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# Compound Interest Questions

Home > Quantitative Aptitude > Compound Interest > General Questions
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If the simple interest on a sum of money for 2 years at 5% per annum is Rs. 50, what is the compound interest on the same at the same rate and for the same time?

ARs. 51.25

BRs. 54.25

CRs. 60

DRs. 52

Explanation:

Sum = Rs. (50 * 100)/(5*2) = Rs. 500.

Amount = Rs. [500 * (1 + 5/100)2]

= Rs. (500 * 21/20 * 21/20 )
= Rs. 551.25

C.I. = Rs. (551.25 - 500) = Rs. 51.25

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A sum of money amounts to Rs.6690 after 3 years and to Rs.10035 after 6 years on compound interest. Find the sum.

ARs.4400

BRs.4560

CRs.4600

DRs.4460

Explanation:

Let's assume the Sum = Rs. P.
P [1 + (R/100)]^3 = 6690 -------- (i)
P [1 + (R/100)]^6 = 10035 ----------(ii)
On dividing, we get [1 + (R/100)]^3 = 10035/6690 = 3/2.
P * (3/2) = 6690 or P = 4460.
Hence, the sum is Rs. 4460.

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The difference between the compound interest and the simple interest on a certain sum at 12% p.a. for two years is Rs.90. What will be the value of the amount at the end of 3 years?

A9780.8

B8780.80.

C7654.4

DNone of these

Explanation:

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A sum of money doubles itself at C.I. in 15 years. In how many years will it become eight times?

A40 years.

B35 years.

C55 years.

D45 years.

Explanation:

P [1 + (R/100)]^15 = 2P => [1 + (R/100)]^15 = 2 ----------- (i)
Let P [1 + (R/100)]^n = 8P => P [1 + (R/100)]^n = 8 = 2^3
= [{1 + (R/100)}^15]^3.
=> [1 + (R/100)]^n = [1 + (R/100)]^45.
=> n = 45.
So, the required time = 45 years.

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The principal that amounts to Rs. 4913 in 3 years at 6 1/4 % per annum C.I. compounded annually, is?

ARs. 3406

BRs. 4096

CRs. 3096

DRs. 4085

Explanation:

Formula: P = Amount / (1 + R/100)^n
Principal = [4913 / (1 + 25/(4 * 100))3]
=> 4913 * 16/17 * 16/17 * 16/17 = Rs. 4096

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If the compound interest on a sum of Rs.5000 at the rate of 10% per annum is Rs.1050, then time period is (Interest compounded yearly):

A1 Years

B21/2 Years

C3 Years

D2 Years

Explanation:

C.I of 5000 at 10% interest for x years is 6050 = Rs. 1050
6050 = 5000 ( 1 + 10/100)^n => 6050/5000 = (11/10)^n
=> 605/500 = (11/10)^n => n = 2 years.

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At what rate of interest (compounded yearly)will Rs. 10,000 amount to Rs. 12,100 in 2 years?

A9%

B11%

C8%

D10%

Explanation:

Amount = P(1 + R/100)^n
Where Principal = P, Rate = R% per annum, Time = n years.
12100 = 10000 (1+R/100)^2
=> 121/100 = (1+R/100)^2
=> 11/10 = (1+R/100)=> 11/10 = (100 + R)/100
=> 110 = 100 + R => R = 10%

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Compound interest of Rs.3000 at 10% per annum for 1 1/2 years will be (interest compounded half yearly).

ARs.473

BRs.374

CRs.495

DRs.347

ENone of these

Explanation:

10% interest per annum will be 5% interest half yearly for 3 terms( 1 1/2 years)
So compound interest = 3000[1+(5/100)]^3 - 3000
= 3000[(21/20)^3 -1]
= 3000(9261-8000)/8000
= 3*1261/8
= 472.8 ~ 473

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What is the difference between compound interest on Rs.3000 for 2 years at 5% P.a. When interest is compounded yearly and compound interest on the same sum and same terms except that it is compounded half yearly?

ARs.3.93

BRs.30

CRs.15.3

DRs.41.28

E1

Explanation:

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Analyzing the good returns that Halocircle Insurance Pvt Ltd was giving, Ratika bought a 1-year, Rs 10,000 certificate of deposit that paid interest at an annual rate of 8% compounded semi-annually.What was the total amount of interest paid on this certificate at maturity?

A716

B816

C886

DNone of these

Explanation:

In the case of semi annual compounding, Interest rate becomes half and Number of periods becomes 2 per year.

So A = P(1+R100)^n
A=10,000(1+4100)^2 = 10000 * 2625 = 10816
Interest = (A-P) = (10816 - 10000) = 816

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