Lets assume sum of money = Rs. x ;
A gets Rs. 33 when sum distributed in the ratio of 3:2:5
so, 33=x*3/10
=> x=110
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Three friends Gerard, Rooney and Ronaldson work together to dig a hole. Gerard alone can complete the work in 10 days, Rooney in 8 days and together all three can complete it in 4 days. They earn a total of Rs. 1,200. Find the share of Rooney if the money that they receive is proportional to the work that they do?
Ronaldson can complete work in 40 days ( 1/4-1/10-1/8)
So, ratio of work done = 1/10 :1/8 : 1/40 = 4 : 5 : 1
So, amount payed rooney = 1200 * (5 / (5+4+1) ) = 1200 * 1/2 = 600
So, Rooney share = 1200/2 = 600
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A sum of Rs.3000 is distributed among A, B, and C. A gets 2/3 of what B and C got together and c gets 1/3 of what A and B got together, C's share is?
As A+B+C=3000. And A=2/3(B+C).
Also C=1/3(A+B).
So, 3C=A+B.
Hence now we can substitute A+B by 3C.
So final equation will be 3C+C=3000.
Hence , 4C=3000 => C=750.
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A started business investing Rs. 60,000.Exactly six months later,B joined him investing Rs. 90,000.If they make a profit of Rs. 1,26,000 at the end of the year. How much should B's share in it?
A investment for 12 months = 60,000*12 = 720000
B investment for 6 months = 90000 * 6 = 540000
A & B investment ratio = 72/54 => 4/3
So, B' share = 126000 * 3/7= 54000
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Out of 9 person, 8 person spent RS.30 each for their meals. The 9th one spent Rs.20 more than the average expenditure of all the nine. The total money spent by all of them was:
Let the 9th person spend Rs x.
Then the total sum spent by the nine people = 30 x 8 + x
= 240 + x.
So the average expenditure = (240 + x)/9.
Now x is 20 more than the average expenditure.
So, x = (240 + x)/9 + 20
Therefore x - 20 = (240 + x)/9
Thus, 9x - 180 = 240 + x
Or, 8x = 420
Or x = 52.50
Therefore total money spent = 240 + 52.50 = 292.50
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George Paul, Hari start a business by contributing Rs. 30000, Rs. 40000, Rs. 50000 respectively. After 1/2 year George withdraws half his contribution. At the end of the year the business showed a profit of Rs. 90000 which has divided amongst the 3 men proportionate to amount and duration and duration of their investment in enterprise. Paul got:
George investiment for year is 6*15000+12*15000 = 2,70,000
Paul = 12*40,000 = 4,80,000
Hari = 50,000*12 = 6,00,000
Their ratio is 9 : 16 : 20
Given, profit = Rs. 90000
So, paul share = (90000)*16/45 = Rs. 32000
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Three generous friends, each with some money, redistribute the money as follows: Sandra gives enough money to David and Mary to double the amount of money each has. David then gives enough to Sandra and Mary to double their amounts. Finally, Mary gives enough to Sandra and David to double their amounts. If Mary had 11 rupees at the beginning and 17 rupees at the end, what is the total amount that all three friends have?
Let Sandra, David and Mary each has s, d and 11 respectively.
After the first distribution,
David has d + d = 2d, Mary has 11 + 11 = 22 and Sandra has s - d - 11.
After the second distribution,
Sandra has 2*(s - d - 11) , mary has 2*22 = 44 and david has 2d - (s - d - 11) - 22=3d - s -11.
After the third distribution,
Sandra has 2*2(s - d - 11), david has 2*(3d - s - 11) and mary has 44 - 2(s - d - 11) - (3d - s - 11) = 77 - s - d
It is given that finally Mary has Rs.17. So, 77 - s - d=17
=> s + d = 60
=> s + d + 11 = 60 + 11 = 71.
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Three partner's A,B,C start a business. Twice A's capital is equal to thrice B's capital and B's capital is four times C's capital. Out of a total profit of Rs.16500 at the end of the year, B's share is:
Let C = x.
Then B = 4x and 2A = 3 * 4x = 12x. or A = 6x.
Therefore, A : B : C = 6x : 4x : x = 6 : 4 : 1.
Therefore, B's capital = Rs. 16500 * 4/11= Rs.6000.
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Mr. X, Mr. Y, Mr. Z collect Rs. 1,00,000 in the ratio of 2:3:5. Can you say how much extra money is given by Mr. Z than Mr. X?
Quantitative Aptitude Partnership Questions and Answers pdf
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