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Problems on Trains Questions

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Choose the correct option.

A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train?


A69.5 km/hr

B70 km/hr

C79 km/hr

D79.2 km/hr

Answer: Option D

Explanation:

Let the length of the train be x meters and its speed by y m/sec.

Then, x/y = 8 => x = 8y ----------- (1)

As per the question total distance = (x + 264) meters.
(x + 264)/20 = y
Put the value of x from equation 1.
=> 8y + 264 = 20y
=> y = 22.

Therefore Speed = 22 m/sec = ( 22 x 18 /5) km/hr = 79.2 km/hr.

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The two trains of lengths 400m, 600m respectively, running at same directions. The faster train can Cross the slower train in 180sec, the speed of the slower train is 48km. then find the speed of the Faster train?


A58 Kmph

B78 kmph

C55 Kmph

D68 Kmph

Answer: Option D

Explanation:

Length of the two trains = 600m + 400m = 1000m



Let's Assume Speed of the first train = x kmph

Speed of the second train= 48 Kmph

So Relative Speed = (x - 48) kmph =((x -48) * 5/18) m/sec

1000/((x -48) * 5/18) = 180

18000/(5x - 240) = 180

100 = 5X - 240

=> 5x = 340 => x = 68 kmph

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Choose the correct option.

Two trains each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is


A30 km /hr

B60 km /hr

C30 km /hr

D30 km /hr

Answer: Option B

Explanation:

speed of the faster train = 2x m/sec.
Relative speed of train = (x + 2x) m/sec = 3x m/sec.
Total distance = (100 + 100)m = 200m
3x = 200/8
=> 24x = 200 => x = 25/3
So speed of the faster train = 2 * 25/3 m/sec
= 50/3 m/sec
= 50/3 * 18/5 = 60 km/hr.

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Two trains start from stations A and B spaced 50 kms apart at the same time and speed. As the trains start, a bird flies from one train towards the other and on reaching the second train, it flies back to the first train. This is repeated till the trains collide. If the speed of the trains is 25 km/h and that of the bird is 100 km/h. How much did the bird travel till the collision.


A50 kms

B60 kms

C100 kms

D80 kms

Answer: Option C

Explanation:

Since the trains is travelling at 25 kmph, at each other, the relative speed is 50 kmph.
Speed = 50 kmph
Distance = 50 km
Time to collision = distance / speed = 1 hr
Speed of bird = 100 kmph
Time flying = 1 hr (the bird is flying till the trains collide)
Distance travelled = speed time = 100 km

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A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?


A120 m

B240 m

C300 m

DNone of these

Answer: Option B

Explanation:

Speed = (54 x 5 /18) m/sec = 15 m/sec.

Length of the train = (15 x 20)m = 300 m.

Let the length of the platform be x metres.

So (x + 300)/36 = 15
x + 300 = 540
=> x = 240 m.

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A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?


A40 sec

B42 sec

C45 sec

D48 sec

Answer: Option A

Explanation:

Formula for converting from km/hr to m/s: X km/hr = X *( 5/18) m/s.
so Speed = 45 * 5/18 m/sec = 25/2 m/sec.

Total distance to be covered = (360 + 140) m = 500 m.

Required time = 500 * 2/25 sec = 40 sec.

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Train A starts from Meerut at 12:00 pm & reach at Delhi on 2:30 pm & train B starts from Delhi at 12:15pm and reach at Meerut on 2:15pm. So, when both trains crosses each other ?


A2:00 PM

B1.30 pm

C1.15 pm

D1:00 PM

Answer: Option C

Explanation:

Lets assume Distance between Meerut & Delhi = x kms
Trains meet t hours after 12.15pm
Speed of A= x/150 kms/min.
speed of B = x/120 kms/min.
Distance covered by A in (t+15) min + Distance covered by B in y hours
=x (x/150)* (y+15) + (x/120) * y = x
=> 1/150 * (y+150) + 1/120 *y = 1
=> y/150 + 1/10 + y/120 = 1
=> Y=60

trains meet at (12.15 + 60) = 1:15 PM

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Two trains for Palwal leave Kanpur at 10 a.m and 10:30 am and travel at the speeds of 60 Kmph and 75 Kmph respectively. After how many kilometers from Kanpur will the two trains be together?


A250 km

B150 km

C100 km

D200 km

Answer: Option B

Explanation:

Lets assume two train meet at X km distance from kanpur.
Given First train speed 60 kmph, second train speed 75 kmph
Second train start after 1/2 hrs.
Time taken by first train to cover X km = x/60 h
Time taken by 2nd train to cover X km=x/75 h
Now, x/60 - x/75=1/2
so x=150.

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Two trains whose respective lengths are 240 m and 360 m cross each other in 30 seconds when they are moving in opposite directions and in 1 minute 40 seconds when they are moving in the same direction. What is the speed of the faster train (kmph) ?


A46

B11 1/2

C46.8

D30

Answer: Option C

Explanation:

Lets assume Trains speed are S1 m/sec and S2 m/sec respectively.

In opposite Direction
------------------------
Then 30 = (240 + 360)/(S1+S2).
=> S1 + S2 = 20 ------------(1)

In same Direction:
their relative speed = (S1-S2) {S1>S1}
so (S1-S2) = 600/100
=> S1-S2=6.------(2)
By solving the both eq. (1) (2) we get,
S1=13 and S2=7
So faster train speed = 13 * (18/5) km/hr. = 46.8 km/hr.

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Two trains A and B start simultaneously in the opposite direction from two points A and B arrive at their destinations 9 and 4 hours respectively after their meeting each other. At what rate dose the second train B travels if the first train travels at 80 km per hour.


A110 km/h

B100 km/h

C120 km/h

D90 km/h

Answer: Option C

Explanation:

(A's speed) : (B's speed) = ?9:?4.
=> B's speed = 80* ?9/?4.
=> 120km/hr.

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