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# Probability Questions

Home > Quantitative Aptitude > Probability > General Questions
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If a number cube is rolled once and coin is tossed once. What is the probability that the coin will show tails and composite number on the cube?

A1/8

B1/6

C1/2

D1/4

Es

Explanation:

Numbers on cube (1,2,3,4,5,6)
Composite number on dice are 4 and 6.

So, Probability that the coin will show tails and composite number on the cube = (1/2) *(2/6) = 1/6

Note: Composite number is a positive integer that can be formed by multiplying together two smaller positive integers. Equivalently, it is a positive integer that has at least one divisor other than 1 and itself

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There ara two bags A and B. A contains 6 red flowers and 3 pink flowers. where as bag B contains 2 red flowers and 7 pink flowers. One flower is choosen from a bag randomly. What is the probability that the flower choosen is pink?

A4/9

B1/3

C5/9

D3/9

Explanation:

Probability of pink ball=((1/2)*3/9)+((1/2)*7/9)=5/9

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In a bid two firms A and B competing against each other.If the probability of bid amount quoted by B being lower than that of A is 0.8 and if it is known that the bid is won by the ones who quotes the lowest price,what is the probability that A wins the bid?

A0.8

B0.004

C0.2

D0.001

Explanation:

Probability of 'a' biding lower than 'b' = 1 - 0.8 = 0.2
so probability of wining of 'a' = 0.2

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A class consists of 100 students, 25 of them are girls and 75 boys; 20 of them are rich and remaining poor; 40 of them are fair complexioned. The probability of selecting a fair complexioned rich girl is

A1/50

B3/50

C1/25

D2/25

Explanation:

The probability of selecting girl is: 25/100 = 1/4
The probability of selecting rich is: 20/100 = 1/5
The probability of selecting fair complexioned is: 40/100 = 2/5
Three are independent:
So, probability of rich and fair complexioned girl is = (1/4) *(1/5)* (2/5) = 1/50

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There are two bags A and B. A contains 6 red flowers and 3 pink flowers. where as bag B contains 2 red flowers and 7 pink flowers. One flower is chosen from a bag randomly. What is the probability that the flower chosen is pink?

A4/9

B1/3

C5/4

D5/9

Explanation:

Given Bag A contain 6 red & 3 pink => total ball = 9
Bag B contain 2 red & 7 pink => total ball = 9
Probability of picking 1 pink from bag A = 3/9
Probability of picking 1 pink from bag B = 7/9
Total = 3/9 + 7/9 = 10/9
And probability of selecting a bag is 1/2
So, probability of choosing a pink flower = [(1/2)* (10/9)] = 5/9

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There are two boxes, one containing 32 black balls and other containing 31 red balls you are allowed to move the boxes at random so that when you choose the box at random and a ball at random from the chosen box, the probability of getting the black ball is maximized. This maximum probability is

A0.25

B0.51

C0.75

D0.5

Explanation:

Here is no explanation for this answer

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Ravi has a bag full of 10 Nestle and 5 Cadbury chocolates. Out of these, he draws two chocolates. What is the probability that he would get at least one Nestle Chocolate ?

A19/21

B3/7

C2/21

D1/3

Explanation:

Total number sample space two chocolates can be drawn in the way of n(S) = 15C2= 105
At least one to be nestle. n(E) = 10C1 * 5C1 + 10C2 * 5C0 = 95
P(E) = 95/105 = 19/21

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A software engineer creates a LAN game where an 8 digit code made up of 1,2,3,4,5,6,7,8 has to be decided on, universal code . There is a condition that each number has to be used once and no number can be repeated . What is the probability that first 4 digits of the code are even numbers ?

A1/70

B1/840

C1/8

D1/40320

Explanation:

Total no of ways = 8!.

To finding even nos at last 4 digit s ways are 4!

and that for odd is 4!

so it can be done in 4*3*2*1*4*3*2*1/8*7*6*5*4*3*2*1 => 4!*4!/8! =>1/70

So, option A is correct

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The probability of getting at least one tail in 5 throws of a coin is?

A1/32

B1/5

C31/32

DNone of these

Explanation:

A coin throws 5 times <=> 5 coins throws at one time.
So total no of choices are 2^5 = 32
Chances that not getting at least one tails is 1 (h,h,h,h,h)
So 1-(1/32)=31/32

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A bag contains 5 oranges, 4 bananas and 3 apples. Rohit wants to eat a banana or an apple.He draws a fruit from the bag randomly. What is the probability that he will get a fruit of this choice?

A1/12

B7/12

C5/12

DNone of these

Explanation:

Total fruits = 12 (5+4+3)
Chances of selecting banana or apple = (4+3) = 7
So, probability =7/12

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