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# Numbers Questions

Home > Quantitative Aptitude > Numbers > General Questions
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A man have many daughters, each daughter have as many sons as her sisters. The product of the number of daughters and grandsons of the man lies between 40 and 50. Find the number of daughters of the man.

A4

B6

C5

D8

Explanation:

Let N be the number of daughters of the man.
Then each daughter has N-1 sisters.
Given that, each daughter has as many sons as her sisters.
That is, each of them has N-1 sons.
Number of grandsons of the man = N(N-1)
And the required product = N(N-1) x N = N x N(N-1) which lies between 40 and 50.
If N = 1 then N x N(N-1) = 0.
f N = 2 then N x N(N-1) = 2 x 2(1) = 4
If N = 3 then N x N(N-1) = 3 x 3 x 2 = 18
If N = 4 then N x N(N-1) = 4 x 4 x 3 = 48
If N = 5 then N x N(N-1) = 5 x 5 x 4 = 100
Therefore the possible value of N is 4.

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(2/3) of a number is 4 more than the (1/6) of the same number?

A6

B8

C36

D34

Explanation:

Solution: Let the number be x

Then 2/3*x - 1/6*x= 4

On solving we get x= 8

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The value of 3/4 + 5 / 36 + 7 / 144 + ...................+17 / 5184 + 19 / 8100 is ??

A0.99

B0.98

C0.95

DNone of these

Explanation:

Convert it into this series

[1-1/4]+ [1/4-1/9]+[1/9-1/16]+.........[1/81-1/100]

=1-1/100

=0.99

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What is the value of

(44444445*88888885*44444442+44444438)/444444442

A88888883

B88888884

C88888888

D44444443

Explanation:

On taking x=44444444
The equation can be written as- (x+1) (2x-3) (x-2)+(x-6) / x^2

Solving equation we get 2x-5

Substitute x=44444444 in above equation we get- 88888883

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The addition 457 + 982 + 896 = 2345 is incorrect. What is the least digit that can be changed to make the addition correct?

A5

B7

C6

D3

Explanation:

457+982+896= 2335 But in question its given 2345
If we change 5 of 457 and make it 467 then the equation will become correct. So the least possible number to be changed is 5.

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Find the value of "n" where 3^48 + 3^1996 + 3^3943+33^n is a perfect cube?

A1963

B1964

C1960

D1991

Explanation:

see subtracting powers of each coefficient 1996-48 = 1948

3943-1996= 1947

similary 3n-3943=1946

solving for n , n comes out to be 1963.

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If 28a + 30b+ 31c=365, find the value of a+b+c, if a, b, and c are natural numbers.

A4

B12

C10

DCannot be determined

Explanation:

Because in a year there are 7 months of 31 days and 4 months of 30 days and 1 month of 29 or 28 days so

28*1+30*4+31*7=365 (There is no other trick to solve this question)

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Let X be a four-digit number with exactly three consecutive digits being same and is a multiple of 9. How many such X?s are possible?

A22

B19

C20

D10

Explanation:

Let the four digit number be ?aaab? or baaa?.

Since, the number has to be a multiple of 9, therefore 3a+b should be either 9, 18 or 27.

Case I: 3a+b=9
Possible cases are: (1116,6111,2223,3222,3330,9000)

Case II: 3a+b=18
Possible cases are: (3339,9333,4446,6444,5553,3555,6660)

Case III: 3a+b=27
Possible cases are: (6669,9666,8883,3888,7776,6777,9990)

Hence, total number of cases is 20.

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Find the smallest 8-digit number which gives 15 as a remainder when divided by 38, 22 and 16.

A10002004

B10002015

C10001919

D10000015

Explanation:

Solution: Go with the options. The smaller numbers are option c and d.

Now divide them and check for the remainders.

10001919, when divided by 16, gives remainder 15

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The sum of odd number between 20 and 30 is

A125

B140

C120

D105

Explanation:

a = 21,l = 29 Clearly n = 5;
sum = n(a+l)/2 = 5*(21+29)/2 = 125

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