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Numbers Questions

Home > Quantitative Aptitude > Numbers > General Questions
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a farmer has a rose garden. Every day he either plucks 7 or 6 or 24 or 23 roses. The rose plant are intelligent and when the farmer plucks these no. of roses, the next day 37 or 36 or 9 or 18 new roses bloom up in the garden respectively. On Monday he counts 189 roses, he plucks the roses as per his plan on consecutive days and new roses bloom up as per the intelligence of the plants mentioned above. After some days which of the following can be the number of roses in the garden?


A4

B37

C14

D30

Answer: Option A

Explanation:

lets assume the case of 23.
when he picks up 23 roses the next day there will be 18 new,
so, in this case., 5 flowers will be less every day.
=> when he counts 189, the next day 184, 179,174,169,................so on.
finally the no. of roses left behind will be 4.

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Find the sum of number between 200 and 300, which is multiple of 3?


A8217

B8317

C8127

D8172

Answer: Option A

Explanation:

Sequence: 201 + 204 + 207 + ...............+ 297

So n=33,a=201,l=297

So, s=n/2[a+l] = 33/2(201 + 297) = 33/2 * 498 =8217

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How many integers in the given below set do not contain the digit 7. 1000,1001,1002,-------------------------.9998,9999


A5832

B2888

C1444

D6746

Answer: Option A

Explanation:

Total number of four digit numbers =9000 (9999 - 999)
Find the numbers not having digit 7 in them.
Now consider the units place it can be selected in 9 ways (i.e 0,1,2,3,4,5,6,8,9)
Tens place it can be selected in 9 ways (i.e 0,1,2,3,4,5,6,8,9)
Hundreds place it can be selected in 9 ways (i.e 0,1,2,3,4,5,6,8,9)
Thousands place can be selected in 8 ways (i.e 1,2,3,4,5,6,8,9) here '0' cannot be taken
Total number of numbers not having digit 7 in it =9 x 9 x 9 x 8 =5832

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Sum of 1(2)+2(2)^2+3(2)^3+.......+100(2)^100


A99(2)^100+2

B100(2)^100+2

C101(2)^100+2

D101(2)^101+2

ENone of these

Answer: Option E

Explanation:

tcs-aptitude-question-answer

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If a publication occurs every seven years and the sum of the years is 13524. Then find the first year if the no. of publication is 7.


A1191

B1711

C1811

D1911

Answer: Option D

Explanation:

Here a= ? , d=7 , s=13524 , n=7
sum of A.P. = n/2(2a + (n-1)d)
so we have series a+(a+7)+(a+14).......=13524;
=> 13524=7/2(2*a+(7-1)7)
=> a=1911;

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3 mangoes and 4 apples costs Rs 85. 5 apples and 6 peaches costs Rs. 122. 6 mangoes and 2 peaches cost Rs.114. what is the combined price of 1 apple, 1 peach and 1 mango?


A37

B39

C40

D73

Answer: Option A

Explanation:

Form the below eq. from the given info. in question.

3m+4a=85 -------- (i)
5a+6p=122 -------- (ii)
6m+2p=114 ----- (iii)

By solving eq. (i), (ii) and (iii)

m=15,a=10,p=12
so 1 apple, 1 peach and 1 mango price = 15+10+12 = Rs. 37

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There are several bags of same weights. A bag is 6 kg plus three fourth of weight of an another bag . What is the weight of the bag?


A12

B24

C36

D42

Answer: Option B

Explanation:

Lets assume bags as a,b,c,d....
Given condition 1: A bag is 6 kg plus three fourth of weight of an another bag
so, a=6+(3/4)b ------ (1)
condition 2: weights are same
so, a=b=c=d

=> a=6+(3/4)a
=> a=24

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How many numbers are there b/w 10 and 99 such that the number exceeds it's sum of the digits by 18


A10

B12

C15

D9

Answer: Option A

Explanation:

let x be tenth digit & y be unit digit
so number is =10*x+y
given, 10x+y=x+y+18
or 9x=18
or x=2
so no. will be of form 2y
value of y can be 0,1,2,3,...,8,9
nubers are 20,21,22,23,...,28,29
total=10 numbers

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How many three digit numbers can be form from digit 1-9 strictly in increasing order and follows an A.P.


A9

B14

C16

D12

Answer: Option C

Explanation:

numbers are 123 135 147 159 234 246 258 345 357 369 456 468 567 579 678 789

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1/4th of 1/2 of 3/4th of 52000 = ?


A4875

B4875

C4857

D4785

E4877

Answer: Option A

Explanation:

1/4[1/2[3/4(52000/1)]]=(3*52000)/32)=156000/32=4875.

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