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# Compound Interest Questions

Home > Quantitative Aptitude > Compound Interest > General Questions
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Compound interest of Rs.3000 at 10% per annum for 1 1/2 years will be (interest compounded half yearly).

ARs.473

BRs.374

CRs.495

DRs.347

ENone of these

Explanation:

10% interest per annum will be 5% interest half yearly for 3 terms( 1 1/2 years)
So compound interest = 3000[1+(5/100)]^3 - 3000
= 3000[(21/20)^3 -1]
= 3000(9261-8000)/8000
= 3*1261/8
= 472.8 ~ 473

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The amount of principal Rs.4000 at compound interest at the ratio of 10% p.a. for 3 years is:

ARs. 4325

BRs. 5324

CRs. 3425

DRs. 5342

Explanation:

P= Rs. 4000, R= 10, Y= 3 years.
so, 1st intrest (4000 + 400) = Rs. 4400
2nd (4400 + 440) = Rs. 4840
3rd year (4840 + 484) = Rs. 5324

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What is the difference between compound interest on Rs.3000 for 2 years at 5% P.a. When interest is compounded yearly and compound interest on the same sum and same terms except that it is compounded half yearly?

ARs.3.93

BRs.30

CRs.15.3

DRs.41.28

E1

Explanation:

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The compound interest on a certain sum for 2 years at 10% per annum is Rs. 525. The simple interest on the same sum for double the time at half the rate percent per annum is:

A400

B500

C600

D800

Explanation:

Lets assume the sum = Rs. P.
Then, P(1 + 10/100)*(1 + 10/100) - P = 525
P [ (11/10)*(11/10) - 1] = 525
P = (525 x 100)/21 = 2500.
Sum = Rs . 2500.
So, S.I. = Rs. (2500 x 5 x 4)/100 = Rs. 500

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A sum of money triples itself at compound interest in 3 years. In 9 years it will be

A6 times the principal

B12 times the principal

C18 times the prinipal

D27 times the principal

Explanation:

p(1+ r/100) ^n=ci
p(1+r/100) ^ 3=3p
(1+r/100) ^3=3 , p(1+r/100) ^9=p(3)^3 = 27 times

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Analyzing the good returns that Halocircle Insurance Pvt Ltd was giving, Ratika bought a 1-year, Rs 10,000 certificate of deposit that paid interest at an annual rate of 8% compounded semi-annually.What was the total amount of interest paid on this certificate at maturity?

A716

B816

C886

DNone of these

Explanation:

In the case of semi annual compounding, Interest rate becomes half and Number of periods becomes 2 per year.

So A = P(1+R100)^n
A=10,000(1+4100)^2 = 10000 * 2625 = 10816
Interest = (A-P) = (10816 - 10000) = 816

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