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# Probability Questions

Home > Quantitative Aptitude > Probability > General Questions
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Out of 40 consecutive integers, two are chosen at random. Find the probability that their sum is odd?

A21/40

B19/39

C21/39

D20/39

Answer: Option D

Explanation:

Solution: To get the sum of 2 integers as odd one must be even and the other one must be odd.

In 40 consecutive integers, 20 are even and 20 are odd.

Hence.. (20C1*20C1)/40C2= 20/39

20C1= TO SELECT ONE ODD NUMBER FROM 20 NUMBERS.

20C1= TO SELECT ONE EVEN NUMBER FROM 20 NUMBERS.

40C2= TO SELECT TWO RANDOM NUMBERS FROM 40 NUMBERS.

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An unbiased cubic die is thrown.What is the probabiltiy of getting a multiple of 3 or 4?

A1/9

B1/12

C1/2

D3/4

Answer: Option C

Explanation:

Answer: 1/2

Solution: Total numbers in a die=6

Probability of getting a (multiple of 3) = 2/6 = 1/3

Probability of getting a (multiple of 4) = 1/6

Probability of getting a (multiple of 3 or 4) = 1/3 1/6 = 1/2

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When 4 dice are thrown, what is the probability that the same number appears on each of them?

A1/36

B1/18

C1/216

D1/5

Answer: Option C

Explanation:

When 4 dice are thrown simultaneously, then the total number of possible outcomes is 64 = 1296.

The chances that all the dice show same number (1,1,1,1), (2,2,2,2), (3,3,3,3), (4,4,4,4), (5,5,5,5), (6,6,6,6)} is 6.

Hence, the required Probability = Event/ Sample space = 6/64 = 1/63 =
1/216.

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3 dice are rolled. what is the probability of getting sum as 13?

A21/216

B1/216

C15/216

D1/36

Answer: Option A

Explanation:

(6,6,1)=3 ways
(6,5,2)=6 ways
(5,5,3)=3 ways
(4,4,5)=3 ways
(6,4,3)=6 ways

Hence total ways = 21
So, probability = 21/(6*6*6) = 21/216

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Two cards are drawn at random from an ordinary pack of cards . Find the probability that they will consist of a king

A1/52

B1/1326

C1/221

DNone of these

Answer: Option C

Explanation:

Sample space is 50C2 which is equal to 1326. Events of getting 2 kings out of 4 is 4C2 which is equals to 6. So probability of getting two kings is 6/1326 = 1/221.

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A man can hit a target once in 3 shots. If he fires 3 shots in succession, find the probability that he will hit his target.

A2/9

B19/27

C5/9

D1/27

Answer: Option B

Explanation:

Probability of hitting the target= (1- probability of not hitting the target)
if he hits once every 3 balls,
probability of hitting = 1/3,
So, probability of not hitting=2/3
probability of not hitting the target all three times= (2/3)* (2/3)* (2/3)
Probability of hitting target = 1 -(2/3)^3 = 19/27

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Thangam and Pandiyamma go for an interview for two vacancies. The probability for the selection of Thangam is 1/3 and whereas the probability for the selection of Pandiyamma is 1/5. What is the probability that none of them are selected?

A3/5

B7/12

C8/15

D1/5

Answer: Option C

Explanation:

Probability of thangam being selected = 1/3
Probability of thangam not being selected = (1-1/3) = 2/3
Probability of pandiyamma being selected = 1/5
Probability of pandiyamma not being selected = (1-1/5) = 4/5

Probability that both are not selected = 2/3 * 4/5 = 8/15

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100 students appeared for two different examinations 60 passed the first, 50 the second and 30 both the examinations. Find the probability that a student selected at random failed in both the examination

A5/6

B1/5

C1/7

D5/7

Answer: Option B

Explanation:

60+50-30=80
100-80=20
20/100=1/5.

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A bag contains 8 white balls, and 3 blue balls. Another bag contains 7 white, and 4 blue balls. What is the probability of getting blue ball?

A3/7

B7/22

C7/25

D7/15

Answer: Option B

Explanation:

First we have to select a bag and then we will draw a ball. Probability of selection of both bags is equal =1/2
Now probability of blue ball taken from first bag = ( 1/2) x (3/11) and probability of blue ball taken from second bag = (1/2) x (4/11) So probability of blue ball = ( 1/2) x (3/11) + (1/2) x (4/11) = 7/22

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In a 3*3 square grid comprising 9 tiles each tile can be painted in red or blue color. When the tile is rotated by 180 degree, there is no difference which can be spotted. How many such possibilities are there?

A16

B32

C64

D256

Answer: Option B

Explanation:

Grid has to be rotated at 180 degrees. hence,
11=33

12=32
13=31
21=23
22=22
31=13
32=12
33=11
cell 11-33 can be altered in 2 ways (as thr are 2 colours)
cell 12-32 can be altered in 2 ways cell 13-31 can be altered in 2 ways cell 21-23 can be altered in 2 ways and , cell 22 can be altered in 2 ways.

so 2X2X2X2X2 = 32.

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