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# Pipes & Cistern Questions

Home > Quantitative Aptitude > Pipes & Cistern > General Questions
NA
SHSTTON
10
Solv. Corr.
31
Solv. In. Corr.
41
Attempted
3 M:11 S
Avg. Time

1 / 2

Choose the correct option.

There are two pipes A and B. If A filled 10 liters in hour B can fills 20 liters in same time. Likewise B can fill 10, 20, 40, 80,160. If B filled in (1/16) th of a tank in 3 hours, how much time will it take to fill completely?

A17 hours

B5 hours

C7 hours

D7 1/2 hours

Explanation:

Tank filled by B in 3 hours=1/16

B fills double amount than in previous hour (from Given series 10,20,40,80,160)

So in 4 hours tank filled=2/16

In 5 hours tank filled=2*2/16=4/16

In 6 hours tank filled=2*4/16=8/16

In 7 hours tank filled=16/16=1

So, it took 7 hours to fill the tank

Workspace

NA
SHSTTON
13
Solv. Corr.
56
Solv. In. Corr.
69
Attempted
1 M:27 S
Avg. Time

2 / 2

Choose the correct option.

It takes 30 minutes to empty a half-full tank by draining it at a constant rate. It is decided to simultaneously pump water into the half-full tank while draining it. What is the rate at which water has to be pumped in so that it gets fully filled in 10 minutes?

A4 times the draining rate

B3 times the draining rate

C2.5 times the draining rate

D2 times the draining rate

Explanation:

The equation to use is RT = Q
Q is equal to 1/2 the tank.
T is equal to 30 minutes
R is derived from the equation as follows:
RT = Q
R*30 = 1/2
R = 1/60
the tank is being drained at the rate of 1/60 of the tank per minute.
at that rate, the remaining 1/2 of the tank will be drained in 30 minutes.

the rate of filling and the rate of draining are opposing forces so you need to subtract one from the other to get the rate of filling.

you want to fill 1/2 the tank while at the same time you are draining the tank.
the combined formula would be as follows:
(RF - RD) * 10 = 1/2
you know RD is 1/60 because we just solved for that.
(RF - 1/60) * 10 = 1/2
simplify this to get:
10*RF - 10/60 = 1/2
add 10/60 to both sides of this equation to get:
10*RF = 1/2 + 10/60 which becomes:
10*RF = 30/60 + 10/60 which becomes:
10*RF = 40/60.
divide both sides of this equation by 10 to get:
RF = 4/60.

4/60 is 4 times 1/60.

fill rate is 4 times the drain rate.

you start at 1/2 a tank which is the same as 3/6 of a tank.
in 10 minutes you will have drained 10*1/60 = 10/60 = 1/6 more of the tank.
in the same 10 minutes you will have filled 10*4/60 = 40/60 = 4/6 of the tank.
sum of fill and drain is equal to 3/6 - 1/6 + 4/6 which is equal to 6/6 which is equal to 1.

at the end of the 10 minutes, the tank is full.

you could have solved this another way as well.
you still had to find the drain rate which is equal to 1/60 of the tank per minute.

in 10 minutes, you will have drained 1/6 more of the tank.
the tank is now 1/2 - 1/6 = 3/6 - 1/6 = 2/6 full.

in order to fill the tank in the same 10 minutes, you have to fill 4/6 of the tank.

the same formula is used.
RT=Q
10R = 4/6
R = 4/60.

the fill rate is 4 times the drain rate.

Workspace

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