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Pipes & Cistern Questions

Home > Quantitative Aptitude > Pipes & Cistern > General Questions
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Choose the correct option.

Bucket A has thrice the capacity as bucket B. It takes 80 turns for bucket A to fill the empty drum. How many turns it will take for both the buckets A and B, having each turn together to fill the empty drum?


A30

B60

C45

D80

Answer: Option B

Explanation:

Lets Assume capacity of bucket A = x
so capacity of bucket B = x/3

Given that it takes 80 turns for bucket A to fill the empty drum.
So capacity of the drum = 80x

Number of turns required if both A and B having each turn together=80x/(x+x/3)=240x/(3x+x)=60

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A large tanker can be filled by two pipes A and B in 60 minutes and 40 minutes respectively. How many minutes will it take to fill the tanker from empty state if B is used for half the time and A and B fill it together for the other half?


A27 min

B30 min

C20 min

D15 min

ENone of these

Answer: Option B

Explanation:

Tank part filled by pipe A in 1 minute = 1/60
Tank part filled by pipe B in 1 minute =1/40

So Tank Part filled by both pipes A and B in 1 minute = (1/60+1/40)=5/120=1/24

Lets Assume tanker get filled in x minutes.
Then, to fill the tanker from empty state, B is used for x/2 minutes
and A and B together is used for the rest x/2 minutes.

(x/2*1/40)+(x/2*1/24)=1
=> x/2(1/40+1/24)=1
=> x/2*8/120=1
=> x/30=1
=> x = 30 minutes

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Pipe A can fill an empty tank in 12 hours. Pipe B can empty it in 36 hours. If at 8 a.m. the pipe A is opened on an empty water tank and pipe B is opended at 9 a.m., 10 a.m. 11 a.m. and 12 p.m. for 15 minutes each, by what time in the evening will the tank be filled?


A6 p.m.

B8 p.m.

C9 p.m.

D10 p.m.

Answer: Option C

Explanation:

Tank part filled by Pipe A in 1 hour = 1/12
similarly Tank part emptied by pipe B in 1 hour = 1/36
or Tank part emptied by pipe B in 15 min = 15 * 1/60*36 = 1/144

From 8 a.m. to 9 a.m. tank part filled = 1/12 => 11/12 of the tank is empty
From 9 a.m. to 10 a.m. tank part will be filled = (1/12 + 1/144) = 11/144 => 1 hour 11/144 of the tank gets filled
11/12 part of the tank would take = 11/12 x 144/11 = 12 hours
Total time required is 1 + 12 = 13 hours
=> Tank would be full @ 8 a.m. + 13 = 9 p.m.

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Three taps A,B and C can fill a tank in 12,15 and 20 hours respectively. If A is open all the time and B ,C are open for one hour each alternatively, the tank will be full in:


A6 hrs

B20/3 hrs

C7 hrs

D15/2 hrs

Answer: Option C

Explanation:

Tank filled by (A+B) in 1 hour = (1/12+1/15) = 9/60 = 3/20
Tank filled by (A+C) in 1 hour = (1/12+1/20) = 8/60 = 2/15
So tank filled in 2 hours = (3/20 + 2/15) = 17/60
Tank part filled in 6 hrs = 3*17/60 = 17/20

Remaining part = (1-17/20) = 3/20

Now, it is the turn of A and B (3/20) part is filled by A and B in 1 hour.
So Total time taken to fill the tank =(6+1)hrs= 7 hrs

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There are 2 taps A and B to fill up a water tank. The tank can be filled in 40 minutes if both taps are on. The same tank can be filled in 60 minutes if tap A alone is on. How much time will tap B alone take to fill up the same tank ?


A64 minutes

B80 minutes

C96 minutes

D120 minutes

ENone of these

Answer: Option D

Explanation:

Tank part filled by (A+B) in 1 min = 1/40
Tank part filled by A alone in 1 min = 1/60
=> Tank part filled by B alone in 1 min = (1/40 -1/60) = 1/120
Therefore Tap B can fill the tank in 120 minutes

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8 taps through which water flows at the same rate can fill a tank in 30 minutes. If two taps go out of order, how long will the remaining taps take to the fill the tank?


A35 minutes

B37 minutes

C40 minutes

D38 minutes

Answer: Option C

Explanation:

Given Time need by 8 taps to fill tank = 30 minutes
So let's assume time need by 6 taps to fill tank = M minutes
M = (8 x 30)/6 = 40 minutes

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A water tank is two-fifth full.Pipe A can fill a tank in 10 minutes and pipe B can empty it in 6 minutes.If both the pipes are open,how long will it take to empty or fill the tank completely?


A6 min.to empty

B6 min.to fill

C9 min.to empty

D9 min.to fill

ENone of these

Answer: Option A

Explanation:

Pipe B is faster than pipe A
=> the tank will be emptied.
part to be emptied = 2/5
Tank part emptied by (A+B) in 1 minute= (1/6-1/10)=1/15
1/15:2/5::1:x =>2/5 = 1/15x=> x = 6min
so, the tank will be emptied in 6 min

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Two pipes can fill a tank in 20 and 24 minutes respectively and a waste pipe can empty 3 gallons per minute. All the three pipes working together can fill the tank in 15 minutes. The capacity of the tank is:


A60 gallons

B100 gallons

C120 gallons

D180 gallons

Answer: Option C

Explanation:

Tank part filled by pipe A in 1 min = 1/20
similarly by pipe B in 1 min = 1/24

So Work done by waste pipe in 1 min = 1/15 - (1/20+1/24) = -1/40(Here negative value means emptying)
Volume of 1/40 part = 3 gallons
Volume of whole = 3*40 = 120 gallons.

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Two pipes P and Q can fill a cistern in 12 and 15 minutes respectively. Both are opened together, but at the end of 3 minutes the first is turned off. How much more time will it take to fill the tabk by pipe B?


A9 1/4 min

B11 1/4 min

C7 1/4 min

D8 1/4 min

ENone of these

Answer: Option D

Explanation:

Tank part filled by pipe A in 1 minute = 1/12
similarly by pipe B = 1/15
Tank part filled by both pipe in 1 min = (1/12+1/15)
so tank part filled by both pipe in 3 min = 3*(1/12+1/15) = 9/20
So remaining part to be filled by B = (1-9/20) = 11/20
1/15 part of tank filed by B = 1 min
so 11/20 part of tank filled by B = 15 * 11/20 = 8 1/4 min.

Workspace

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20 / 42

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A cistern has a leak which would empty the cistern in 20 minutes. A tap is turned on which admits 4 liters a minute into the cistern, and it is emptied in 24 minutes. How many liters does the cistern hold?


A480 liters

B600 liters

C720 liters

D800 liters

Answer: Option A

Explanation:

Work done by the inlet in 1 min = (1/20-1/24) = 1/120
=> volume fo 1/120 part = 4 liters.
=> volume of whole = 120*4 = 480 liter.

Workspace

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