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Problems on Trains Questions

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1 / 14

Choose the correct option.

A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?


A120 metres

B180 metres

C324 metres

D150 metres

Answer: Option D

Explanation:

Length of the train = (Speed x Time) =50/3 x 9 m = 150 m.

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A 120 m long train is running at 72 Kmph. How much time will it take to cross a man standing on the platform?


A6 sec

B2.5 sec

C5 sec

D12 sec

Answer: Option A

Explanation:

Formula Used: Time = ( Distance / Speed)



As all the option given in sec., so convert the train speed (Kmph) in to mps multiply by 5/18



speed (mps) = 72 * 5/18 = 20 mps



Time = (120 / 20) sec = 6 sec



Time take by Train = 6 Sec.

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Two trains 400m and 300m long run at the speeds of 50 kmph and 40kmph respectively in opposite Directions on parallel tracks. The time taken to cross each other?


A20 sec

B28 secs

C25 sec

D24 sec

ENone of these

Answer: Option B

Explanation:

Trains are running in opposite Direction:
So need to find Length of two Trains = 300m + 400m = 700m

and Total Speed = 40 Kmph + 50 Kmph (Opposite Direction)
= 90 Kmph
so speed (m/sec) = 90 * 5/18 m/sec = 25 m/sec
Formula Used: Time = Distance/Speed

Time = 700/ 25 sec
Time = 28 Sec

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A train overtakes two persons who are walking in the same direction in which the train is going, at the rate of 2 kmph and 4 kmph and passes them completely in 19 and 20 seconds respectively. The length of the train is:


A245 m

B211.1 m

C210 m

D213 m

Answer: Option B

Explanation:

Convert the persons Speed in m/sec
2 kmph = (2 x 5/18) m/sec = 5/9 m/sec.
4 kmph = (4 x 5/18 m/sec = 10/9 m/sec.

Let the length of the train be x meters and its speed by y m/sec.
Relative speed in respect to both person (y - 5/9) and (y - 10/9)

Formula Used: Time = Distance / speed
so x / (y - 5/9) = 19 ---- (1)
and x / (y - 10/9) = 20 ---- (2)
9x = 19 (9y - 5) ----- (1)
9x = 20 (9y - 10) ------(2)
find the value of x and y
19 (9y - 5) = 20(9y - 10)
171 y - 95 = 180 y -200 => 9y = 105 => y = 105/9 = 35/3

Now find the value fo x by above any equations
9x = 171 *35/3 - 95 = 57 *35 - 95
9x = 1900 => x = 211.1 meter

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Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?


A10 a.m.

B11 a.m.

C10 p.m.

D11 p.m.

Answer: Option A

Explanation:

Let they meet x hours after 7 a.m.

Distance covered by A in x hours = 20x km.

Distance covered by B in (x - 1) hours = 25(x - 1) km.

So Total Distance
=> 20x + 25(x - 1) = 110
=> 45x - 25 = 110 => 45x = 135
=> x = 3.
As They meet x hrs after 7 a.m. so they meet at 10 a.m.

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Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train?


A27 m

B33 m

C27 7/9 m

D23 4/9 m

Answer: Option C

Explanation:

As train are running in same direction
so Relative speed = (40 - 20) km/hr = 20 km/hr
= ( 20 x 5/18 ) m/sec = 50/9 m/sec.
Formula Used: Distance = Speed * Time
Now Length of Faster Train = ( 50/9 x 5 ) m = 250/9 m
= 27 7/9 m

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A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train?


A69.5 km/hr

B70 km/hr

C79 km/hr

D79.2 km/hr

Answer: Option D

Explanation:

Let the length of the train be x meters and its speed by y m/sec.

Then, x/y = 8 => x = 8y ----------- (1)

As per the question total distance = (x + 264) meters.
(x + 264)/20 = y
Put the value of x from equation 1.
=> 8y + 264 = 20y
=> y = 22.

Therefore Speed = 22 m/sec = ( 22 x 18 /5) km/hr = 79.2 km/hr.

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The two trains of lengths 400m, 600m respectively, running at same directions. The faster train can Cross the slower train in 180sec, the speed of the slower train is 48km. then find the speed of the Faster train?


A58 Kmph

B78 kmph

C55 Kmph

D68 Kmph

Answer: Option D

Explanation:

Length of the two trains = 600m + 400m = 1000m



Let's Assume Speed of the first train = x kmph

Speed of the second train= 48 Kmph

So Relative Speed = (x - 48) kmph =((x -48) * 5/18) m/sec

1000/((x -48) * 5/18) = 180

18000/(5x - 240) = 180

100 = 5X - 240

=> 5x = 340 => x = 68 kmph

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A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?


A120 m

B240 m

C300 m

DNone of these

Answer: Option B

Explanation:

Speed = (54 x 5 /18) m/sec = 15 m/sec.

Length of the train = (15 x 20)m = 300 m.

Let the length of the platform be x metres.

So (x + 300)/36 = 15
x + 300 = 540
=> x = 240 m.

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A train traveling at 72 kmph crosses a platform in 30 seconds and a man standing on the platform in 18 seconds. What is the length of the platform in meters?


A300 meters.

B550 meters.

C340 meters.

D240 meters.

Answer: Option D

Explanation:

72kmph= 20m/sec
Length of the train can be found by taking the time in which the train crosses the man= 20* 18=360m
Let length of platform be x
So 20*30= (360+x)
Solving we get x= 240m

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