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Percentage Questions

Home > Quantitative Aptitude > Percentage > General Questions
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A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?


A45%

B45.45%

C54.55%

D55%

Answer: Option B

Explanation:

Number of runs made by running = 110 - (3 * 4 + 8 * 6)
= 110 - (60) = 50.
Required percentage = ({50/110}*100)% = 45{5/11}%

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Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:


A39, 30

B41, 32

C42, 33

D43, 34

Answer: Option C

Explanation:

Let their marks be (x + 9) and x.
Then, x + 9 = (56/100)(x + 9 + x)
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.

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1,40,00,000 pencils are put up straight. all the pencils are of length range 3 to 6 inches. 80% of the pencils have average of five inches. so the find out the total length spanned by the pencils.


A644000 inches to 728000 inches

B64400000 inches to 72800000 inches

C644000 inches to 72800000 inches

DNone of these

Answer: Option B

Explanation:

length covered by 80% of the pencils =80/100 * 14000000 * 5 = 56000000 inches

Minimum length covered by remaining 20% of the pencils =20/100 * 14000000 * 3 = 8400000 inches

Maximum length covered by remaining 20% of the pencils =20/100 * 14000000 * 6 = 16800000 inches

Hence, total length spanned by the pencils is (56000000 +8400000) to (56000000 +16800000 )

ie, 64400000 inches to 72800000 inches

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A bakery opened yesterday with its daily supply of 40 dozen rolls. Half of the rolls were sold by noon and 80 % of the remaining rolls were sold between noon and closing time. How many dozen rolls had not been sold when the bakery closed yesterday?


A4

B5

C8

D2

Answer: Option A

Explanation:

If half of the rolls were sold by noon,
Than remaining are 50 % (40) = 20.
Given 80% of the remaining were sold after the noon to closing time
80% (20) = 16
Unsold rolls = (20 - 16) = 4

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A tank contains 10,000 gallons of a solution that is 5 percent sodium chloride by volume. If 2500 gallons of water evaporate from the tank, the remaining solution will be approximately what percentage of sodium chloride?


A6%

B6.67%

C5.67%

D5%

Answer: Option B

Explanation:

Sodium chloride in the original solution = 5% of 10000 = 500
Water in the original solution = 10000 - 500 = 9500
If 2,500 Liters of the water is evaporated then the remaining water = (9500 - 2500) = 7000
Sodium chloride concentration = 500/(500+7000) * 100 = 6.67 %

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Jose is a student of horticulture in the University of Hose. In a horticultural experiment in his final year, 200 seeds were planted in plot I and 300 were planted in plot II. If 57% of the seeds in plot I germinated and 42% of the seeds in plot II germinated, what percent of the total number of planted seeds germinated?


A48%

B44%

C54%

D50%

Answer: Option A

Explanation:

Total seeds germinated in Plot I = 57% of 200 = 114
Total seeds germinated in Plot II = 42% of 300 = 126

So, total germinated seeds = (114 + 126) = 240
Percentage of germinated seeds of the total seeds = 240/500 = 48%

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If 75% of a class answered the first question on a certain test correctly, 55% answered the second question on the test correctly, and 20% answered neither of the questions correctly, what percentage answered both correctly?


A50%

B45%

C55%

DNone of these

Answer: Option A

Explanation:

Given 20% student answered neither question => students who answered atleast one question = 100% - 20% = 80%

Student answered first question = 75%
Student answered second question = 55%

Follow the formula n(A?B) = n(A) + n(B) - n(A?B)
=> 80% = 75% + 55% - n(A?B)
? n(A?B) = 50%

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There are 120 male and 100 female in a society. Out of 25% male and 20% female are rural. 20% of male and 25% of female rural people passed in the exam. What % of rural students have passed the exam?


A23%

B22%

C21%

DNone of these

Answer: Option B

Explanation:

Given 120 male and 100 female society.
Rural male = 25*120/100= 30, Rural female = 20*100/100 = 20.
Passed students from rural:
male = 20*30/100 = 6, female = 25*20/100 = 5
Required percentage = 11/50*100=22%

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In paper A, one student got 18 out of 70 and in paper B he got 14 out of 30. In which paper he did fare well?


A46.6

B46

C45

D4.6

Answer: Option A

Explanation:

Find the percentages. Paper A = 18/70 * 100 = 25.7
Paper B = 14/30 * 100 = 46.6

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If the value of the numerator is increased by 20% and that of the denominator is decreased by 25% the fraction becomes unity the numerator of original fraction is:


A8

B5

C9

DNone of these

Answer: Option B

Explanation:

120n/75d=1
n/d=75/120=5/8

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