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Quantitative Aptitude :: Numbers - Discussion

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Choose the correct option.

2345 23455 234555 234555........... what was last 2 numbers at 200th digit?

A44

B55

C54

D66

Answer: Option (Login/Signup)

Show Explanation

the given series is 2345 23455 234555......



So the number of digits in each term are 4, 5, 6, ... or (3  1), (3  2), (3  3),......upto nth terms are=3n [n(n 1)/2]



so 3n [n(n 1)/2]>=200



For n = 16, We get 184 in the left hand side. So after 16 terms the number of digits equal to 184. And 16 them contains 16  3 = 19 digits.



Now 17 term contains 20 digits and 123444......4(17times)...  last two digits are 55.

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