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A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?
A10/21
B11/21
C2/7
D5/7
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Answer: 10/21
Solution: 2 red, 3 green, and 2 blue balls are there. So the probability of getting no blue ball is not selecting any blue ball among the two chosen balls hence 5C2.
5C2/7C2 = 10/21.
7C2 because we can select any 2 balls from 7 balls in that number of ways.
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Answer: 10/21
Solution: 2 red, 3 green, and 2 blue balls are there. So the probability of getting no blue ball is not selecting any blue ball among the two chosen balls hence 5C2.
5C2/7C2 = 10/21.
7C2 because we can select any 2 balls from 7 balls in that number of ways.
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