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Problems on Trains Questions

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Two trains are travelling between two stations at a constant speed of 25kmph.The stations are 50km apart .A bird traveling at 100kmph starts its flight along with one train and travels in the same direction until it meets the other train. It changes its direction and goes in the reverse direction until it meets the initial train. Find the distance travelled by the bird before the two trains collide.


A100 kms

B25 kms

C250 kms

D75 kms

Answer: Option A

Explanation:

Train will collide after 1 hour because,both trains speed are same i.e 25km/hr.
Distance travelled by bird in 1hr = 1*100= 100 kms.

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A train covers a distance between station A and station B in 45 min. If the speed of the train is reduced by 5 km/hr,then the same distance is covered in 48 min. what is the distance between the stations A and B?


A64

B55

C80

D60

Answer: Option D

Explanation:

Distance between the stations A and B = x and speed of train = y km/hr.

x = y * 45/60 => x = y*3/4 --------------- (1)

speed reduce by 5 km/hr. so new speed of train is (y-5) km/hr.

x = (y-5) * 48/60 => x = (y-5) 4/5 ---------------- (2)

By solving eq. (1) and (2)

y*3/4 = (y-5) * 4/5
=> y = 80 kmph.
x = 60 km.

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A train traveling at 72 kmph crosses a platform in 30 seconds and a man standing on the platform in 18 seconds. What is the length of the platform in meters?


A300 meters.

B550 meters.

C340 meters.

D240 meters.

Answer: Option D

Explanation:

72kmph= 20m/sec
Length of the train can be found by taking the time in which the train crosses the man= 20* 18=360m
Let length of platform be x
So 20*30= (360+x)
Solving we get x= 240m

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Two trains 200mts and 150mts are running on the parallel rails at this rate of 40km/hr and 45km/hr.In how much time will they cross each other if they are running in the same direction.


A200 sec

B250 sec

C202 sec

D252 sec

Answer: Option D

Explanation:

Relative speed=45-40=5km/hr=25/18 mt/sec
Total distance covered =sum of lengths of trains =350mts.
So, time taken =350*18/25=252sec.

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A man is standing on a railway bridge which is 180m long. He finds that a train crosses the bridge in 20seconds but himself in 8 seconds. Find the length of the train and its speed.


ALength of train=120m Speed of train=54 kmph

BLength of train= 54 m Speed of train=120kmph

CLength of train=120m Speed of train=60 kmph

DLength of train=140m Speed of train=54 kmph

Answer: Option A

Explanation:

Lets assume the length of the train = x meters
Then, the train covers x meters in 8 seconds and (x + 180) meters in 20 seconds.
So, x/8 = (x+180)/20 <=> 20x = 8(x+180) <=> x = 120
Therefore Length of the train = 120m
Speed of the train = 120/8 m/sec = 15 m/sec = (15 * 18/5) kmph = 54kmph

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Train A traveling at 60 km/hr leaves Mumbai for Delhi at 6 P.M. Train B traveling at 90 km/hr also leaves Mumbai for Delhi at 9 P.M. Train C leaves Delhi for Mumbai at 9 P.M. If all three trains meet at the same time between Mumbai and Delhi, what is the speed of Train C if the distance between Delhi and Mumbai is 1260 kms?


A20 km/hr.

B120 km/hr.

C80 km/hr.

D110 km/hr.

Answer: Option B

Explanation:

All three trains meet at the same time between Delhi and Mumbai. Which means Train A and
Train B are at the same point at that time. This will happen when Train B is overtaking Train A.

Train A starts 3 hours before Train B. Therefore, by the time Train B leaves Mumbai, Train A has
covered 3 * 60 = 180 kms.

The relative speed between Train A and Train B = 90 - 60 = 30 kmph. Therefore, Train B will
overtake Train A in 180/30 = 6 hours from the time Train B leaves Mumbai. That is at 3 A.M, Train
B will overtake Train A. The point between Mumbai and Delhi at which Train B overtakes Train
A will be 6*90=540 kms from Mumbai.

Train C will also be at that point at 3 A.M while Train B is overtaking Train A. And Train C
would have travelled 1260-540 = 720 kms in these 6 hours. Therefore, the speed of Train C = 720/6
= 120 km/hr.

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A train running at 54 kmph takes 20 seconds to pass a platform. Next it takes 12 sec. to pass a man walking at 6 kmph in the same direction in which the train is going. Find the length of the train and the length of the platform.


ATrain length = 140 m. Platform length = 160 m.

BTrain length = 260 m. Platform length = 240 m.

CTrain length = 160 m. Platform length = 140 m.

DTrain length = 120 m. Platform length = 160 m.

Answer: Option C

Explanation:

Lets assume the length of the train = x meters
and length of the platform = y meters.
Speed of the train relative to man =(54-6)kmph = 48 kmph.
=> (48*5/18) m/sec =40/3 m/sec.
In passing a man, the train covers its own length with relative speed.
So, length of the train=(Relative speed *Time)
=(40/3 * 12) m =160 m.
Also, speed of the train=(54 * 5/18) m/sec=15 m/sec.

Therefore, (x+y/2xy)=20 => (x+y)=300 or y =(300-160)+ m=140 m.
So, Length of the platform=140 m.

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Two trains A and B start simultaneously from stations X and Y towards each other respectively. After meeting at a point between X and Y, train A reaches station Y in 9 hours and train B reaches station X in 4 hours from the time they have met each other. If the speed of train A is 36 km/hr, what is the speed of train B?


A44 km/hr

B24 km/hr

C54 km/hr

D34 km/hr

Answer: Option C

Explanation:

Speed of train B = 3/2 * Speed of train A = 3/2* 36 = 54 km/hr

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A train running at certain speed crosses a stationary engine in 20 seconds. To find out the speed of the train, which of the following information is necessary?


AOnly the length of the train

BOnly the length of the engine

CEither the length of the train or the length of the engine

DBoth the length of the train and the length of the engine

Answer: Option D

Explanation:

Since the sum of the length of the train and the length of the engine is needed, so both the lengths must be known.

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A train 110 m long is running with a speed of 60 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going?


A6 sec.

B8 sec.

C10 sec

D6 1/2 sec.

Answer: Option A

Explanation:

Relative speed = (60 + 6) = 66 km/hr.
converting km/hr to m/sec.
=> (66 * 5/18) = 55/3 m/sec.
Time required to pass the men = 110 * 3/55 = 6 sec.

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