 and x/3 hours respectively to finish the work.

So their 1 day's work (1/x+2/x+3/x)=1/2 => 6/x = 1/2
=> x=12

So, B take 6) hours to finish the work.

Workspace

NA
SHSTTON
36
Solv. Corr.
43
Solv. In. Corr.
79
Attempted
2 M:3 S
Avg. Time

14 / 90

Choose the correct option.

A machine P can print one lakh books in 8 hours, machine Q can print the same number of books in 10 hours while machine R can print them in 12 hours. if All the machines are started at 9 a.m. while machine P is closed at 11 a.m. and the remaining two machines complete the work. Approximately at what time will the work be finished ?


A11:30 a.m.

B12 noon

C12:30 p.m.

D1 p.m.

Answer: Option D

Explanation:

find the (P + Q + R)'s 1 hour's work = (1/8+1/10+1/12) = 37/120

So Work done by P, Q and R in 2 hours = (2*37/120) = 37/60

Now find the Remaining work = (1?37/60) = 23/60

(Q + R)'s 1 hour's work = (1/10+1/12) = 11/60
OR
Time taken to do 11/60 part of work by (Q+R) = 1 hrs.
=> so to do whole work by (Q&R) = 60/11 hrs
so for 23/60 part of work = (23/60*60/11) hrs. = 23/11 = ~2 hrs.

So, the work will be finished approximately 2 hours after 11 a.m . i.e., around 1 p.m.

Workspace

NA
SHSTTON
31
Solv. Corr.
37
Solv. In. Corr.
68
Attempted
0 M:59 S
Avg. Time

15 / 90

Choose the correct option.

A and B can complete a work in 15 days and 10 days respectively. They started doing the work together but after 2 days B had to leave and A alone completed the remaining work. The whole work was completed in:


A8 days

B10 days

C12 days

D15 days

Answer: Option C

Explanation:

(A+ B)'s 1 day's work = (1/15+1/10) = 5/30 = 1/6

So work done by A and B in 2 days = (1/6?2) = 1/3

so Remaining work = (1?1/3) = 2/3

A 1 day work = 1/15
or
1/15 work is done by A in = 1 day.

? 2/3 work will be done by A = (15?2/3) = 10 days.

so total time required = (10 + 2) = 12 days.

Workspace

NA
SHSTTON
41
Solv. Corr.
27
Solv. In. Corr.
68
Attempted
2 M:6 S
Avg. Time

16 / 90

Choose the correct option.

A can finish a work in 24 days, B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in :


A5 days

B6 days

C10 days

D10 1/2days

Answer: Option C

Explanation:

A's 1 day work = 1/24
B's 1 day work = 1/9
C's 1 day work = 1/12

S0 (B + C)'s 1 day's work = (1/9+1/12)=7/36

Work done by B and C in 3 days = (3*7/36)=7/12

left work = (1?7/12)=5/12

.

1/24 part of work done by A = 1 day.

So 5/12 part of work is done by A = (24?5/12) = 10 days.

Workspace

NA
SHSTTON
35
Solv. Corr.
31
Solv. In. Corr.
66
Attempted
1 M:22 S
Avg. Time

17 / 90

Choose the correct option.

P can do a piece of work in 40 days. He works at it for 8 days arid then Q finished it in 16 days. How long will they together take to complete the work ?


A13 1/3days

B15 days

C20 days

D56 days

Answer: Option A

Explanation:

P one day work = 1/40
So P 8 days Work = (8*1/40)=1/5

Left work = (1?1/5)=4/5

4/5 part of work is done by Q = 16 days.

So Whole work will be done by Q = [16/(4/5)] = 16*5/4 = 20 days.

Q's 1 day's work = 1/20

(P + Q)'s 1 day's work = (1/40+1/20) = 3/40

Hence,( P and Q) together complete the work = 40/3=13 1/3 days.

Workspace

NA
SHSTTON
38
Solv. Corr.
27
Solv. In. Corr.
65
Attempted
1 M:30 S
Avg. Time

18 / 90

Choose the correct option.

A does 4/5 of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work ?


A23 days

B37 days

C37 1/2 days

D40 days

Answer: Option C

Explanation:

4/5 part of work done by A = 20 days.

Whole work is done by A = (20?5/4) = 25 days.

Left work = (1-4/5) = 1/5

1/5 part of work is done by (A & B) = 3 days.

Whole work will be none by A and B = (3 x 5) = 15 days.

A's 1 day's work = 1/25
(A + B)'s 1 day's work = 1/15

B's 1 day's work = (1/15?1/25)=10/(15*25)=2/75

So, B alone would do the work in 75/2=37 1/2 days.

Workspace

NA
SHSTTON
30
Solv. Corr.
33
Solv. In. Corr.
63
Attempted
1 M:26 S
Avg. Time

19 / 90

Choose the correct option.

A, B and C together can complete a piece of work in 10 days. All the three started working at it together and after 4 days A left. Then B and C together completed the work in 10 more days. A alone could complete the work in :


A15 days

B16 days

C25 days

D50 days

Answer: Option C

Explanation:

(A,B and C) 1 day work = 1/10
Work done by (A, B and C) in 4 days = 4*1/10=2/5
Left work = (1?2/5)=3/5

3/5 part of work is done by (B and C) = 10 days.

(B + C)'s 1 day's work = 3/50

So Whole work will be done by (B and C) = (10?5/)3 = 50/3 days.
=> (B+C)'s 1 day work = 3/50
A's 1 day's work = (1/10?3/50)=2/50=1/25

So A alone could complete the work in 25 days.

Workspace

NA
SHSTTON
25
Solv. Corr.
30
Solv. In. Corr.
55
Attempted
0 M:42 S
Avg. Time

20 / 90

Choose the correct option.

A man can do a piece of work in 5 days, but with the help of his son, he can do it in 3 days. In what time can the son do it alone ?


A6 1/2

B2 1/7

C2/15

D7 1/2

Answer: Option D

Explanation:

1 day's work done by man = 1/5
1 day's work done by man and his son = 1/3
=> His son 1 day's work = (1/3-1/5) = (5/15-3/15) = 2/15
so his son can do it alone = 15/2 days = 7 1/2 days

Workspace

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