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# Probability Questions

Home > Quantitative Aptitude > Probability > General Questions
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In a school, sixty percent of the students are girls and thirty five percent of the girls are poor. If a student is randomly selected, what is the probability of selecting a poor girl student?

A60%

B35%

C21%

DNone of these

Explanation:

Lets assume 100 be the total strength
60% out of 100= 60 number of girls
now 35% of girls are poor i.e. (35/100)*60 =21
Therefore probability of selecting a poor girl out of 21 poor girls is 21 c 1=21

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Three dice are rolled. What is the probability that you will get the sum of the numbers as 10?

A27/216

B25/216

C10/216

D11-Jan

Explanation:

Total events = 6*6*6=216
possible cases for sum equal to 10 are
(1,3,6)-6 combinations + (1,4,5)-6 combinations + (2,3,5)-6 combinations + (2,4,4)-3 combinations + (3,3,4)-3 combinations +
(2,2,6)-3 combinations
So, Total combinations = 27
Hence probability = 27/216

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A drawer holds 4 red hats. what is the probability of getting exactly 3 red or exactly 3 blue hats when taking out 4 hats randomly out of the drawer and immediately returning every hat to the drawer before taking out the next?

A1/4

B3/8

C1/2

D1/8

Explanation:

Probablity of taking out a particular color hat = 4/8 = 1/2
P(BBBR) = (1/2)^4
P(BBRB) = (1/2)^4
P(BRBB) = (1/2)^4
P(RBBB) = (1/2)^4
Total = 4 * (1/2)^4
Similary for (RRRB) = 4 * (1/2)^4
Hence, the required answer is 8 * (1/2) ^4 = 1/2.

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There are 3 red, 3 blue, 3 green marbles. What is probability that atleast two of them are of same color. If 3 marbles are done without replacement.

A17/28

B19/28

C19/14

D9/28

Explanation:

Total possible outcomes = 9c3.
Probability(atleast two of them are same color) = 1 - probability(3 different).
=> 1-(3c1*3c1*3c1)/9c3
=> 19/28.

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A coin will be flipped five times. If the results are either 0, 1, 4, or 5 heads, you will receive Rs.10. If the results are 2 or 3 heads, you will have to pay Rs.5. What is your mathematical expectation?

A0.625 Paisa

B0.725 Paisa

C0.825 Paisa

D0.925 Paisa

Explanation:

4*10*(1/2)^5+2*(-5)*(1/2)^5
(1/2) is probability of getting no of heads.
Therefore calculating above gives 0.825 paisa.

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There are 3 red balls,3 green balls and 3 blue balls are present.what is the probability of atleast two of them are of same colour if 3 balls are drawn?

A57/84

B27/42

C75/84

DNone of these

Explanation:

Total combinations = 9c3 = 84
if we calculate the combinations in which three balls are of different colours,
then combinations will be = 3c1*3c1*3c1 = 27
so final probability of at least two of them are of same colour if 3 balls are drawn = 1 - (27/84) = 57/84.

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A jar contains 2 red, 3 blue, and 4 green marbles. Niki draws one marble from the jar, and then Tom draws a marble. What is the probability that Niki will draw a green marble and Tom will draw a blue marble?

A1/6

B2/8

C5/6

D3/8

Explanation:

P(green, blue) = 4/9 * 3/8 = 1/6

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There are 9 popsicles: 3 orange, 3 cherry, 3 grape. There are 4 children. What is the probability that all 4 children will get the flavor of their choice?

A23/27

B25/27

C1/27

D26/27

Explanation:

Consider the 4 children. Each of them has a flavor preference, and so there are 3x3x3x3 = 81 possibilities for what the kids want (we assume that each kid does in fact want one of the three flavors: orange, cherry, or grape).

Of these 81 possibilities, 3 of them mean that one child will be unhappy: OOOO, CCCC, and GGGG (i.e., when all four of them want the same flavor as the others). For all of the other possibilities (e.g.OOCG, OOOC, OOCC,...) there are going to be enough popsicles of the required flavors.

Assuming that each of the 81 possibilities is equally likely,

Pr(4 happy kids) = 1 - Pr(at least one unhappy kid)
= 1 - 3/81
= 1 - 1/27
= 26/27

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2 boxes, 32 black n 31 red balls the probability of getting black ball is maximum. The maximum probability is

A3/4

B1/4

C2/3

DNone of these

Explanation:

Here is no explanation for this answer

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Two urns contain respectively 2 red 3 white and 3 red,5 white balls.One ball is drawn at random from the first urn and transferred into the second.A ball is now drawn from the second urn and it turns out to be red. What is the probability that the transferred ball was white?

A3/17

B9/17

C5/17

DNone of these

Explanation:

According to baye's theorem:
p(no of way to drawn a ball from 2nd urns is red and ball transferred from 1 urns)=(3c1/5c1)*(3c1/9c1)=9/45
Total=(2c1/5c1)*(4c1/9c1)+(3c1/5c1)*(3c1/9c1)=17/45
so probability=9/45/17/45=9/17;

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