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# Profit and Loss Questions

Home > Quantitative Aptitude > Profit and Loss > General Questions
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Choose the correct option.

A vendor bought toffees at 6 for a rupee. How many for a rupee must he sell to gain 20%?

A3

B4

C5

D6

Explanation:

C.P. of 6 toffees = Re. 1

S.P. of 6 toffees = 120% of Re. 1 = Rs. (120/100 ) = Rs. 6/5
so toffees in Re 1 = 6 * 5/6 = 5

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Find S.P, when (1) C.P. = Rs. 56.25, Gain = 20% (2) C.P. = Rs. 80.40, Loss = 15%

A(1) Rs. 67.50 (2) Rs. 68.34

B(1) Rs. 68.50 (2) Rs. 65.34

C(1) Rs. 78.50 (2) Rs. 75.34

D(1) Rs. 68.50 (2) Rs. 65.34

Explanation:

(1) S.P = 120 of Rs. 56.25
= Rs. (120/100 * 56.25) = Rs. 67.50
(2) S.P. = 85% of Rs. 80.40
= Rs. (85/100 *80.40) = Rs. 68.34

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It cost a college Rs.0.70 a copy to produce a Programme for the homecoming football game. If Rs.15,000/- was received for advertisements in the programme, how many copies at Rs.0.50 a copy must be sold to make a profit of Rs.8000/- ?

A30000

B34000

C35000

D25000

Explanation:

Copy is sold at loss =0.70-0.50=0.20
Even then a profit of 8000 is made.
Let N be no. of copies.
Therefore,
(N*0.2)+8000=15000
N*0.20=7000
N=35000
So 35000 copies sold

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A shopkeeper marked a suit at Rs.400. He sold it after allowing a discount, and still made at a profit of 25%. At what percentage above its cost price did he marked the suit, if he sold it for Rs.320?

A50%

B66.67%

C62.50%

D56.25%

Explanation:

Solution: There are two selling prices equation equating them we will get the answer.

S.P on obtaining profit= S.P. on getting discount  ( let the C.P BE x)

125x/100 = 80/100 * 400

solving the equation we get x= 256 Rs that is the cost price. So Marked Price was 400

Therefore (400-256)/256 *100%  =56.25%

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The price of an article was increased by p%. Later the new price was decreased by p%. If the latest price was Rs.1, the original price was:

A(1-p^2)/100

BRs. 1

C[10000/(10000-p^2)

Dsqr [(1-p^2)/100]

Explanation:

NetProfit=p%-p% -pXp/100=p2/100
=>original+original*Net_Profit=RS 1
=>Original=[10000/(10000-p^2)]

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