The two trains of lengths 400m, 600m respectively, running at same directions. The faster train can Cross the slower train in 180sec, the speed of the slower train is 48km. then find the speed of the Faster train?
Two trains each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is
speed of the faster train = 2x m/sec.
Relative speed of train = (x + 2x) m/sec = 3x m/sec.
Total distance = (100 + 100)m = 200m
3x = 200/8
=> 24x = 200 => x = 25/3
So speed of the faster train = 2 * 25/3 m/sec
= 50/3 m/sec
= 50/3 * 18/5 = 60 km/hr.
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Two trains start from stations A and B spaced 50 kms apart at the same time and speed. As the trains start, a bird flies from one train towards the other and on reaching the second train, it flies back to the first train. This is repeated till the trains collide. If the speed of the trains is 25 km/h and that of the bird is 100 km/h. How much did the bird travel till the collision.
Since the trains is travelling at 25 kmph, at each other, the relative speed is 50 kmph.
Speed = 50 kmph
Distance = 50 km
Time to collision = distance / speed = 1 hr
Speed of bird = 100 kmph
Time flying = 1 hr (the bird is flying till the trains collide)
Distance travelled = speed time = 100 km
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A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Formula for converting from km/hr to m/s: X km/hr = X *( 5/18) m/s.
so Speed = 45 * 5/18 m/sec = 25/2 m/sec.
Total distance to be covered = (360 + 140) m = 500 m.
Required time = 500 * 2/25 sec = 40 sec.
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Train A starts from Meerut at 12:00 pm & reach at Delhi on 2:30 pm & train B starts from Delhi at 12:15pm and reach at Meerut on 2:15pm. So, when both trains crosses each other ?
Lets assume Distance between Meerut & Delhi = x kms
Trains meet t hours after 12.15pm
Speed of A= x/150 kms/min.
speed of B = x/120 kms/min.
Distance covered by A in (t+15) min + Distance covered by B in y hours
=x (x/150)* (y+15) + (x/120) * y = x
=> 1/150 * (y+150) + 1/120 *y = 1
=> y/150 + 1/10 + y/120 = 1
=> Y=60
trains meet at (12.15 + 60) = 1:15 PM
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Two trains for Palwal leave Kanpur at 10 a.m and 10:30 am and travel at the speeds of 60 Kmph and 75 Kmph respectively. After how many kilometers from Kanpur will the two trains be together?
Lets assume two train meet at X km distance from kanpur.
Given First train speed 60 kmph, second train speed 75 kmph
Second train start after 1/2 hrs.
Time taken by first train to cover X km = x/60 h
Time taken by 2nd train to cover X km=x/75 h
Now, x/60 - x/75=1/2
so x=150.
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Two trains whose respective lengths are 240 m and 360 m cross each other in 30 seconds when they are moving in opposite directions and in 1 minute 40 seconds when they are moving in the same direction. What is the speed of the faster train (kmph) ?
Lets assume Trains speed are S1 m/sec and S2 m/sec respectively.
In opposite Direction
------------------------
Then 30 = (240 + 360)/(S1+S2).
=> S1 + S2 = 20 ------------(1)
In same Direction:
their relative speed = (S1-S2) {S1>S1}
so (S1-S2) = 600/100
=> S1-S2=6.------(2)
By solving the both eq. (1) (2) we get,
S1=13 and S2=7
So faster train speed = 13 * (18/5) km/hr. = 46.8 km/hr.
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Two trains A and B start simultaneously in the opposite direction from two points A and B arrive at their destinations 9 and 4 hours respectively after their meeting each other. At what rate dose the second train B travels if the first train travels at 80 km per hour.
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