Method: 1
Let's assume Ravi salary = 100
It get reduced by 25% => Salary = 75
75(1 + P/100) = 100
1+ P/100 = 4/3
P = 100/3 = 33 1/3%.
Method: 2
You can use directly formula i.e
[(R*100)/(100-R)]% Where 'R' is decresed %
so put 25 at place of 'R'
=> [(25 * 100)/(100 - 25)]% => [(25 *100)/75]%
=>100/3% = 33 1/3%
Workspace
NA
SHSTTON
50
Solv. Corr.
138
Solv. In. Corr.
188
Attempted
1 M:12 S
Avg. Time
2 / 12
Choose the correct option.
Fresh fruit contains 68% water and dry fruit contains 20% water. How much dry fruit can be obtained from 100 kg
1. Given fresh fruit has 68% water,
=> Remaining 32% will be fruit content.
2. Given Dry fruit has 20% water
=> Remaining 80% is fruit content.
Here assume weight of dry fruit = x kg.
"fruit content in both the fresh fruit and dry fruit is the same"
Fruit % in fresh-fruit = fruit% in dry-fruit
so (32/100) * 100 = (80/100 )* x
=> x = 40 kg.
Workspace
NA
SHSTTON
105
Solv. Corr.
129
Solv. In. Corr.
234
Attempted
1 M:3 S
Avg. Time
3 / 12
Choose the correct option.
A student multiplied a number by 3/5 instead of 5/3. What is the percentage error in the calculation?
In a certain college, 20% of the boys and 40% of the girls attended the annual college outing. If 35% of all the students are boys, what percent of all the employees went to the outing?
Lets assume total students =100
so in that 35 students are boys and remaining 65 will be girl.
20% of boys = (35)*20/100 = 7
40% of girls = (65)*40/100 = 26
Totally (26+7)=33 employee went to outing.
So 33 is 33% in 100
=> 33% employees went for outing.
Workspace
NA
SHSTTON
52
Solv. Corr.
44
Solv. In. Corr.
96
Attempted
0 M:5 S
Avg. Time
5 / 12
Choose the correct option.
If the price of petrol increases by 25%, by how much must a user cut down his consumption so that his expenditure on petrol remains constant?
Let the petrol 1 unit initial price be rs 100.
25% increase on rs 100= rs 125
since expenditure to remain constant 125*x= 100*1
x=.80 unit
So, consumer reduces =.20 unit i.e 20%
Workspace
NA
SHSTTON
29
Solv. Corr.
80
Solv. In. Corr.
109
Attempted
0 M:10 S
Avg. Time
6 / 12
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On the first test of the semester, kiran scored a 60. On the last test of the semester, kiran scored 75%. By what percent did kiran's score improve?
P=(30/100)of Q
P=(30/100)*(20/100)of M
p=(30/100)*(20/100)*(50/100)of N
=>p=(30/100)*(20/100)*(50/100)*N
=>P/N=3/100
Workspace
NA
SHSTTON
21
Solv. Corr.
18
Solv. In. Corr.
39
Attempted
0 M:49 S
Avg. Time
8 / 12
Choose the correct option.
The value of a scooter depreciates in such a way that its value of the end of each year is 3/4 of its value of the beginning of the same year. If the initial value of the scooter is Rs.40,000, what is the value at the end of 3 years ?
A store has a banner of 25% off on MRP of all branded items. Sheetal goes into the store and buys a belt worth Rs. 75, a shirt of Rs. 1,999 and a shawl of Rs. 2,900. How much amount will she have to pay?
The discount is 25% so she has to pay 75% of the total bill.
Total = (75+1999+2900)=4974
Now, 75/100*4974= Rs. 3730.50
Workspace
NA
SHSTTON
17
Solv. Corr.
13
Solv. In. Corr.
30
Attempted
1 M:1 S
Avg. Time
10 / 12
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Jose is a student of horticulture in the University of Hose. In a horticultural experiment in his final year, 200 seeds were planted in plot I and 300 were planted in plot II. If 57% of the seeds in plot I germinated and 42% of the seeds in plot II germinated, what percent of the total number of planted seeds germinated?
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