a farmer has a rose garden. Every day he either plucks 7 or 6 or 24 or 23 roses. The rose plant are intelligent and when the farmer plucks these no. of roses, the next day 37 or 36 or 9 or 18 new roses bloom up in the garden respectively. On Monday he counts 189 roses, he plucks the roses as per his plan on consecutive days and new roses bloom up as per the intelligence of the plants mentioned above. After some days which of the following can be the number of roses in the garden?
lets assume the case of 23.
when he picks up 23 roses the next day there will be 18 new,
so, in this case., 5 flowers will be less every day.
=> when he counts 189, the next day 184, 179,174,169,................so on.
finally the no. of roses left behind will be 4.
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Find the sum of number between 200 and 300, which is multiple of 3?
Total number of four digit numbers =9000 (9999 - 999)
Find the numbers not having digit 7 in them.
Now consider the units place it can be selected in 9 ways (i.e 0,1,2,3,4,5,6,8,9)
Tens place it can be selected in 9 ways (i.e 0,1,2,3,4,5,6,8,9)
Hundreds place it can be selected in 9 ways (i.e 0,1,2,3,4,5,6,8,9)
Thousands place can be selected in 8 ways (i.e 1,2,3,4,5,6,8,9) here '0' cannot be taken
Total number of numbers not having digit 7 in it =9 x 9 x 9 x 8 =5832
Here a= ? , d=7 , s=13524 , n=7
sum of A.P. = n/2(2a + (n-1)d)
so we have series a+(a+7)+(a+14).......=13524;
=> 13524=7/2(2*a+(7-1)7)
=> a=1911;
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3 mangoes and 4 apples costs Rs 85. 5 apples and 6 peaches costs Rs. 122. 6 mangoes and 2 peaches cost Rs.114. what is the combined price of 1 apple, 1 peach and 1 mango?
Lets assume bags as a,b,c,d....
Given condition 1: A bag is 6 kg plus three fourth of weight of an another bag
so, a=6+(3/4)b ------ (1)
condition 2: weights are same
so, a=b=c=d
=> a=6+(3/4)a
=> a=24
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18
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29
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47
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How many numbers are there b/w 10 and 99 such that the number exceeds it's sum of the digits by 18
let x be tenth digit & y be unit digit
so number is =10*x+y
given, 10x+y=x+y+18
or 9x=18
or x=2
so no. will be of form 2y
value of y can be 0,1,2,3,...,8,9
nubers are 20,21,22,23,...,28,29
total=10 numbers
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How many three digit numbers can be form from digit 1-9 strictly in increasing order and follows an A.P.
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