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# Numbers Questions

Home > Quantitative Aptitude > Numbers > General Questions
NA
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Solv. Corr.
162
Solv. In. Corr.
337
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In school there are some bicycles and 4 wheeler wagons. One Tuesday there are 58 wheels in the campus. How many bicycles are there?

A2

BBoth C & D

C5

D7

Explanation:

Let there are B bicycles and W wagons.

Total number of wheels = 2 Ã— B 4 Ã— W

Given 58 wheels â‡’ 2B 4W = 58

â‡’ B 2W = 29 â€¦â€¦ (Eq.1)

Also given B W = 18 â€¦â€¦ (Eq.2)

âˆ´ Eq.1 â€“ Eq.2

â‡’ W = 11

â‡’ B = 18 â€“ W

â‡’ B = 18 â€“ 11 = 7 Bicycles.

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NA
SHSTTON
137
Solv. Corr.
198
Solv. In. Corr.
335
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Which is the smallest no divides 2880 and gives a perfect square?

A1

B2

C5

D6

Explanation:

Solution: Do option verification

2880 on dividing by 5 gives 576 which is 24^2

Workspace

NA
SHSTTON
41
Solv. Corr.
125
Solv. In. Corr.
166
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The citizens of planet nigiet are 8 fingered and have thus developed their decimal system in base 8. A certain street in nigiet contains 1000 (in base 8) buildings numbered 1 to 1000. How many 3s are used in numbering these buildings?

A54

B64

C265

D192

Explanation:

0 - 77 we have 16 3's.

1-277 & 400 - 777 we have 96 3's.

in between 300 - 377 we have 63 3's.

Workspace

NA
SHSTTON
206
Solv. Corr.
222
Solv. In. Corr.
428
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If f(x) is divided by (1+x)(1-x). What is the value of x?

A+-1

B+-2

C+-3

D0

Explanation:

(1+x)(1-x)
=1-x^2
If f(x) is divisible comletely by (1-x^2) then the value of 1-x^2 must be zero
x^2=1
x=+-1

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NA
SHSTTON
151
Solv. Corr.
236
Solv. In. Corr.
387
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2 M:23 S
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15 / 115

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How Many no Between 1000 to 9900 in which four digits of number are different?

A3454

B4536

C4456

D4434

Explanation:

Number of 4 digit numbers having all different digits = 9*9*8*7 = 4536
smallest number : 1234, largest number : 9876, all are between 1000 and 9900.

Workspace

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SHSTTON
91
Solv. Corr.
74
Solv. In. Corr.
165
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For what value of "k" will the equation (2kx^2 + 5kx +2)=0 have equal roots?

A2/7

B9/4

C16/25

D7/1

Explanation:

For a 2nd degree equation "ax2+bx-c=0" has equal roots the condition is b2-4ac =0
So in the given equation (2kx^2 + 5kx +2)
a=2k, b=5k, c=2

=> (5k)^2-4(2k)(2)=0
=> 25k^2-16k=0
=>k(25k-16)=0
=> k=16/25;

Workspace

NA
SHSTTON
44
Solv. Corr.
107
Solv. In. Corr.
151
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0 M:20 S
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An elephant fell into a wall of depth 20mts.Everyday it climbs 4mts but at the end falls by 2mts.Find the number of days it would take for the elephant to get out of the wall

A10 days

B7 days

C9 days

D8 days

Explanation:

Solution: Net displacement of the elephant per day= 4-2=2mtr.

So if he climbs 8 days then he will cover 16m

On the 9th day when he will climb 4m then he will be out of the well.

Workspace

NA
SHSTTON
44
Solv. Corr.
101
Solv. In. Corr.
145
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1 M:39 S
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In a fraction, if numerator is added by 2 and denominator by 1 it results 1, and if numerator added again by 4 and denominator by 2 it results 1/2. Find the fraction?

A7/8

B8/9

C2/7

D7/2

Explanation:

Lets assume numerator=x and denominator=y.

So (x+2/y+1)=1 (by first condition)

=> x-y+1= 0 ------(1)

(x+6)/(y+3) = 1/2 (by second condition)

=> 2x+12= y+3 =>2x-y+9 = 0 ------(2)

By solving eq(1) and eq(2), we get x/y = 8/9.

Workspace

NA
SHSTTON
42
Solv. Corr.
101
Solv. In. Corr.
143
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0 M:53 S
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In a 2 digit no unit's place is halved and tens place is doubled. The differencce between the nos is 37.digit in unit's place is 2 more than tens place.

A23

B37

C64

D46

Explanation:

Lets assume tenth place digit be x & unit place be y.
So no. is = 10x + y.
Given unit place is halved and tens place is doubled.
so number will be = (10*2x + y/2).

Then Difference:
=> 10*2x + y/2 -(10x+y) = 37 .
=> 10x - y/2 = 37 .....(1)
and y-x = 2 .....(2)

By solving above 2 eq.
x=4 and y=6.
So required number is 46.

Workspace

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SHSTTON
47
Solv. Corr.
48
Solv. In. Corr.
95
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A three digit number consists of 9,5 and one more number . When these digits are reversed and then subtracted from the original number the answer yielded will be consisting of the same digits arranged yet in a different order. What is the other digit?

A4

B9

C3

D7

Explanation:

Let the digit unknown be n.
The given number is then 900+50+n=950+n.

When reversed the new number is 100n+50+9=59+100n.
Subtracting these two numbers we get 891-99n.
The digit can be arranged in 3 ways or 6 ways.
We have already investigated 2 of these ways.
We can now try one of the remaining 4 ways. One of these is n 95
100*n+90+5=891-99*n
=> 199*n =796
=> n=4
So the other digit is 4.

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