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# Chain Rule Questions

Home > Quantitative Aptitude > Chain Rule > General Questions
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If 18 binders bind 900 books in 10 days, How many binders will be required to bind 660 books in 12 days?

A22

B14

C13

D11

Explanation:

Lets assume x binders required to bind 660 books.

Note: (u) means up arrow and (d) means down arrow.

binders books days
--------------------------
18(d) 900(d) 10 (u)
x 660 12

=> (660/900 * 10/12) = x/18
=> x = (660/900 * 10/12) * 18
=> x = 11 binders.

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If a quarter Kg of potato costs 60 paisa, How many paisa will 200 gm cost?

A48 paisa

B54 paisa

C56 paisa

D72 paisa

Explanation:

Lets assume x paisa for 200 gm.

Note: (u) means up arrow and (d) means down arrow.

gms paisa
------------------
250(d) 60 (d)
200 x

=> 200/250 = x/60
=> x = 200/250 * 60
=> x = 48 paisa.

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If 8 men can reap 80 hectares in 24 days , then how many hectares can 36 men reap in 30 days?

A350

B400

C425

D450

Explanation:

Lets assume x hectares can reap in 30 days.

Note: (u) means up arrow and (d) means down arrow.

men hectares days
----------------------------
8(d) 80 24(d)
36 x 30

(36/8 * 30/24) = x/80
=> x = 36/8 * 30/24 * 80
=> x = 450.

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If the cost of x meters of wire is d rupees, then what is the cost of y meters of wire at the same rate?

ARs. (xy/d)

BRs. (xd)

CRs. (yd)

DRs. (yd/x)

Explanation:

Cost of x meters = Rs.d.

Cost of 1 meter=Rs.(d/x)

Cost of y meter=Rs.[(d/x)*y]=Rs.(yd/x)

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In a camp, there is a meal for 120 men or 200 children. If 150 children have taken the meal, how many men will be catered to with remaining meal?

A50

B40

C30

D20

Explanation:

Lets assume x men required.

Note: (u) means up arrow and (d) means down arrow.

Remaining meal is to be created to 50 children.

children men
----------------------------
200(d) 120(d)
50 x

50/200 = x/120
=> x = (50*120)/200
=> x = 30 men.

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An industrial loom weaves 0.128 meters of cloth every second. Approximately, how many seconds will it take for the loom to weave 25 meter of cloth?

A194 seconds

B195 seconds

C196 seconds

D197seconds

Explanation:

Lets assume x sec. required to weave 25 meters.

Note: (u) means up arrow and (d) means down arrow.

meters(cloths) sec(time)
----------------------------
0.128(d) 1(d)
25 x

25/0.128 = x/1
=> x = 25000/128
=> x = 195.31 sec.
So approx time will be required = 195.

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If the Price of 6 toys is Rs. 264.37, What will be the approximate price of 5 toys?

ARs.120

BRs.100

CRs.200

DRs.220

Explanation:

Lets assume Rs. x is price for 5 toys.

Note: (u) means up arrow and (d) means down arrow.

Toys Price
----------------
6(d) 264.37(d)
5 x

5/6 = x/264.37
=> x = (5*264.37)/6

=>x=220.308
=>x=~220

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If 12 box containers require 18 feet of wall space, how many feet of wall space will 30 box containers require?

A45

B25

C47

D28

Explanation:

Lets assume 30 box containers require x feet wall.

Note: (u) means up arrow and (d) means down arrow.

container require space
-----------------------------
12 (d) 18 (d)
30 x

30/12 = x/18
=> x = 30/12 * 18
=> x = 45 feet.

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If 20 men can build a wall 56m long in 6 days, what length of a similar wall can be built by 35 men in 3 days?

ALength=50m.

BLength=39m.

CLength=49m.

DLength=59m.

Explanation:

More men, more length built (Direct).
Less days, less length built (Direct).
Men 20:35 :: 56: x
Similarly, days 6:3 :: 56: x.
Therefore, 20*6*x= 35*3*56 or x= 49.
Hence, the required length= 49m.

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If 9 engines consume 24 metric tonnes of coal, when each is working 8 hours a day; how much coal will be required for 8 engines, each running 13 hours a day, it being given that 3 engines of the former type consume as much as 4 engines of latter type.

A36 metric tonnes.

B22 metric tonnes.

C32 metric tonnes.

D26 metric tonnes.

Explanation:

Less engines, less coal consumed (direct)
More working hours, more coal consumed (direct)
If 3 engines of former type consume 1 unit, then 1 engine will consume 1/3 unit.
If 4 engines of latter type consume 1 unit, then 1 engine will consume 1/4 unit.
Less rate of consumption, less coal consumed (direct).
Therefore, number of engines 9:8 :: 24:x
Working hours 8:13 :: 24:x
Rate of consumption 1/3:1/4 :: 24:x.
9*8*1/3*x= 8*13*1/4*24 or x= 26.
So, required consumption of coal 26 metric tonnes.

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