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Choose the correct option.

When a square of an odd number is divided by 8

AThe remainder could be any odd number.

Bnothing definite can be said about the remainder.

Cthe remainder is always 1.

Dthe remainder could be any even number.

Answer: Option (Login/Signup)

Show Explanation

Then (2a+1)^2 = 4a^2 + 4a + 1 = 4a(a+1) + 1.

Since a is odd, a+1 is even.

So, 4a(a+1) has to be a multiple of 8

Therefore 4a(a+1) + 1 must leave a remainder of 1 when divided by 8.

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