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# Profit and Loss Questions

Home > Quantitative Aptitude > Profit and Loss > General Questions
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A merchant has announced 25% rebate on prices of ready-male garments at the time of sale. If a purchaser needs to have a rebate of Rs. 400 then how many shirts each costing Rs. 320, Should he purchase?

A10

B7

C6

D5

Answer: Option D

Explanation:

Discount at the shirt costing Rs. 320
= 320*25/100 = Rs. 80
So Number of shirts for a rebate of Rs. 400 = 400/80 = 5

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A merchant purchases a wrist watch for Rs. 450 and fixes its list price in such a way that after allowing a discount of 10%, he earns a profit of 20%. Then the list price (in rupees) of the wrist watch is

A500

B750

C600

D800

Answer: Option C

Explanation:

If the marked price of the wrist watch be Rs. x then
x*90/100 = 450*120/100 = 540

x=540*100/90 = Rs. 600

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A reduction of 10% in the price of tea enables a dealer to purchase 25 kg more tea for Rs.22500. What la the reduced price per kg or tea ?

ARs. 70 / Kg

BRs. 80 / Kg

CRs. 90 / Kg

DRs. 100 / Kg

Answer: Option C

Explanation:

Let the original price of tea be Rs. x/kg

New price = Rs.(9x/10)/kg

so 22500/)9x/10) - 22500/x = 25
=> 22500 (10/9x - 1/x) = 25
=> 2250(10-9)/9x = 25=> 2250 = 25 * 9x
=> x = 22500/(25*9) = 100
so New price = (9/10 * 10) = Rs 90 per kg.

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It cost a college Rs.0.70 a copy to produce a Programme for the homecoming football game. If Rs.15,000/- was received for advertisements in the programme, how many copies at Rs.0.50 a copy must be sold to make a profit of Rs.8000/- ?

A30000

B34000

C35000

D25000

Answer: Option C

Explanation:

Copy is sold at loss =0.70-0.50=0.20
Even then a profit of 8000 is made.
Let N be no. of copies.
Therefore,
(N*0.2)+8000=15000
N*0.20=7000
N=35000
So 35000 copies sold

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The cost of four dozen proof machine ribbons and five dozen accounting machine ribbons was Rs.160/-. If one dozen accounting machine ribbons cost Rs.20/-, what is the cost of a dozen proof machine ribbons?

A15

B60

C10

D16

Answer: Option A

Explanation:

Lets take proof machine as pm & accounting machine as am.
so, here 4 pm + 5 am=160
given that 1 am=Rs.20 then 5 am=20 x 5=100
substitute this in the above eqn,
now, 4 pm + 100 = 160
4 pm=160 -100
4 pm=60
1 pm=60/4=15

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A tape manufacturer reduces the price of his heavy duty tape from Rs.30/- to Rs.28/- a reel and the price of a regular tape from Rs.24/- to Rs.23/- a reel. A computing center normally spends Rs.1440/- a month for tapes and 3/4 of this is for heavy duty tapes. How much will they save a month under the new prices?

A87

B140

C122

D72

Answer: Option A

Explanation:

Hd tape = (3/4)*1440 = 1080
Hd tape + Reg tape = 1440
(3/4)*1440 + Reg tape = 1440
SO, Reg tape = 360
HD tape = 1080
no. of reg tape = 360/24 = 15
no. of HD tape = 1080/30 = 36
For new price, Hd tape savings = (30-28) = 2
Reg tape savings = 24-23 = 1
Total savings = (36*2)+(15*1) = 87

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A shopkeeper marked a suit at Rs.400. He sold it after allowing a discount, and still made at a profit of 25%. At what percentage above its cost price did he marked the suit, if he sold it for Rs.320?

A50%

B66.67%

C62.50%

D56.25%

Answer: Option D

Explanation:

Solution: There are two selling prices equation equating them we will get the answer.

S.P on obtaining profit= S.P. on getting discount  ( let the C.P BE x)

125x/100 = 80/100 * 400

solving the equation we get x= 256 Rs that is the cost price. So Marked Price was 400

Therefore (400-256)/256 *100%  =56.25%

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The price of an article was increased by p%. Later the new price was decreased by p%. If the latest price was Rs.1, the original price was:

A(1-p^2)/100

BRs. 1

C[10000/(10000-p^2)

Dsqr [(1-p^2)/100]

Answer: Option C

Explanation:

NetProfit=p%-p% -pXp/100=p2/100
=>original+original*Net_Profit=RS 1
=>Original=[10000/(10000-p^2)]

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Radha bought a watch for Rs. 144 and got a percentage of profit equal to the cost price of the watch. What is the cost price of the watch?

ARs. 72

BRs. 80

CRs. 78

DRs. 90

Answer: Option B

Explanation:

SP=144
Lets assume cost price of watch= Rs. x
so profit %=x
C.P.= (100/(100+gain%))*S.P. -----(formula to get CP)
x=(100/100+x) *144
=> x^2+100x=14400
=> x^2+180x-80x-14400=0
=> (x+180) (x-80)=0
=> x=-180
=> x=80

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5 tables and 10 chairs were sold for 20000.15%gain for table,10%loss on chair.overall profit Rs 750.the CP of table is

ARs. 2140

BRs. 2240

CRs. 3000

DRs. 2500

Answer: Option A

Explanation:

Lets assume cost of table is X and cost of chair is Y.
sold price is 20000 and profit is 750 .
so cost for both is 19250.
=> 5X+10Y=19250 ------------ (1)

=> 5*(115/100)X + 10* (90/100)Y =20000 ------- (2)

By solving both eq.
We get X=2140

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