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Quantitative Aptitude :: Simplification - Discussion

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Choose the correct option.

For what values of 'm' is y = 0, if y = x^2 + (2m + 1)x + m^2 - 1? x is a real number.

Am >= -2

Bm < 0

Cm = 0

Dm >= -1.25

Answer: Option (Login/Signup)

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Asked In :: AMCAT

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