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# Problems on Numbers Questions

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The sum of three from the four numbers A, B, C, D are 4024, 4087, 4524 and 4573. What is the largest of the numbers A, B, C, D?

A1712

B1650

C1164

D1211

Answer: Option A

Explanation:

a+b+c=4024
b+c+d= 4087
a+c+d=4524
a+b+d=4573
Combining all we get 3(a+b+c+d) = 17208
=> a + b + c +d = 3736
Now we find individual values. a = 1649, b = 1212, c = 1163, d = 1712. So maximum value is 1712.

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In a city there are few engineering, MBA and CA candidates. Sum of four times the engineering, three times the MBA and 5 times CA candidates is 3650. Also three times CA is equal to two times MBA and three times engineering is equal to two times CA. In total how many MBA candidates are there in the city?

A200

B300

C450

D400

Answer: Option C

Explanation:

Lets assume number of engg = e
number of Mba = m
and Number of CA = c
4e+3m+5c=3650
3c=2m m=3c/2
3e=2c e=2c/3 ------------- (1)
put the value in the above eq. (1)
4*2c/3+3*3c/2+5c=3650
c=300
m=3c/2
m=450

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Which of the following numbers must be added to 5678 to give a remainder of 35 when divided by 460?

A955

B980

C797

D618

Answer: Option C

Explanation:

5678 - 35 + (one of the answer option) should be divisible by 460. Only option C satisfies.

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A number when successively divided by 5.3.2 gives remainders of 0, 2 and 1 respectively in that order. What will be the remainder when the same number is divided successively by 2, 3 and 5 in that order?

A2, 1, 3

B4, 1, 2

C1, 0, 4

D4, 3, 2

Answer: Option C

Explanation:

Let the number = N
Now N = 5K
K = 3L + 2
L = 2M + 1
K = 3(2M + 1) + 2 = 6M + 5
N = 5(6M + 5) = 30 M + 25
For M = 0 we get the least number as 25.
Now when 25 is divided by 2, we get 12 as quotient and 1 as remainder.
When 12 is divided by 3 we get 4 as quotient, and 0 as remainder. When 4 is divided by 5 we gt 4 as remainder.

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At a garden site, 16 Mango trees,24 banyan trees and 28 Guava trees are to be planted in certain no of rows in such a way that each row has equal no of trees of the same species. what is the minimum number of rows that are required for this purpose

A17

B11

C18

D19

Answer: Option A

Explanation:

4 mango trees in 4 rows
4 banyan trees in 6 rows
4 guava trees in 7 rows
Total = 4+6+7=17

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The arithmetic mean of three numbers is 55. if the largest number is 2.5 times the smallest number and the remaining number is twice the smallest number, what is te largest of the three numbers.

A55

B165

C70

D75

ENone of these

Answer: Option D

Explanation:

Here is no explanation for this answer

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A number when divided by D leaves a remainder of 8 and when divided by 3D leaves a remainder of 21. What is the remainder left, when twice the number is divided by 3D?

A13

B3

C42

DCannot be determined

Answer: Option B

Explanation:

Let's number is N
so N = DX + 8 -------(1)
N = 3DY + 21 ---------(2)

From Eq. 1 & 2
=> D(X-3Y) = 13
"13" is prime number, and its factors will be 1 and 13 only
=> X-3Y must be 1
Let X = 4 and Y = 1, D=13
So, N = 60
Remainder Left = 2N / 3D
= 120 / 39 = 3

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The shopkeeper charged 12 rupees for a bunch of chocolate. but i bargained to shopkeeper and got two extra ones, and that made them cost one rupee for dozen less then first asking price. How many chocolates I received in 12 rupees ?

A10

B16

C14

D18

Answer: Option B

Explanation:

n chocolates = Rs 12
Price per dozen = 144/n
I got n+2 in rs 12 = > Price per dozen = 144/n+2
144/n+2 = 144/n - 1
=> n = 16

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The sum of the four consecutive two digit odd numbers, when divided by 10, becomes a perfect square. Which of the following can be one of these four numbers?

A31

B25

C41

D67

Answer: Option C

Explanation:

Let the numbers are 2a +1, 2a + 3, 2a + 5, 2a + 7 and their sum = 8a + 16
Given that if this sum is divided by 10, results in a perfect square.
So, (8a+16)/10 = k^2.
=> a = (10k^2?16) /8
=> a=[ 5(k^2)/4 ]?2
As k^2 is a perfect square and has to be divided by 4, only even numbers should be considered for k.
For k = 2, we get, a = 3, but 2a + 1 is not a two digit number.
For k = 4, a = 18 for which the given condition is satisfying.
So the numbers are 37, 39, 41, 43.
For k = 6, a = 43. The number are 87, 89, 91, 93.

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What is the greatest power of 143 which can divide exactly 125!

A12

B11

C8

D9

Answer: Option D

Explanation:

Here is no explanation for this answer

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