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# Pipes & Cistern Questions

Home > Quantitative Aptitude > Pipes & Cistern > General Questions
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13 buckets of water fill a tank when the capacity of each bucket is 51 litres. How many buckets will be needed to fill the same tank, if the capacity of each bucket is 17 litres?

A33

B29

C39

D42

Explanation:

Capacity of the tank =(13*51) liters.

Number of buckets required when capacity of each bucket is 17 liters =13*51/17=39

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A leak in bottom of tank can empty a full tank in 12 minutes. If the leak is not there then two pipes A and B can fill the tank in 15 minutes and 20 minutes respectively. If the leak is active and both the pipes are open then How much time will be required to fill the tank:

A30 minutes

B60 minutes

C23 minutes

D35 minutes

ENone of these

Explanation:

Tank part filled by both (A+B) in 1 min = (1/15+1/20) = 7/60
Tank part can be empty by leak in 1 min = 1/12
So Tank part will be filled when Both taps and leak are active in 1 min = (7/60 - 1/12) = 2/60 = 1/30
=> 1/30 part of tank filled by both tap when leak is active = 1 min
=> Whole tank can be filled by both tap when leak is active = 30 min

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23 / 36

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Two taps can separately fill a cistern 10 minutes and 15 minutes respectively and when the waste pipe is open, they can together fill it in 18 minutes. The waste pipe can empty the full cistern in?

A7 min

B13 min

C23 min

D9 min

ENone of these

Explanation:

Work done by third tap in 1 min = (1/18-1/10+1/15) = -10/90 = -1/9 (The negative value denote that emptying)
so the third tap alone can empty the cistern in 9 min.

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One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 36 minutes, then the slower pipe alone will be able to fill the tank in:

A81 min.

B108 min.

C144 min.

D192 min

Explanation:

Let the slower pipe alone fill the tank in x minutes.

Then, faster pipe will fill it in x/3 minutes.
So, 1/x + 3/x = 1/36

=> 4/x = 1/36

=> x = 144 min.

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A tank is fitted with 8 pipes, some of them that fill the tank and others that are waste pipe meant to empty the tank. Each of the pipes that fill the tank can fill it in 8 hours, while each of those that empty the tank can empty it in 6 hours. If all the pipes are kept open when the tank is full, it will take exactly 6 hours for the tank to empty. How many of these are fill pipes?

A4

B5

C1

D7

Explanation:

Let the number of fill pipes be x and empty pipes be 8-x
Let one pipe in 1 hr fills 1/8th part of the tank then x pipes will fill x/8 part
Similarly 8-x pipes will empty (8-x)/6th part of the tank in 1 hour

Hence x/8 - (8-x)/6 =1/6 (All the pipes operating simultaneously so finding the result of 1 hr)

Solving for x we get as x= 4

So no. of fill pipes =no. of empty pipes=4

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Pipe A usually fills a tank in 2 hours. On account of a leak at the bottom of the tank, it takes pipe A 30 more minutes to fill the tank. How long will the leak take to empty a full tank if pipe A is shut?

A14 hours

B15 hours

C10 hours

DNone of these

Explanation:

Solution:

Pipe A takes 2 hours to fill the tank. Therefore, it fills half the tank in an hour or 50% of the tank in an hour.

When there is a leak it takes 2 hours 30 minutes for the tank to fill. i.e 5/2 hrs hours to fill the tank or 2/5th or 40% of the tank gets filled in 1 hr.

On account of the leak, (50âˆ’40)%=10% of the water gets wasted every hour. Therefore, the leak will take 10 hours to drain a full tank.

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A pump can be used either to fill or to empty a tank. The capacity of the tank is 3600 m. The emptying capacity of the pump is 10 m 3/min higher than its filling capacity. What is the emptying capacity of the pump if the pump needs 12 more minutes to fill the tank than to empty it?

A50 m

B60 m

C30 m

DNone of these

Explanation:

Let â€˜fâ€™ m^3/min be the filling capacity of the pump. Therefore, the emptying capacity of the
pump will be = (f + 10 ) m^3/ min.
The time taken to fill the tank will be = 3600/f minutes
And the time taken to empty the tank will be = 3600/(f+10).
We know that it takes 12 more minutes to fill the tank than to empty it
=> 3600/f - 3600/(f+10) = 12
=> 36000 = 12 (f^2 + 10 f) => 3000
=> f^2 + 10f - 3000 = 0
Solving for positive value of â€˜fâ€™ we get, f = 50.
So, the emptying capacity of the pump = 50 + 10 = 60 m

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Three pipes A, B and C can fill a tank from empty to full in 30 minutes, 20 minutes and 10 minutes respectively. When the tank is empty, all the three pipes are opened. A, B and C discharge chemical Exputions P, Q and R respectively. What is the proportion of Expution R in the liquid in the tank after 3 minutes?

A7/11

B3/11

C5/11

D6/11

Explanation:

Part filled by A in 1 min. = 1/30
Part filled by B in 1 min. = 1/20
and Part filled by C in 1 min. = 1/10
So, Part filled by (A + B + C) in 3 minutes = 3(1/30 + 1/20 + 1/10) = 11/20.
Part filled by C in 3 minutes = 3/10
Hence, the Required ratio = 3/10 * 20/11 = 6/11.

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There are two water tanks A and B, A is much smaller than B. While water fills at the rate of 1 liter every hour in A, it gets filled up like, 10, 20, 40, 80, 160 in tank B. (At the end of first hour, B has 10 liters, second hour it has 20 liters and so on). If tank B is 1/32 filled of the 21 hours, what is total duration of hours required to fill it completely?

A26

B25

C5

D27

Explanation:

for every hour water in tank in B is doubled,
Let the duration to fill the tank B is x hours.
x/32 part of water in tank of B is filled in 21 hours,
Next hour it is doubled so,
2*(x/32) part i.e (x/16) part is filled in 22 hours,
Similarly (x/8)th part in 23 hours,(x/4)th part is filled in 24 hours,
(x/2)th part is filled in 25 hours, (x)th part is filled in 26 hours

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If a pipe can fill the tank within 6hrs.But due to leak it takes 30 min more. Now the tank is full then how much time will it take to empty the tank through the leak?

A78

B56

C66

D59

Explanation:

Pipe A takes 6 hours to fill the tank. Therefore, it fills 1/6th of the tank in an hour or 16.66% of the tank in an hour.

When there is a leak it takes 6 hours 30 minutes for the tank to fill. i.e 13/2 hrs hours to fill the tank or 2/13th or 15.38% of the tank gets filled in 1 hr.

On account of the leak, (16.66âˆ’15.38)%=1.28% of the water gets wasted every hour. Therefore, the leak will take 100/1.28 i.e 78.125 hrs to drain a full tank.

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