Let the number be x. then,
\(\frac{3}{5}x^2=126.15 \Leftrightarrow x^2=\left(126.15\times\frac{5}{3}\right)=210.25\)
\( \Leftrightarrow x=\sqrt{210.25}=14.5\)
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If \(\sqrt{1+\frac{55}{729}}=1+\frac{x}{27}\),then the value of x is:
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