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# Chain Rule Questions

Home > Quantitative Aptitude > Chain Rule > General Questions
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2 oranges, 3 bananas and 4 apples cost Rs.15. 3 oranges 2 bananas 1 apple costs Rs.10. what is the cost of 3 oranges, 3 bananas and 3 apples?

A30

B15

C10

D20

Explanation:

Lets assume orange, banana and apple cost is x, y and z respectively.
So, 2 orange + 3 banana + 4 apple =(2x+ 3y + 4z) = 15 -------- (1)
and 3 orange + 2 banana + 1 apple) = (3x+2y+z) = 10 ---------(2)

so from eq. (1) and (2)
5 (orange + banana + apple ) = 25
=> (orange + banana + apple ) = 5
so 3 orange + 3 banana + 3 apple = 3 * 5 = Rs. 15

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A college starts from 10 AM continues till 1:30 PM. In this duration there are five periods. If 5 minutes are provided before each period to leave the room and enter the other, then what is the duration of each period?

A38 min

B41 min

C40 min

D42 min

Explanation:

four 5 minutes breaks are needed so 4*5=20min
total duration is 210 minutes
duration left : 210-20 = 190
duration of each period: 190/5 = 38 min.

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A man walking at 3/4th of the speed, reaches his office late by 2 hours. What is the usual time?

A5 hours

B3 hours

C6 hours

D12 hours

Explanation:

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3 men and 8 women complete a task in same time as 6 men and 2 women do. How much fraction of work will be finished in same time if 4 men and 5 women will do that task.

A6/ 13

B7/11

C13/14

D11/12

Explanation:

3M + 8W = 6M + 2W ---------(1)
solving this we get
M = 2W
Therefore 3M + 8W = 14W
4M + 5W =13W
=>fraction of work is 13/14

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A bread making machine can be make bread of 50 kg dough in 3 minutes. How many such machines are required to make breads of 300kg dough in 6 minutes

A6

B3

C4

D5

Explanation:

Lets assume x machine required to make breads of 300 kg dough in 6 min.

Note: (u) means up arrow and (d) means down arrow.

-------------------------------
1(d) 50 kg. (d) 3 min. (u)
x 300 kg. 6 min.

=> x/1 = 300/50 * 3/6
=> x = 3 Machine

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2 computer each produces 4800 utility bills in a day. First computer bills at a rate of 9600 per hour while other at the rate of 7800 per hour. When first computer finished its run, how many bills did the other computer still have to print?

A200

B1000

C900

D850

Explanation:

First computer take 30 minit to print 4800 bills than stop working thus second computer will print for 30 minit.
Hence second computer print per minit= 7800/60 = 130 (in one min)
Hence in 30 minit 130*30 = 3900
Remain to print 4800-3900 = 900

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