Quantitative Aptitude :: Time and Work - Discussion
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A can complete a piece of work in 8 hours, B can complete in 10 hours and C in 12 hours. If A,B, C start the work together but A laves after 2 hours. Find the time taken by B and C to complete the remaining work.
A2 (1/11) hours
B4 (1/11) hours
C2 (6/11) hours
Asked In ::
18 Nov, 2019 2:03 AM
A=8 hrs ,B=10 hrs ,C= 12 hrs
Work done by them together in 1hr=1/8+1/10+1/12= 37/120
In 2hrs=37/60. Work left= 23/60
Now A left after 2 hrs so remaining 23/60 will be done by B & C together.
If B & C work together in 1 hour they can do 1/10+1/12=11/60
So 11/60 in 1 hr. So 1 in 60/11 hr.
Therefore 23/60 in 23/60 * 60/11= 23/11hours.
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