21 / 72
When Rajeev was born, his father was 32 years older than his brother and his mother was 25 years older than his sister. If Rajeev's brother is 6 years older than Rajeev and his mother is 3 years younger than his father, how old was Rajeev's sister when Rajeev was born?
A15 Years
B7 Years
C17 Years
D10 Years
ENone of these
Answer: Option D
Explanation:Rajeev age = 0,
Father age = 32 + Brother age,
Mother age = 25 + Sister age = Father age -3
Brother age = 6 + Rajeev age = 6 + 0 = 6
Father age = 32 + 6 = 38
Mother age = 38 - 3 =35
Sister age = 35 - 25 = 10.
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22 / 72
The ages of A and B are in the ratio of 8:5.If the sum of their ages is 39 years,what will be the ratio of their ages after 9 years?
A5:08
B10:11
C11:08
D8:11
Answer: Option C
Explanation:As per the formula( If the given ages in a ratio a : b then age will be ax and bx.)
so A and B age will be 8x and 5x respectively.
=> 8x+5x = 39 => 13x=39
=> x=39/13=3
A nad B age will be 25 and 15 respectively.
After 9 yr,
A and B age will be 33 and 24.
So, the ratio of their ages A:B::11:8
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23 / 72
The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be:
A12 years
B14 years
C18 years
D20 years
Answer: Option D
Explanation:Let the present ages of son and father be x and (60 -x) years respectively.
Then, (60 - x) - 6 = 5(x - 6)
=> 54 - x = 5x - 30
=> 6x = 84
=> x = 14.
Son's age after 6 years = (x+ 6) = 20 years..
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24 / 72
Ten years ago, chandrawathi's mother was four times older than her daughter. After 10years,the mother will be twice older than daughter. The present age of Chandrawathi is:
A20 years
B15 years
C25 years
DNone of these
Answer: Option A
Explanation:Let Chandrawathi's age 10 years ago be x years.
So Her mother's age 10 years ago = 4x
=> (4x+10)+10=2(x+10+10)
=> x=10
So, Present age of Chandrawathi = (x+10) = 20 years
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25 / 72
Diophantus passed one sixth of his life in childhood, one twelfth in youth, and one seventh more as a bachelor; five years after his marriage a son was born who died four years before his father at half his final age. How old is Diophantus?
A44 years
B74 years
C64 years
D84 years
Answer: Option D
Explanation:x/6 + x/12 + x/7 + 5 + x/2 + 4 = x
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26 / 72
Fathers age is 5 times his son's age. 4 years back the father was 9 times older than son. Find the fathers present age.
A40 years.
B20 years.
C45 years.
D50 years.
Answer: Option A
Explanation:lets assume son age=x
fathers age=5x
4 years back, so (x-4)=(5x-4)
then father was 9 times older than son so, 9(x-4)=(5x-4).....(1)
solving eqn (1), x=8
and fathers age =8*5=40 years
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A father is 30 years older than his son however he will be only thrice as old as the son after 5 years what is father's present age ?
A40 yrs
B30 yrs
C50 yrs
DNone of these
Answer: Option A
Explanation:Lets assume son's age = x
So, father's age = x + 30
After 5 years:
Son's age = x + 5
Father's age = x + 35
In 5 years the father is thrice as old as his son so:
3(x + 5) = x + 35
x = 10
So, current father's age = 40 Years.
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28 / 72
The ratio of the ages of Swati and Varun is 2 : 5, After 8 years, their ages will be in the ratio of 1 : 2. The difference in their present ages (in years) is?
A24
B29
C26
D32
Answer: Option A
Explanation:Let Swati's age = 2X and Varun's age = 5X
(2X + 8)/(5X + 8) = 1/2 => X = 8
Swati's age = 16 years
and Varun's age = 40 years
Difference of their ages = 24 years.
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29 / 72
A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present?
A32 years
B46 years
C40 years
D44 years
Answer: Option C
Explanation:Lets assume mother's present age = x years
So, the person's present age = 2/5 x years
As per the question:
=>(2/5 x + 8) = 1/2 (x + 8)
=> 2(2x + 40) = 5(x + 8)
=> x = 40
So Mother present age = 40 years.
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When you reverse the digits of age of father you will get the age of son. one year ago the age of father was twice that of son's age. What are the current ages of father and son?
A73 & 37
B73 & 45
C65 & 37
DNone of these
Answer: Option A
Explanation:When you reverse the digits of age of father you will get the age of son.
10x y = father's age
10y x = son's age
:
one year ago the age of father was twice that of son's age.
10x y - 1 = 2(10y x - 1)
10x y - 1 = 20y 2x - 2
10x - 2x = 20y - y - 2 1
8x = 19y - 1
x = 19/8y - 1/8
Only one set of single digit integers will satisfy this equation
y = 3; x = 7
Current ages of father and son
Dad is 73, son is 37
Check one year ago
Dad is 72, son is 36, half Dad's age
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